AS & A Level Physics · Area 1 · AS Level Content

Physical Quantities and Units

Every physical quantity is a numerical magnitude together with a unit, and every measurement carries an uncertainty. This topic covers the SI base quantities and their units, derived units and prefixes, checking equations by the units on each side, random and systematic errors, precision against accuracy, combining uncertainties, and adding, subtracting and resolving vectors.

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Syllabus coverage

  • Understand that all physical quantities consist of a numerical magnitude and a unit, and make reasonable estimates of physical quantities included within the syllabus
  • Recall the following SI base quantities and their units: mass (kg), length (m), time (s), current (A) and temperature (K)
  • Express derived units as products or quotients of the SI base units and use the derived units for quantities listed in this syllabus as appropriate
  • Use SI base units to check the homogeneity of physical equations
  • Recall and use the following prefixes and their symbols to indicate decimal submultiples or multiples of both base and derived units: pico (p), nano (n), micro (mu), milli (m), centi (c), deci (d), kilo (k), mega (M), giga (G) and tera (T)
  • Understand and explain the effects of systematic errors (including zero errors) and random errors in measurements
  • Understand the distinction between precision and accuracy
  • Assess the uncertainty in a derived quantity by simple addition of absolute or percentage uncertainties
  • Understand the difference between scalar and vector quantities and give examples of scalar and vector quantities included in the syllabus, and add and subtract coplanar vectors
  • Represent a vector as two perpendicular components

Part of the AS & A Level Physics syllabus 9702.

The seven SI base quantities and the decimal prefixesEvery other unit in physics is built from these seven by multiplying and dividing.Base quantitysymbol, name and unit, exactly as the syllabus writes themquantitysymbolunitunit symbollengthlmetremmassmkilogramkgtimetsecondselectric currentIampereAthermodynamic temperatureTkelvinKamount of substancenmolemolluminous intensityIvcandelacda derived unit is a product of base units: for examplethe newton is 1 kg m s-2 and the pascal is 1 kg m-1 s-2Prefixesthe prefix multiplies the unit that follows itprefixsymbolfactorteraT10^12gigaG10^9megaM10^6kilok10^3millim10-3micromu10-6nanon10-9picop10-121 km = 10^3 m and 1 mm = 10-3 m, so 1 km= 10^6 mm. Prefixes are powers of ten only.Watch the symbols: kg is a base unit, but m is both the metre and the milli prefix,and T is both the tesla and the tera prefix. Read the context, then convert.
A labelled summary of the five SI base quantities with their units, the decimal prefixes from pico to tera with their factors, and how a derived unit such as the newton is built from the base units.

A physical quantity is a magnitude and a unit

Every physical quantity is written as a numerical magnitude together with a unit. A length is not 2.4; it is 2.4 m, where 2.4 tells you how many and m tells you how much of one. A number on its own means nothing in physics: 2.4 could be a length, a mass or a current, and only the unit distinguishes them. Changing the unit changes the number, never the quantity itself: the same length is 2.4 m, 240 cm or 2.4 x 10^3 mm.

Carrying units through a calculation is the cheapest check you have. If you want a speed from a distance of 1500 m and a time of 300 s, then 1500 m / 300 s = 5.0 m s-1, and the unit of the answer confirms that you divided rather than multiplied. If the unit of your answer is not the unit of the quantity you were asked for, the calculation is wrong whatever the arithmetic says.

You are also expected to estimate quantities sensibly, to the nearest power of ten or so. An estimate is never quoted to three significant figures: the mass of an adult is about 70 kg, not 69.3 kg, and the height of Mount Everest is about 1 x 10^4 m. Learn the anchor values in the table below; they are the ones a question is most likely to ask you to judge.

QuantityReasonable estimate
Mass of an adult70 kg
Mass of a paperclip1 x 10-3 kg (1 g)
Thickness of a sheet of paper1 x 10-4 m (0.1 mm)
Diameter of an atom1 x 10-10 m
Time for one heartbeat1 s
Current in a 60 W lamp on 240 V mains0.25 A
Temperature of a room300 K (about 27 degrees C)
Speed of sound in air330 m s-1
Atmospheric pressure1.0 x 10^5 Pa
Speed of light in a vacuum3.0 x 10^8 m s-1
A quantity with no unit is not a physical quantity. Write the unit on every answer, including estimates and every step of a calculation.

