AS & A Level Physics · Area 2 · A Level Content

Oscillations

An oscillation is a repeated back-and-forth motion about an equilibrium position, and it is simple harmonic when the acceleration is proportional to the displacement and directed towards that point. This topic covers the terms and equations of simple harmonic motion, its graphs, the interchange of kinetic and potential energy, damping, and resonance in forced oscillations.

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Syllabus coverage

  • Understand and use the terms displacement, amplitude, period, frequency, angular frequency and phase difference in the context of oscillations, and express the period in terms of both frequency and angular frequency
  • Understand that simple harmonic motion occurs when acceleration is proportional to displacement from a fixed point and in the opposite direction
  • Use a = -omega^2 x and recall and use, as a solution to this equation, x = x0 sin omega t
  • Use the equations v = v0 cos omega t and v = +/- omega sqrt(x0^2 - x^2)
  • Analyse and interpret graphical representations of the variations of displacement, velocity and acceleration for simple harmonic motion
  • Describe the interchange between kinetic and potential energy during simple harmonic motion
  • Recall and use E = 1/2 m omega^2 x0^2 for the total energy of a system undergoing simple harmonic motion
  • Understand that a resistive force acting on an oscillating system causes damping
  • Understand and use the terms light, critical and heavy damping, and sketch displacement-time graphs illustrating these types of damping
  • Understand that resonance involves a maximum amplitude of oscillations and that this occurs when an oscillating system is forced to oscillate at its natural frequency

Part of the AS & A Level Physics syllabus 9702.

Displacement, velocity and acceleration in simple harmonic motionThe three graphs are plotted against the same time axis with the axes lined up, so thephase differences can be read straight off. Velocity is a quarter of a cycle ahead ofdisplacement, and acceleration is in antiphase with displacement.x / m+A-Ax = A cos(omega t)displacement starts at +Av / m s-1+A omega-A omegav = -A omega sin(omega t)v is zero when x is maximumv is 90 degrees (pi/2) ahead of xa / m s-2+A omega^2-A omega^2a = -A omega^2 cos(omega t)a is in antiphase with x,so a = -(2 pi f)^2 x0T/4T/23T/4Ttime tone full cycleSimple harmonic motion: the acceleration is proportional to the displacementfrom the equilibrium position and is always directed towards it,so a = -(2 pi f)^2 x. The period is independent of the amplitude.Isochronous: different amplitudes give the same periodamp A1amp A2
The variation with time of displacement, velocity and acceleration for a simple harmonic oscillator: the three curves have exactly the same period, the velocity is a quarter of a cycle ahead of the displacement, and the acceleration is half a cycle out of phase with the displacement, being proportional to the negative of it.

The six words that describe an oscillation

An oscillation is a repeated back-and-forth motion about an equilibrium position. A pendulum bob, a mass hanging on a spring, a guitar string, a quartz crystal in a watch and the ions in a crystal lattice all oscillate. Each of them has a position where it would rest if it were left alone, and the whole motion is a repeating departure from and return to that position.

Displacement x is the distance of the oscillating object from the equilibrium position, measured in a stated direction. Because direction matters, displacement is positive on one side of the equilibrium position and negative on the other, and it is measured in metres. Amplitude x0 is the maximum magnitude of that displacement, so it is always positive and is measured from the equilibrium position out to an extreme, never from one extreme to the other: the peak-to-peak distance is twice the amplitude.

Period T is the time taken for one complete oscillation, that is the time for the object to return to the same position moving in the same direction. Frequency f is the number of complete oscillations each second, so f = 1 / T, measured in hertz (Hz), where 1 Hz is one oscillation per second. A 2.5 Hz oscillation repeats 2.5 times each second and has a period of 1 / 2.5 = 0.40 s.

Angular frequency omega is the same idea in radians: it is the phase change per second, omega = 2 pi f = 2 pi / T, measured in radians per second (rad s-1). One complete cycle is 2 pi radians, so an oscillation of frequency f completes 2 pi f radians of phase every second. This gives the two forms of the period, T = 1 / f and T = 2 pi / omega, and both are quoted in the syllabus. Phase difference describes how far one oscillation leads or lags another at the same instant, as a fraction of a cycle: measured in degrees or radians, a quarter of a cycle is 90 degrees (half pi radians) and half a cycle is 180 degrees (pi radians).

QuantityMeaningUnitRelation
Displacement xDistance from the equilibrium position in a stated directionmPositive on one side, negative on the other
Amplitude x0Maximum magnitude of the displacementmMeasured from the equilibrium position to an extreme
Period TTime for one complete oscillationsT = 1 / f = 2 pi / omega
Frequency fNumber of complete oscillations per secondHzf = 1 / T
Angular frequency omegaPhase change per second, 2 pi radians per cyclerad s-1omega = 2 pi f = 2 pi / T
Phase differenceHow far one oscillation leads or lags anotherdegrees or radians360 degrees = 2 pi radians = one complete cycle
Keep the two frequency measures apart: f is in Hz and counts cycles, omega is in rad s-1 and counts radians. They differ by a factor of 2 pi.

What makes an oscillation simple harmonic

An oscillation is simple harmonic when two conditions are both true: the acceleration is proportional to the displacement from a fixed point, and the acceleration is always directed towards that fixed point, that is in the opposite direction to the displacement. Written as an equation, a = -omega^2 x, where x is the displacement in metres, a is the acceleration in m s-2 and omega is the angular frequency in rad s-1. The constant of proportionality is omega^2, and the minus sign carries the physics: it is what makes the acceleration always point back towards the equilibrium position.