SI base quantities, derived units and prefixes

The syllabus uses five SI base quantities, each with its own SI base unit: mass (kg), length (m), time (s), electric current (A) and thermodynamic temperature (K). Base units are the ones that are defined directly, so they are not written in terms of anything else. Note that the base unit of mass is the kilogram, not the gram: the kilo is already built into the name, so there is no such thing as a base unit of 'gram' and you must not treat the kg as 10^3 of some larger unit.

Every other unit is a derived unit, written as a product or quotient of base units. You get there by taking the defining equation of the quantity and replacing each symbol with its unit. Force is defined by F = m a, so 1 N = 1 kg x 1 m s-2 = 1 kg m s-2. Work is defined by W = F s, so 1 J = 1 N m = 1 kg m2 s-2. Learn to do this from the equation rather than memorising the list, because a question can ask you for any quantity in the syllabus.

Prefixes save you from writing long strings of powers of ten. Each prefix is a fixed factor, and it works with base units and derived units alike: 2.4 kN is 2.4 x 10^3 N, 470 microA is 470 x 10-6 A = 4.7 x 10-4 A, and 3.2 GJ is 3.2 x 10^9 J.

The safe routine is always to convert to base units before substituting into an equation. Then every intermediate value is in base units, the answer comes out in base units, and the only decision left is which prefix to use when you write the final value. Watch the kilo in kg: a density is in kg m-3, so convert grams to kilograms and centimetres to metres before you divide.

  • pico (p): x 10-12, nano (n): x 10-9, micro (mu): x 10-6
  • milli (m): x 10-3, centi (c): x 10-2, deci (d): x 10-1
  • kilo (k): x 10^3, mega (M): x 10^6, giga (G): x 10^9, tera (T): x 10^12
QuantityUnitIn SI base units
Forcenewton (N)kg m s-2
Energy or work donejoule (J)kg m2 s-2
Powerwatt (W)kg m2 s-3
Pressure or stresspascal (Pa)kg m-1 s-2
Electric chargecoulomb (C)A s
Potential differencevolt (V)kg m2 s-3 A-1
Resistanceohmkg m2 s-3 A-2
Frequencyhertz (Hz)s-1
Build any derived unit from the defining equation: replace each symbol by its unit and simplify. Force gives kg m s-2, and everything else follows.

Checking an equation with base units: homogeneity

An equation is homogeneous when both sides reduce to the same base units. This must be true of every correct physical equation, because you cannot add metres to seconds in the same way that you cannot add apples to volts. So the check is quick and decisive: write the base units of the quantity on the left, do the same for the expression on the right, and compare.

Take the constant-acceleration equation v2 = u2 + 2 a s. On the left, v is a velocity, so v2 has units (m s-1)2 = m2 s-2. On the right, u2 also has units m2 s-2. The term 2 a s has units (m s-2) x m = m2 s-2, and the '2' is a pure number with no unit, so it does not affect the comparison. Both sides are m2 s-2, so the equation is homogeneous.

Now try a wrong equation: a student writes s = u t + a t. The term u t has units (m s-1) x s = m, which matches the metre on the left. But a t has units (m s-2) x s = m s-1, so the second term is a velocity and cannot be added to a displacement. The equation is not homogeneous, and that alone proves it is wrong; the correct version is s = u t + 0.5 a t2.

Homogeneity is necessary but not sufficient. The equations s = a t2 and s = 0.5 a t2 are both homogeneous, and only one of them is physically correct, so a units check can never confirm that a dimensionless factor such as a half or a 2 pi is right. It can only rule an equation out. Units also cannot check the argument of a trigonometric or exponential function, since those arguments are dimensionless numbers.

If the units balance the equation might be right; if they do not balance it is definitely wrong. Use the check to eliminate, never to prove.

Random errors and systematic errors

No reading is exact. The error of a measurement is the difference between the measured value and the true value, and the uncertainty is the range within which the true value is expected to lie. The starting point is the instrument's resolution, the smallest change it can detect: 1 mm on a metre rule, 0.1 mm on vernier calipers, 0.01 mm on a micrometer screw gauge, 0.01 s on a digital stopwatch. Choosing a coarser instrument immediately makes every percentage uncertainty larger.