The minus sign also explains the shape of the motion. When the object is at the equilibrium position, x is zero, so the acceleration is zero and the object is travelling at its fastest. As it moves away from the centre the acceleration grows and points back, slowing it down, until at maximum displacement the speed is momentarily zero and the acceleration has its largest value, omega^2 x0, directed towards the centre. The object then accelerates back through the centre and out to the other side, where the displacement is negative and the acceleration is positive again. The repetition of this exchange is what makes the motion periodic.

This is why a mass on a spring oscillates with simple harmonic motion for any amplitude, while a pendulum is only approximately simple harmonic. For a spring, the restoring force is F = -kx by Hooke's law, so a = F / m = -(k / m) x, which has exactly the required form with omega^2 = k / m, giving omega = sqrt(k / m) and so T = 2 pi sqrt(m / k). A pendulum's restoring force is proportional to sin theta rather than to theta, so a = -g sin(theta) / L is proportional to the displacement only while the angle stays small; that is why a pendulum is treated as simple harmonic only for small oscillations, and why the small-angle approximation matters in the laboratory.

  • Simple harmonic motion: a = -omega^2 x, so the acceleration is proportional to the displacement and always directed towards the fixed point.
  • At the equilibrium position: displacement zero, acceleration zero, speed a maximum.
  • At maximum displacement: displacement x0, speed zero, acceleration omega^2 x0 towards the centre.
  • Mass on a spring: omega = sqrt(k / m) and T = 2 pi sqrt(m / k), exact at all amplitudes.
  • Simple pendulum: T = 2 pi sqrt(L / g), a good approximation only for small angles.
Both halves of the definition are needed: proportional to the displacement, and directed towards the fixed point. A description that leaves out the direction loses the mark.

The equations of simple harmonic motion

The defining equation a = -omega^2 x is a relation between the acceleration and the displacement at the same instant. Because the acceleration is the rate of change of velocity and the velocity is the rate of change of displacement, the whole motion can be built out of it. The displacement that satisfies it, starting from the equilibrium position and moving in the positive direction, is x = x0 sin omega t. You can check the solution by differentiating: the velocity is v = dx/dt = omega x0 cos omega t, which is written as v = v0 cos omega t with the maximum speed v0 = omega x0, and differentiating once more gives the acceleration a = -omega^2 x0 sin omega t = -(omega^2) x, which is the equation you started from. The solution really does satisfy the definition.

The two forms of the velocity equation are used in different situations. Use v = v0 cos omega t when you want the velocity as a function of time, and use the displacement form v = +/- omega sqrt(x0^2 - x^2) when you are told where the object is and want its speed there. The square root gives the magnitude of the speed, so you add the sign yourself from the direction of travel: positive on the way out, negative on the way back. Two limits are worth remembering and they follow straight from the equation: at x = x0 the square root is zero, so the speed is zero at the extremes, and at x = 0 the square root is x0, so the speed is omega x0 at the centre.

Which trig function describes the motion depends only on where the object is at t = 0. Starting at the equilibrium position, the displacement is x = x0 sin omega t. Starting at maximum displacement, the motion is a quarter of a cycle ahead, so the same motion is described by x = x0 cos omega t, with v = -v0 sin omega t. The choice of starting point never changes the amplitude, the period or the maximum speed, only the phase.

A worked example. A 0.40 kg mass on a spring oscillates with period 1.20 s and amplitude 4.0 cm. The angular frequency is omega = 2 pi / T = 2 x 3.14 / 1.20 = 5.23 rad s-1. The maximum speed is v0 = omega x0 = 5.23 x 0.040 = 0.21 m s-1, and the speed at a displacement of 2.0 cm is v = omega sqrt(x0^2 - x^2) = 5.23 x sqrt(0.040^2 - 0.020^2) = 5.23 x sqrt(0.0016 - 0.0004) = 5.23 x 0.0346 = 0.18 m s-1. The acceleration there is a = -omega^2 x = -27.4 x 0.020 = -0.55 m s-2, the minus sign meaning that it is directed back towards the equilibrium position, while at maximum displacement the magnitude would be 27.4 x 0.040 = 1.10 m s-2.

EquationWhat it givesValue at the centre (x = 0)Value at an extreme (x = x0)
a = -omega^2 xAcceleration at a given displacementZeroomega^2 x0, towards the centre
x = x0 sin omega tDisplacement at a time, when starting at the centreZero at t = 0 and every half periodx0 at t = T / 4
v = v0 cos omega tVelocity at a time, when starting at the centreMaximum, v0 = omega x0Zero
v = +/- omega sqrt(x0^2 - x^2)Speed at a given displacementomega x0Zero
T = 2 pi / omegaPeriod from the angular frequency--
Every equation of simple harmonic motion needs omega in rad s-1, never the frequency in Hz. convert with omega = 2 pi f before you substitute.

Displacement, velocity and acceleration graphs

The three graphs of an oscillator are all sinusoidal curves with the same period, and they differ only in amplitude and in phase. Because the velocity is the gradient of the displacement-time graph, the velocity curve is a quarter of a cycle ahead of the displacement curve: a crest of displacement happens where the displacement-time graph is momentarily flat, so the velocity is zero there, and the velocity is largest where the displacement-time graph is at its steepest, which is where it crosses the axis. The velocity curve is therefore 90 degrees (a quarter of a cycle) ahead of the displacement curve, and the speed is greatest at the equilibrium position.

The acceleration is the gradient of the velocity-time graph, and it is also given by a = -omega^2 x. Both ways of looking at it give the same answer: the acceleration-time graph is the displacement-time graph turned upside down and stretched by a factor of omega^2. So acceleration and displacement are 180 degrees out of phase (half a cycle apart), and the acceleration peaks are omega^2 x0 at the instants when the displacement peaks are x0. The three amplitudes are linked: if x = x0 sin omega t then a0 = omega^2 x0, so the acceleration amplitude is omega^2 times the displacement amplitude, and the velocity amplitude is omega times the displacement amplitude.

There is a fourth graph worth knowing, because it is the cleanest test of simple harmonic motion: acceleration plotted against displacement. Since a = -omega^2 x, this graph is a straight line through the origin with a negative gradient, and the gradient is -omega^2. A curve, or a line that does not pass through the origin, means the motion is not simple harmonic. This is exactly what a data-logging experiment with a mass on a spring and a motion sensor produces, and the period can be found from the gradient by omega = sqrt(-gradient), then T = 2 pi / omega.

GraphShapeWhere it is zeroWhere it is maximum
Displacement against timeSine curve of amplitude x0At the equilibrium positionx0 at the extremes
Velocity against timeCosine curve of amplitude omega x0At the extremesomega x0 at the equilibrium position
Acceleration against timeSine curve of amplitude omega^2 x0, 180 degrees out of phase with displacementAt the equilibrium positionomega^2 x0 at the extremes, directed towards the centre
Acceleration against displacementStraight line through the origin with gradient -omega^2At the originomega^2 x0 at x = x0
Read the graphs in order of gradient: velocity is the gradient of displacement, acceleration is the gradient of velocity, and acceleration is the negative of displacement multiplied by omega squared.
Displacement, velocity and acceleration in simple harmonic motionThe three graphs are plotted against the same time axis with the axes lined up, so thephase differences can be read straight off. Velocity is a quarter of a cycle ahead ofdisplacement, and acceleration is in antiphase with displacement.x / m+A-Ax = A cos(omega t)displacement starts at +Av / m s-1+A omega-A omegav = -A omega sin(omega t)v is zero when x is maximumv is 90 degrees (pi/2) ahead of xa / m s-2+A omega^2-A omega^2a = -A omega^2 cos(omega t)a is in antiphase with x,so a = -(2 pi f)^2 x0T/4T/23T/4Ttime tone full cycleSimple harmonic motion: the acceleration is proportional to the displacementfrom the equilibrium position and is always directed towards it,so a = -(2 pi f)^2 x. The period is independent of the amplitude.Isochronous: different amplitudes give the same periodamp A1amp A2
Displacement, velocity and acceleration plotted against time for one complete oscillation starting from the equilibrium position: the velocity curve is a quarter of a cycle ahead of the displacement curve, so the speed is greatest where the displacement is zero, and the acceleration curve is a half cycle (180 degrees) out of phase with the displacement curve, so the acceleration is greatest at the extremes of the motion.

The interchange of kinetic and potential energy

During an oscillation the restoring force is doing work on the object on the way in and the object is doing work against the restoring force on the way out, so energy is passed backwards and forwards between two stores. In a mass-spring system those stores are the kinetic energy of the moving mass and the elastic potential energy stored in the deformed spring; in a pendulum they are the kinetic energy of the bob and its gravitational potential energy. At the equilibrium position the whole of the energy is kinetic and the potential energy is zero, and at the extremes the whole of it is potential and the kinetic energy is zero because the object is momentarily at rest.

If the amplitude is steady, the forces doing work are conservative and the total energy stays constant through the cycle. The total energy is easiest to find at the equilibrium position, where all of it is kinetic: E = 1/2 m v0^2, and with v0 = omega x0 this becomes E = 1/2 m omega^2 x0^2, the syllabus expression for the total energy. Because the total energy is constant, the energy at any displacement is the sum of the two parts: kinetic energy = 1/2 m omega^2 (x0^2 - x^2) and potential energy = 1/2 m omega^2 x^2, adding to 1/2 m omega^2 x0^2, which is the same answer from every displacement.

The expression E = 1/2 m omega^2 x0^2 has two consequences you should be able to quote. First, the total energy depends on the square of the amplitude: doubling the amplitude multiplies the total energy by four, and halving the amplitude divides it by four. Second, because E = 1/2 m v0^2 as well, doubling the amplitude only doubles the maximum speed, since v0 = omega x0. A graph question usually asks for the shape of the energy curves: plotted against time, the kinetic and potential energies are squared sine curves that swap with each other, and each of them reaches its maximum twice per cycle, because the object passes through the equilibrium position twice and comes to rest at the extremes twice. That is why the energy curves repeat at twice the frequency of the displacement curve.

A worked example. A 0.20 kg mass oscillates with amplitude 5.0 cm and angular frequency 8.0 rad s-1. The total energy is E = 1/2 m omega^2 x0^2 = 0.5 x 0.20 x 8.0^2 x 0.050^2 = 0.016 J, and this is the kinetic energy at the centre. The maximum speed is v0 = omega x0 = 8.0 x 0.050 = 0.40 m s-1, and the kinetic energy at the centre calculated the other way is 0.5 x 0.20 x 0.40^2 = 0.016 J, which agrees. At a displacement of 3.0 cm the potential energy is 0.5 x 0.20 x 64 x 0.030^2 = 0.0058 J and the kinetic energy is therefore 0.016 - 0.0058 = 0.010 J.