Random errors are unpredictable. They vary in size and in sign from one reading to the next, so repeated readings are scattered about a mean. They come from reading a scale by eye, from parallax when the eye is not level with the pointer, from reaction time when a stopwatch is started and stopped, and from small changes in temperature, vibration or supply voltage. You reduce them by repeating and averaging, and by improving technique: read scales at eye level, time many oscillations instead of one, and take each reading to the finest division the instrument allows.

Systematic errors act in one direction. Every reading is shifted by the same amount, or scaled by the same factor, so the readings are consistently too large or consistently too small. A zero error is the commonest example: an instrument that does not read zero when it should. A micrometer screw gauge that reads +0.03 mm when it is closed adds 0.03 mm to every diameter; a top-pan balance that reads 0.3 g with an empty pan adds 0.3 g to every mass; a stopwatch that runs slow makes every time too small. A wrongly calibrated scale, a thermometer reading 2 degrees C high at every temperature, and a metre rule read from a worn end all do the same thing.

The two behave completely differently in the laboratory. Averaging a large number of readings cancels random errors, because the scatter falls on both sides of the mean, but it does nothing at all to a systematic error: the mean of many readings is simply the same wrong value. The only cure for a systematic error is to find it and correct it, by measuring the zero reading and subtracting it, or by calibrating the instrument against a known value. A precise set of readings that is consistently off the true value is the signature of a zero error.

Repeating and averaging removes random errors. Only finding and correcting a systematic error, such as a zero error, removes that.
Measuring length: three instruments and a worked readingChoose the instrument whose range covers the whole quantity and whose finest division is fine enough to make the reading reliable.Metre rulerange 0 to 100 cm, smallest division 1 mm0123456789101112cm85 mm = 8.5 cmLine the object up with the 0 mark, not with the end of the rule,and read with the eye directly above the mark.Resolution 1 mm, so quote a length to the nearest millimetre.Vernier caliperrange 0 to 150 mm, vernier division 0.1 mm0102030400510verniermain scale, mm8.0 mm0.7 mmReading = 8.0 + 0.7 = 8.7 mmMicrometer screw gaugerange 0 to 25 mm, resolution 0.01 mm0.02.04.06.08.0sleeve scale, mm02550thimble scale, 50 divisionstowards the object5 divisions = 0.05 mmReading = 8.50 mm (sleeve) + 0.05 mm (thimble, 0.01 mm per division)= 8.55 mm. Close the gap with the ratchet so you do not squash the wire.Uncertainty and resolutionThe uncertainty of a single reading is half the smallest division, so therule is +/- 0.5 mm but the micrometer is only +/- 0.005 mm.Worked reading, micrometervalue = main scale + thimblesleeve reads 8.50 mm and the thimble reads 5 divisions x 0.01 mm= 0.05 mm, so the diameter is 8.55 mm, quoted as 8.55 +/- 0.01 mm.The caliper reading on the left is 8.7 mm, i.e. 8.70 +/- 0.05 mm.
A metre rule, vernier calipers and a micrometer screw gauge drawn side by side with their smallest scale divisions of 1 mm, 0.1 mm and 0.01 mm, showing how the choice of instrument sets the precision of a length measurement.

Precision and accuracy are not the same thing

Precision describes how close repeated measurements are to one another, so it is a statement about the spread of your readings and about the instrument you used. A set of readings that all lie within 0.02 mm of each other is precise; a set spread over 0.12 mm is not. Accuracy describes how close a measurement is to the true value, so accuracy only has meaning when the true value is known, for example when you measure a standard mass or check a value given in the question.

The two can occur in any combination, and the combination tells you what is wrong. Precise but not accurate readings are all close together but all shifted the same way, which is the signature of a systematic error or zero error: the technique is good and the instrument is faulty. Accurate but not precise readings are scattered, but their mean is close to the true value, which is the signature of random error that has been averaged out. Neither precise nor accurate points to poor technique and a miscalibrated instrument together.

Resolution and sensitivity are separate again. The resolution of an instrument is the smallest change it can detect, and the sensitivity is the change in output per unit change in input. An instrument can be very sensitive but coarse, or coarse but perfectly calibrated. When you choose an instrument, ask two questions: is its resolution fine enough for the size of the quantity, and can I read it to that resolution? Measuring 20 mm with a metre rule gives a percentage uncertainty of about 5 per cent, whereas measuring 200 mm with the same rule gives about 0.5 per cent, so measuring a larger length or using a finer instrument is the way to improve a result.

Precision is about the spread of your readings; accuracy is about the true value. A zero error destroys accuracy while leaving precision untouched.

Assessing the uncertainty in a derived quantity

Every measurement is quoted as value +/- uncertainty, for example 60.0 +/- 0.6 g or 8.0 +/- 0.4 cm3. The absolute uncertainty has the same unit as the value; the percentage uncertainty is the absolute uncertainty divided by the value and multiplied by 100. From repeated readings the uncertainty is taken as half the range between the largest and the smallest reading, and a single reading cannot have an uncertainty smaller than half the smallest scale division.

Two rules carry you through almost every question. When quantities are added or subtracted, add their absolute uncertainties. When quantities are multiplied or divided, add their percentage uncertainties. The word is add, never subtract: the uncertainties always make the answer less certain, whatever the arithmetic does. If a quantity is raised to a power n, its percentage uncertainty is multiplied by n, so the percentage uncertainty in the volume of a sphere is three times the percentage uncertainty in the radius.

Here is the rule used on a real measurement. A student finds the mass of a metal block with a top-pan balance and its volume by displacement in a measuring cylinder. The density is the mass divided by the volume, so the percentage uncertainties add. The absolute uncertainty in the density is then that percentage of the density, and the density is quoted with its uncertainty to the same number of decimal places.

Quote the uncertainty to one or two significant figures and give the value to the same decimal place: 7.5 +/- 0.5 g cm-3, not 7.5 +/- 0.45 g cm-3. Finally, look at which measurement dominates. If the percentage uncertainty in the volume is five times that in the mass, there is no point in buying a better balance; you improve the result by measuring the volume more precisely.

QuantityValueAbsolute uncertaintyPercentage uncertainty
Mass60.0 g+/- 0.6 g0.6 / 60.0 x 100 = 1.0 per cent
Volume8.0 cm3+/- 0.4 cm30.4 / 8.0 x 100 = 5.0 per cent
Density60.0 / 8.0 = 7.5 g cm-30.060 x 7.5 = 0.45 g cm-31.0 + 5.0 = 6.0 per cent
Density quoted7.5 +/- 0.5 g cm-3+/- 0.5 g cm-36.0 per cent
Multiply or divide the values, add the percentages. Add or subtract the values, add the absolute uncertainties. Never subtract an uncertainty.

Scalars, vectors and resolving vectors into components

A scalar has magnitude only: distance, speed, mass, time, energy, work, power, density, pressure, temperature, charge and potential difference are all scalars, and they add like ordinary numbers. A vector has both magnitude and direction: displacement, velocity, acceleration, force, weight, friction, tension, momentum, impulse, electric field strength and magnetic flux density are all vectors. Direction is not decoration: two 5 N forces on the same object may add to 10 N or to zero depending on the angle between them, so a vector answer that gives no direction is incomplete.

Adding coplanar vectors. Draw them head to tail and the resultant is the single vector from the tail of the first to the head of the last; the parallelogram construction gives the same resultant. Subtracting a vector means adding it reversed, which is why a change in velocity is the final velocity plus the reversed initial velocity. If the two vectors act along the same line, add or subtract their magnitudes. If they are perpendicular, find the magnitude with Pythagoras and the direction with a tangent: for 3.0 km north followed by 4.0 km east the resultant displacement is the square root of (3.0^2 + 4.0^2) = 5.0 km, at an angle whose tangent is 4.0 / 3.0, that is 53 degrees east of north.

Resolving does the opposite: it replaces one vector by two perpendicular components that together have exactly the same effect. For a force F at an angle theta to the x-direction, the x-component is F cos theta and the y-component is F sin theta. Choose the axes so that as many forces as possible lie along them, and remember that the components are independent: the x-component affects only motion in x, which is why projectile motion splits so neatly into a constant-velocity horizontal part and an accelerating vertical part.