The total energy is constant and proportional to the amplitude squared: E = 1/2 m omega^2 x0^2. The kinetic and potential energies each vary twice as fast as the displacement.

Damping: what a resistive force does to an oscillation

A resistive force such as friction, air resistance or the viscous drag of a liquid removes energy from an oscillating system and transfers it to the thermal store of the surroundings. This is damping, and its visible effect is that the amplitude of the oscillation falls as time goes on. The restoring force is unchanged, so damping does not alter the period much at all, and the oscillation continues at almost the same frequency with a steadily shrinking amplitude.

With light damping, the amplitude decreases gradually over many oscillations. The extremes lie on a smooth decaying curve, usually an exponential envelope, and after each cycle the amplitude has multiplied by the same factor; since the energy is proportional to the amplitude squared, the energy of the oscillation falls away more quickly than the amplitude does. A pendulum swinging in air and a guitar string after it is plucked are both lightly damped: they lose only a fraction of their amplitude each swing, but they do eventually stop.

With critical damping, the system is displaced and released and returns to the equilibrium position in the shortest possible time without overshooting it. There is no oscillation at all, no period, and no amplitude to measure. Critical damping is what every measuring instrument with a moving pointer needs: the needle of a moving-coil galvanometer, a set of kitchen scales, the movement of an analogue ammeter and a well-designed door closer are all damped so that the reading settles quickly without flicking past the answer and swinging back.

Heavy damping also gives a return to equilibrium with no oscillation, but it is much slower than critical damping, because the resistive force is so large that it prevents the system from building up any speed. This is the part students most often get backwards: heavy damping is slow, not fast. A pendulum in thick oil, or a door closer with too stiff a hydraulic damper, creeps back to the rest position without ever crossing it. Between the two extremes there is a whole family of damped motions: light damping still oscillates, and both critical and heavy damping stop without crossing the equilibrium position.

Type of dampingDisplacement-time graphDoes it cross the equilibrium positionExample use
Light dampingOscillates with the amplitude decaying gradually over many cyclesYes, many timesA pendulum swinging in air, a plucked guitar string
Critical dampingFalls to zero in the shortest time without overshootingNo, it approaches zero from one sideDoor closer, moving-coil galvanometer, car suspension
Heavy dampingFalls to zero without overshooting, but much more slowlyNo, it approaches zero from one sideA pendulum in thick oil, a stiff hydraulic damper
Critical damping is the fastest return to equilibrium without overshoot. Heavy damping also avoids overshoot but takes much longer.

Forced oscillations and resonance

A system that is displaced and then left alone oscillates at its natural frequency, which is fixed by its mass, its stiffness or its length. If instead a periodic driving force keeps acting on it, the system is forced to oscillate at the frequency of the driving force, whatever that frequency happens to be, and it soon settles into a steady oscillation at the driving frequency rather than at its natural frequency. Pluck a guitar string and it sounds its natural frequency; hold it against a loudspeaker and it is forced to move at the loudspeaker's frequency instead.

The amplitude of a forced oscillation depends on how the driving frequency compares with the natural frequency, and the dependence is the resonance curve. When the driving frequency is much lower than the natural frequency, the system simply follows the driving force and the amplitude stays modest; when the driving frequency is much higher, the system cannot keep up with the rapidly changing force and the amplitude is again small. The amplitude is a maximum when the driving frequency equals the natural frequency, and this is resonance: the driving force is always in step with the motion, so energy is transferred from the driving force to the system at the greatest possible rate. That energy is stored in the oscillation until the energy lost to damping each cycle equals the energy supplied, at which point the amplitude stops growing and stays at its maximum.

Damping controls how big the resonance peak is. A very lightly damped system has a sharp, narrow peak with a large maximum amplitude, because very little energy is lost each cycle and the amplitude can grow a great deal; a more heavily damped system has a lower and broader peak, and if the damping is heavy enough the peak disappears altogether. This is why resonance needs both halves of the sentence: the driving frequency must equal the natural frequency, and the size of the resulting amplitude depends on the damping. Buildings are fitted with dampers, and tuned mass dampers are fitted inside tall towers and footbridges, precisely to keep the amplitude at resonance within safe limits.

The phase of a forced oscillation also changes as the driving frequency changes, and the pattern is worth remembering. At a driving frequency well below resonance the displacement is in step with the driving force, so the system is in phase with it; at resonance the displacement lags the force by a quarter of a cycle, 90 degrees; and at driving frequencies well above resonance the displacement is half a cycle behind the force, that is 180 degrees, or in anti-phase. This phase change is used in practice: in a magnetic resonance imaging machine the radio-frequency pulses are switched on at the resonance of the hydrogen nuclei so that energy is absorbed strongly by the tissue being imaged.

Resonance is not just a large amplitude: it is a maximum amplitude, and it happens when the driving frequency equals the natural frequency. Damping lowers the peak.
Resonance and the effect of dampingA system driven at a frequency close to its own natural frequency oscillates with alarge amplitude. Damping removes energy from the oscillator, so the resonance peakbecomes lower, flatter and slightly lower in frequency.Amplitude against driving frequency0510152001.53.04.56.0amplitudeof theoscillation/ mmdriving frequency f / Hzf0 = 3.0 Hzthe natural frequencyat low frequency every curve tends to the same amplitudelight damping (Q = 10)medium damping (Q = 4)heavy damping (Q = 1.5)Two real examplesWashing machine: the drum on its springshas a natural frequency; at the matchingspin speed it shakes violently.windBridge: a periodic wind force at thebridge's natural frequency builds a largeamplitude and can destroy it (TacomaDamping removes energy from the oscillator every cycle, so the amplitude at resonance is smaller and thepeak is broader. With no damping at all the amplitude would grow without limit.Designers keep the natural frequency well away from the driving frequencies, add damping, or drive thesystem through the resonance quickly.
The amplitude of a forced oscillation plotted against driving frequency for three different amounts of damping: each curve peaks when the driving frequency equals the natural frequency, and the more heavily damped curves have a lower, broader peak than the lightly damped curve.

Oscillators and resonance in real systems

The simple pendulum is the standard laboratory oscillator, and its famous property is that the period depends only on the length: T = 2 pi sqrt(L / g), with no mass in the expression. A pendulum 1.00 m long has a period of 2 pi sqrt(1.00 / 9.81) = 2.0 s, which is why pendulum clocks used a rod of about a metre. Rearranged as g = 4 pi^2 L / T^2, the same equation turns a pendulum into a way of measuring the gravitational field strength, which is one of the standard practicals for this course. Pendulum clocks, the first of which was designed by Christiaan Huygens in 1656, keep time because the period is so nearly independent of the amplitude, and their accuracy improved enormously when the pendulum was made to swing independently of the escapement.

The quartz crystal oscillator in a wristwatch is a different kind of oscillator and a much more reliable one. A thin slice of quartz is a piezoelectric material: apply a voltage and it deforms, and deform it and it produces a voltage, so it can both drive and sense its own vibration. Cut and mounted in the right way it has an extremely stable natural frequency, and the common watch crystal is designed to vibrate at 32768 Hz, which is 2 to the power 15. Divide that frequency by two fifteen times with electronic counters and you have exactly one pulse per second to drive the hands. The natural frequency hardly depends on temperature, on the drive level or on the age of the watch, which is why a quartz watch is far better timekeeper than a mechanical one.

Resonance is used deliberately in many instruments and devices. Musical instruments work by it: a guitar or violin body has resonances that radiate the string's vibration into the air, a wind instrument's air column resonates at the frequencies that make its notes, and a tuning fork held over a tube of adjustable length will drive the air column into a loud resonance when the length is right. A tuned circuit in a radio receiver is a resonance: the inductance and capacitance are chosen so that the circuit resonates at the frequency of the one station wanted, giving the largest current at that frequency and rejecting the rest. A microwave oven heats food at 2.45 GHz, and a seismometer uses a mass on a spring whose natural frequency is far below that of the earthquakes it detects, so that it responds to ground motion rather than resonating with it.

Resonance can also be destructive, and engineers spend a great deal of effort preventing it. The Millennium Bridge across the Thames in London was opened in June 2000 and closed two days later, because pedestrians walking at about two steps per second pushed sideways on the deck at a frequency that matched the bridge's natural sideways oscillation of about 0.5 Hz, and the deck began to wobble so much that people had to hold the handrails; the problem was cured by fitting viscous dampers and tuned mass dampers before it reopened in 2002. In a similar way, a washing machine passes through a violent vibration as its spin speed rises through the speed that matches the natural frequency of the drum suspension, and every internal combustion engine is mounted on flexible, damped mountings so that the engine's vibration is not passed into the body of the car at its resonant speed.

  • Simple pendulum: T = 2 pi sqrt(L / g); the 1 m pendulum has a period of 2.0 s and is used to measure g.
  • Mass on a spring: T = 2 pi sqrt(m / k); used in seismometers, where the natural frequency is kept low.
  • Quartz watch: a crystal at 32768 Hz divided down to one pulse per second.
  • Millennium Bridge, London (2000): pedestrian-driven resonance in the sideways mode, cured by dampers.
  • Washing machine: violent vibration when the spin frequency matches the natural frequency of the drum suspension.
Resonance is either useful or dangerous depending on the damping and the amplitude: musical instruments and radio receivers want a sharp peak, bridges and machines must be damped to keep it small.

Key terms you must be able to define

Simple harmonic motion
Oscillation in which the acceleration is proportional to the displacement from a fixed point and is always directed towards that point, described by a = -omega^2 x.
Displacement
The distance of an oscillating object from its equilibrium position, measured in a stated direction, so that it is positive on one side of that position and negative on the other; measured in metres.
Amplitude
The maximum magnitude of the displacement of an oscillation, measured from the equilibrium position out to an extreme; it is always positive and is measured in metres.
Period
The time taken for one complete oscillation, that is for the object to return to the same position moving in the same direction; T = 1 / f = 2 pi / omega, measured in seconds.
Angular frequency
The phase change per second of an oscillation, omega = 2 pi f = 2 pi / T, measured in radians per second (rad s-1); it is the constant that appears in a = -omega^2 x and in v0 = omega x0.
Phase difference
The fraction of a cycle by which one oscillation leads or lags another at the same instant, measured in degrees or radians; a quarter of a cycle is 90 degrees and half a cycle is 180 degrees.
Damping
The gradual reduction in the amplitude of an oscillation caused by a resistive force such as friction or air resistance, which does work on the system and transfers its energy to the surroundings as thermal energy.
Critical damping
The damping that returns a displaced system to its equilibrium position in the shortest possible time without overshooting it; the system does not oscillate at all, and it is used for door closers, galvanometer needles and car suspension.
Resonance
The maximum amplitude of a forced oscillation, which occurs when the frequency of the driving force equals the natural frequency of the system; the size of the peak depends on the amount of damping.