A standard use is a body on a slope of angle theta. The weight mg resolves into mg sin theta down the slope and mg cos theta perpendicular to the surface, while the normal contact force balances the perpendicular component. For a 2.0 kg block on a slope of 20 degrees: mg sin 20 = 2.0 x 9.81 x 0.342 = 6.7 N down the slope, and mg cos 20 = 2.0 x 9.81 x 0.940 = 18.4 N into the surface. Take care with which angle theta is measured from, because using the wrong one swaps sine and cosine.

Perpendicular components are independent, so resolve along axes chosen to put the known forces or the motion along them.

Key terms you must be able to define

SI base quantity and base unit
A quantity in terms of which all other quantities can be defined, with a unit that is not written in terms of any other unit. The five in this syllabus are mass (kg), length (m), time (s), electric current (A) and thermodynamic temperature (K).
Derived unit
The unit of a derived quantity, expressed as a product or quotient of SI base units: 1 N = 1 kg m s-2, 1 J = 1 kg m2 s-2, 1 Pa = 1 kg m-1 s-2.
Prefix
A symbol written before a unit to indicate a decimal multiple or submultiple of it, for example k for x 10^3, m for x 10-3 and n for x 10-9.
Systematic error (including a zero error)
An error that is the same in size and direction for every reading, so all readings are shifted the same way, for example a zero error or a wrongly calibrated scale; averaging cannot remove it, so the zero reading must be measured and subtracted.
Random error
An unpredictable error that varies in size and sign from one reading to the next, producing scatter about the mean; reduced by taking repeated readings and averaging them.
Precision
How close repeated measurements are to each other, so a small spread of readings means good precision; it depends on the resolution of the instrument and on the technique used.
Accuracy
How close a measurement is to the true value; it is spoiled by systematic errors and is only meaningful when the true value is known.
Percentage uncertainty
The absolute uncertainty of a measurement divided by the value of the measurement, multiplied by 100; when quantities are multiplied or divided their percentage uncertainties are added.
Vector
A quantity with both magnitude and direction, such as displacement, velocity, force, momentum or electric field strength; vectors of the same kind are added by a scale diagram or by resolving them into perpendicular components.

Applied to the real world

Cambridge sets 9702 in unfamiliar contexts - a fairground ride, a power station, a hospital scanner, a satellite, an astronomical observatory. Use these as models for how to apply the physics, then write your own.

In the laboratory

The diameter of a wire is measured with a micrometer screw gauge, whose resolution is 0.01 mm, rather than with a metre rule, whose resolution is 1 mm. Before measuring, the student closes the micrometer and finds that it reads +0.03 mm: a zero error. Every diameter reading is therefore 0.03 mm too large, so a reading of 0.52 mm gives a true diameter of 0.52 - 0.03 = 0.49 mm. Repeating each measurement and averaging would have done nothing to this error, because it shifts all the readings the same way.

In engineering

A steel tie rod in a bridge is designed to carry a tensile stress of 1.2 x 10^8 Pa. The pascal is a derived unit, 1 Pa = 1 N m-2 = 1 kg m-1 s-2, so the stress is 1.2 x 10^8 N m-2 and a rod of cross-sectional area 4.0 x 10-4 m2 carries a force of 1.2 x 10^8 x 4.0 x 10-4 = 4.8 x 10^4 N. Machined parts are made to a stated tolerance such as +/- 0.02 mm, and a part outside that band is rejected even if the machine was precise, because a correct mean value is not enough when individual parts must be accurate.

In sport

A 100 m sprint is timed electronically to 0.01 s and the wind speed is measured, with a following wind above 2.0 m s-1 making a record invalid. Timing by hand with a stopwatch adds the timer's reaction time, which varies unpredictably from race to race: that is a random error, so it is reduced by taking several timings and averaging. A stopwatch that is calibrated to run slow, on the other hand, would make every time too small by the same proportion, and averaging would never reveal it.

In medicine

Body temperature is measured in kelvin: a patient at 37.0 degrees C is at 37.0 + 273 = 310 K. Drug doses are written with prefixes rather than with long strings of zeros, so a prescription for 250 mg of a drug means 250 x 10-3 g = 0.25 g, and a syringe may be graduated in microL where 1 microL = 1 x 10-6 L. Mixing up milli and micro gives a dose a thousand times too large, which is why the prefix, not just the number, is checked.