Applied to the real world

Cambridge sets 9702 in unfamiliar contexts - a fairground ride, a power station, a hospital scanner, a satellite, an astronomical observatory. Use these as models for how to apply the physics, then write your own.

In the laboratory

A simple pendulum is used to measure g. A small dense bob is hung from a thin thread about a metre long and displaced by only a few degrees so that it moves almost in simple harmonic motion. The period of 20 complete oscillations is timed with a stopwatch and divided by 20, the length is measured from the suspension point to the centre of the bob, and g is found from g = 4 pi^2 L / T^2. Timing from the equilibrium position, where the bob moves fastest, reduces the reaction-time error, and repeating the measurement with different lengths and plotting T^2 against L gives a straight line through the origin whose gradient is 4 pi^2 / g.

In engineering

The Millennium Bridge in London was closed two days after it opened in June 2000 because pedestrians walking at about two steps per second drove the deck sideways at a frequency that matched the bridge's natural sideways mode of about 0.5 Hz. As people felt the deck move they adjusted their steps to it, so the driving force stayed in step with the motion, the amplitude grew, and the sway became alarming. Viscous dampers and tuned mass dampers were fitted before the bridge reopened in 2002: the dampers absorb the oscillation energy each cycle, so the same driving force produces a much smaller amplitude.

On the road

A car body sits on steel springs, and each spring is paired with a damper (the shock absorber) whose piston forces oil through small holes, converting the energy of the oscillation into thermal energy. A worn damper gives light damping, so after a bump the body keeps bouncing for several cycles and the wheels lose contact with the road, which lengthens the braking distance. The suspension is designed to be close to critically damped: the body returns to its proper height as quickly as possible without overshooting and bouncing, so the tyres stay in contact with the road.

In medicine

Magnetic resonance imaging relies on resonance. The patient is placed in a strong steady magnetic field of about 1.5 T, which makes the nuclei of hydrogen atoms in the tissue precess at a natural frequency of about 64 MHz, that is 42.6 MHz for each tesla of field. A radio-frequency pulse is applied at exactly that frequency, energy is absorbed strongly by the nuclei, and when the pulse ends the nuclei re-emit the energy as a radio signal that coils around the patient detect. The strength of the signal depends on the amount of water in the tissue, so the collected signals build up an image of the inside of the body.

In sport

A diver on a springboard rides the board's natural oscillation. The board has a natural frequency set by its length, stiffness and the mass on it, and the diver bends his knees and pushes down at the instant the board begins to rise, so the driving force is always in step with the motion and each push adds energy. The amplitude grows with every bounce and the diver is launched much higher than a single push at the wrong moment would achieve, which is exactly how a child on a swing makes it go higher by pumping at the right point in the cycle.

In astronomy

Some stars pulsate because their outer layers are driven into oscillation by variations in their opacity. Delta Cephei, the prototype of the Cepheid variables, brightens and dims with a period of 5.37 days, and the star's radius changes by several per cent during the cycle. In 1912 Henrietta Leavitt found that the period of a Cepheid is related to its luminosity, so measuring the period tells you how bright the star really is; comparing that with how bright it looks gives its distance, which makes these oscillating stars the standard candles used to measure distances to other galaxies.

Flashcards

Click a card to flip it. Mark honestly — the tracker uses this.

Q1State the two conditions that make an oscillation simple harmonic.
The acceleration is proportional to the displacement from a fixed point, and the acceleration is always directed towards that fixed point (in the opposite direction to the displacement), so a = -omega^2 x.
Q2What is the angular frequency, and how is it related to the period and the frequency?
The phase change per second, measured in rad s-1: omega = 2 pi f = 2 pi / T. It is the constant in a = -omega^2 x and in v0 = omega x0.
Q3What are the displacement, velocity and acceleration at the equilibrium position?
Displacement zero, velocity a maximum of omega x0, acceleration zero.
Q4What are the displacement, velocity and acceleration at maximum displacement?
Displacement x0, velocity zero, and acceleration a maximum of omega^2 x0 directed towards the equilibrium position.
Q5What is the phase relationship between displacement and acceleration in simple harmonic motion?
They are 180 degrees (half a cycle) out of phase, because a = -omega^2 x: the acceleration is the largest and is directed back towards the centre exactly when the displacement is the largest.
Q6Write the equation for the speed at a given displacement, and say what the sign means.
v = +/- omega sqrt(x0^2 - x^2). The square root gives the magnitude of the speed; the sign is chosen from the direction the object is moving, positive one way and negative the other.
Q7For an oscillation starting at the equilibrium position, write the displacement and velocity as functions of time.
x = x0 sin omega t and v = v0 cos omega t with v0 = omega x0. If the oscillation starts at maximum displacement, x = x0 cos omega t and v = -v0 sin omega t instead.
Q8Where in the cycle are the kinetic energy and the potential energy a maximum?
Kinetic energy is a maximum at the equilibrium position, where the speed is greatest, and potential energy is a maximum at the extremes of the motion, where the object is momentarily at rest. Each of them reaches its maximum twice in every cycle.
Q9Write the expression for the total energy of a simple harmonic oscillator, and say how it depends on the amplitude.
E = 1/2 m omega^2 x0^2. It is proportional to the square of the amplitude, so doubling the amplitude multiplies the total energy by four.
Q10What causes damping, and how does damping affect the period?
A resistive force such as friction, air resistance or viscous drag does work on the system and transfers energy to the surroundings as thermal energy, so the amplitude falls. The restoring force is unchanged, so the period is almost unaffected.
Q11Describe the displacement-time graph for a critically damped system.
The displacement falls smoothly to zero in the shortest possible time without the system overshooting the equilibrium position. The system does not oscillate, so there is no period and no amplitude to read off.
Q12How does heavy damping differ from critical damping?
Both return the system to equilibrium without overshooting, but heavy damping is much slower because the very large resistive force prevents the system from building up any speed. Critical damping is the fastest return without overshoot.
Q13What is resonance?
The maximum amplitude of a forced oscillation, which occurs when the frequency of the driving force equals the natural frequency of the system, so that the energy transferred from the driving force to the system each cycle is a maximum.
Q14How does increasing the damping affect the resonance curve?
It lowers and broadens the peak. A lightly damped system has a tall, sharp peak, and heavy damping can remove the peak altogether, which is why dampers are fitted to bridges and tall buildings.
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Exam-style questions

8 questions, 27 marks. Write your answer, then reveal the mark scheme and tick each point you actually made. Answering honestly here is what makes the rest of the site useful.

StateAO11 mark
State what is meant by simple harmonic motion.

Mark scheme — tick each point you actually made

Examiner tip: One mark, so write the complete definition in one sentence and keep the minus sign. 'Acceleration proportional to displacement' on its own is not enough, because the direction is half of the definition.
DefineAO12 marks
Define the angular frequency of an oscillation and state its unit.

Mark scheme — tick each point you actually made

Examiner tip: Do not give the unit as Hz. The angular frequency counts radians rather than cycles, so it is larger than the frequency by a factor of 2 pi and is measured in rad s-1.
CalculateAO24 marks
The displacement-time graph of a 0.20 kg mass oscillating on a spring is a sine curve of amplitude 3.0 cm and period 0.80 s. (a) Calculate the frequency of the oscillation. (b) Calculate the angular frequency of the oscillation. (c) Calculate the magnitude of the acceleration of the mass at maximum displacement.

Mark scheme — tick each point you actually made

Examiner tip: Convert the amplitude to metres before substituting, and use omega, not f, in a = omega^2 x0. Always give the unit: a bare 1.85 scores at most the method mark.
ExplainAO23 marks
A pendulum bob oscillates with simple harmonic motion between two extreme positions, passing through its lowest point. Explain how the velocity and the acceleration of the bob vary during one complete oscillation, and state the phase relationship between the displacement and the acceleration.

Mark scheme — tick each point you actually made

Examiner tip: Say what happens at both places, the extremes and the equilibrium position, and give the phase relationship as a number in degrees or radians. Describing only one end of the motion cannot score full marks.
CalculateAO24 marks
A 0.25 kg mass on a spring oscillates with amplitude 4.0 cm and period 0.50 s. (a) Calculate the angular frequency of the oscillation. (b) Calculate the maximum speed of the mass. (c) Calculate the total energy of the oscillation.

Mark scheme — tick each point you actually made

Examiner tip: The maximum speed is omega x0, not omega x0 squared, and it occurs at the equilibrium position rather than at the extremes. In part (c) the energy depends on the square of the amplitude, so 4.0 cm must go in as 0.040 m.
DescribeAO24 marks
Describe the shape of the displacement-time graph for an oscillating system that is (a) lightly damped, (b) critically damped and (c) heavily damped, and state the feature that distinguishes (b) and (c) from (a).

Mark scheme — tick each point you actually made

Examiner tip: Label both axes on any sketch and draw the light curve so that its extremes lie on a smooth decaying envelope. For (b) and (c) the curve must approach the equilibrium line from one side only and must never cross it.
ExplainAO25 marks
A washing machine drum spins at a steadily increasing speed, and the machine vibrates violently when the drum passes one particular speed. Explain what is meant by resonance and use your explanation to account for the violent vibration. State one change that would reduce the vibration.

Mark scheme — tick each point you actually made

Examiner tip: Name both frequencies and say they are equal: the driving frequency and the natural frequency. The mark for the fix is for linking extra damping to a lower resonance peak, not just for writing 'add damping'.
DescribeAO34 marks
A student uses a simple pendulum to determine the gravitational field strength g. Describe the measurements that should be taken and explain how g is obtained from them. Include one precaution that improves the accuracy of the result.

Mark scheme — tick each point you actually made

Examiner tip: Twenty oscillations, not one: dividing the total time by 20 divides the reaction-time error by 20 as well. The length is measured to the centre of the bob, and the amplitude must be small because the pendulum is only approximately simple harmonic.

Exam technique for this topic

  • Quote both halves of the simple harmonic motion definition: the acceleration is proportional to the displacement from a fixed point, and it is directed towards that point. Candidates who leave out the direction, or who write that the acceleration is proportional to the displacement without a minus sign in a = -omega^2 x, lose the mark.
  • Use the angular frequency in every equation: a = -omega^2 x, v = v0 cos omega t, v0 = omega x0 and E = 1/2 m omega^2 x0^2 all need omega = 2 pi f measured in rad s-1. Substituting the frequency in Hz is one of the commonest errors at this level and every later mark in the question depends on it.
  • Check where the oscillation starts before choosing between x = x0 sin omega t and x = x0 cos omega t. Use sin when the object starts at the equilibrium position and cos when it starts at maximum displacement, and remember that v = +/- omega sqrt(x0^2 - x^2) gives only the speed, so you must add the sign from the direction of travel.
  • Give graph answers three things: the shape (sine or cosine), the amplitude (x0, omega x0 or omega^2 x0) and the phase relationship (90 degrees between displacement and velocity, 180 degrees between displacement and acceleration). Sketch damping curves as smooth decaying envelopes on labelled axes, and remember that critically and heavily damped curves must not cross the time axis at all.
  • For energy questions, state that the total energy is constant and equal to 1/2 m omega^2 x0^2, that it is proportional to the square of the amplitude, and that the kinetic and potential energies each reach a maximum twice per cycle. A question that gives you the amplitude and asks for the energy wants the amplitude in metres and the angular frequency in rad s-1, not the frequency in Hz.
  • In a resonance question, name both frequencies and say that they are equal: the driving frequency equals the natural frequency of the system, so the energy transferred per cycle is a maximum and the amplitude is a maximum. Then say what damping does, which is to lower and broaden the peak, and quote a real case such as the Millennium Bridge swaying under the steps of pedestrians.

Why students lose marks here

A student wroteA student wrote: 'At the point of maximum displacement the velocity and the acceleration of the mass are both zero, because the mass is momentarily at rest.'
Why it loses marksOnly the velocity is zero at the extremes. The acceleration there is as large as it ever gets, because a = -omega^2 x and the displacement magnitude is at its maximum.
The answer that scoresAt maximum displacement x = x0, so the speed is zero but the acceleration has magnitude omega^2 x0 and is directed towards the equilibrium position. The two quantities are out of step: the acceleration is zero where the speed is greatest, which is at the equilibrium position, and the speed is zero where the acceleration is greatest, which is at the extremes.
Displacement, velocity and acceleration in simple harmonic motionThe three graphs are plotted against the same time axis with the axes lined up, so thephase differences can be read straight off. Velocity is a quarter of a cycle ahead ofdisplacement, and acceleration is in antiphase with displacement.x / m+A-Ax = A cos(omega t)displacement starts at +Av / m s-1+A omega-A omegav = -A omega sin(omega t)v is zero when x is maximumv is 90 degrees (pi/2) ahead of xa / m s-2+A omega^2-A omega^2a = -A omega^2 cos(omega t)a is in antiphase with x,so a = -(2 pi f)^2 x0T/4T/23T/4Ttime tone full cycleSimple harmonic motion: the acceleration is proportional to the displacementfrom the equilibrium position and is always directed towards it,so a = -(2 pi f)^2 x. The period is independent of the amplitude.Isochronous: different amplitudes give the same periodamp A1amp A2
Displacement, velocity and acceleration against time for one oscillation: the velocity curve peaks where the displacement curve crosses zero, and the acceleration curve peaks where the displacement curve peaks, because acceleration is proportional to the negative of displacement.
A student wroteA student wrote: 'An oscillator has a frequency of 4.0 Hz, so its acceleration is a = -(4.0)^2 x.'
Why it loses marksThe equation a = -omega^2 x needs the angular frequency, not the frequency. The two differ by a factor of 2 pi, so omega is always greater than f and the acceleration comes out far too small if f is used.
The answer that scoresConvert first: omega = 2 pi f = 2 x 3.14 x 4.0 = 25 rad s-1. Then a = -omega^2 x = -(25)^2 x = -625 x, with x in metres and a in m s-2. The maximum speed comes out of the same constant, v0 = omega x0 = 25 x0, and the total energy is E = 1/2 m omega^2 x0^2 = 1/2 m x 625 x x0^2.
A student wroteA student wrote: 'Doubling the amplitude of an oscillation doubles the total energy, because the energy is proportional to the amplitude.'
Why it loses marksThe total energy is proportional to the amplitude squared, E = 1/2 m omega^2 x0^2, not to the amplitude. Doubling the amplitude multiplies the total energy by four, because 2 squared is 4.
The answer that scoresE = 1/2 m omega^2 x0^2, so doubling x0 multiplies the energy by 2^2 = 4. What does double is the maximum speed, v0 = omega x0, because the energy depends on the square of the speed as well as on the square of the amplitude: E = 1/2 m v0^2 = 1/2 m (omega x0)^2, which is the same expression.
A student wroteA student wrote: 'A heavily damped system returns to its equilibrium position more quickly than a critically damped one, because the damping force is larger.'
Why it loses marksThe damping force opposes the motion, so a very large one slows the return down. It is critical damping, not heavy damping, that gives the fastest return to equilibrium without overshoot.
The answer that scoresCritical damping returns the system to equilibrium in the shortest time without it crossing the equilibrium position, and it is used for door closers, the needle of a moving-coil galvanometer and car suspension. Heavy damping also avoids overshoot, but the very large resistive force prevents the system from building up speed, so the return to equilibrium is much slower. Light damping is the only one of the three that still oscillates, with the amplitude decaying gradually.

Where this fits in AS & A Level Physics

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