In astronomy

Astronomers work in prefixes because the numbers are so large. The mass of the Sun is 1.99 x 10^30 kg, which is 1.99 x 10^27 tonne and about 3.3 x 10^5 times the mass of the Earth at 5.97 x 10^24 kg. The distance to Proxima Centauri is 4.0 x 10^16 m, which is more compactly written as 4.0 x 10^13 km. Every one of these values is a magnitude with a unit; the distance alone means nothing unless you know whether it is in metres, kilometres or light-years.

Flashcards

Click a card to flip it. Mark honestly — the tracker uses this.

Q1What two parts make up every physical quantity?
A numerical magnitude and a unit. A length of 2.4 m has magnitude 2.4 and unit m; the number on its own is not a physical quantity.
Q2List the five SI base quantities used in this syllabus with their base units.
Mass in kilograms (kg), length in metres (m), time in seconds (s), electric current in amperes (A) and thermodynamic temperature in kelvin (K).
Q3Express the newton, the joule and the pascal in SI base units.
1 N = 1 kg m s-2, from F = m a. 1 J = 1 N m = 1 kg m2 s-2, from W = F s. 1 Pa = 1 N m-2 = 1 kg m-1 s-2, from p = F / A.
Q4What is the factor and symbol of the prefixes nano, micro, milli and centi?
Nano (n) is x 10-9, micro (mu) is x 10-6, milli (m) is x 10-3 and centi (c) is x 10-2.
Q5What is the factor and symbol of the prefixes kilo, mega, giga and tera?
Kilo (k) is x 10^3, mega (M) is x 10^6, giga (G) is x 10^9 and tera (T) is x 10^12.
Q6How do you use base units to check whether an equation is homogeneous?
Replace every quantity in the equation by its SI base units and simplify each side. If both sides reduce to the same base units the equation is homogeneous; if they do not, the equation must be wrong.
Q7Why can a units check never prove an equation correct?
Because dimensionless factors such as 0.5 or 2 pi carry no units at all, so s = a t2 and s = 0.5 a t2 both pass the check. Units can rule an equation out, never in.
Q8What is a random error and how is it reduced?
An error that varies unpredictably in size and sign from reading to reading, scattering the readings about a mean. It is reduced by repeating the measurement and averaging, and by careful technique such as reading a scale at eye level.
Q9What is a systematic error, and why does averaging not remove it?
An error that shifts every reading by the same amount or the same fraction, such as a zero error or a wrongly calibrated scale. Because every reading is shifted the same way, the mean is shifted too; the error must be found and corrected.
Q10What is the difference between precision and accuracy?
Precision is how close repeated readings are to each other, so it describes the spread. Accuracy is how close a reading is to the true value. Precise readings can be inaccurate if there is a zero error.
Q11How is the percentage uncertainty of a measurement calculated?
Percentage uncertainty = (absolute uncertainty / value) x 100, for example 0.6 g in 60.0 g is 1.0 per cent. From repeated readings the absolute uncertainty is half the range.
Q12How do uncertainties combine when quantities are multiplied, divided or raised to a power?
For a product or quotient, add the percentage uncertainties. For a quantity raised to a power n, multiply its percentage uncertainty by n. For a sum or difference, add the absolute uncertainties.
Q13How is a vector resolved into two perpendicular components?
A force F at an angle theta to the x-direction has components F cos theta along x and F sin theta along y. The components are independent, which is why projectile motion splits into horizontal and vertical parts.
Q14How is the resultant of two perpendicular vectors found?
Magnitude from Pythagoras, direction from the tangent of the angle: 3.0 km north with 4.0 km east gives a resultant of 5.0 km at 53 degrees east of north.
0 of 14 marked as known

Exam-style questions

9 questions, 30 marks. Write your answer, then reveal the mark scheme and tick each point you actually made. Answering honestly here is what makes the rest of the site useful.

StateAO11 mark
State the SI base unit of electric current and the SI base unit of thermodynamic temperature.

Mark scheme — tick each point you actually made

Examiner tip: One mark, so one unit for each quantity. Write the symbol as well as the name, and do not offer the coulomb or the degree Celsius.
StateAO12 marks
State the numerical factor represented by each of the prefixes nano (n), micro (mu), mega (M) and tera (T).

Mark scheme — tick each point you actually made

Any 2 of these score full marks. The examiner only needs 2 distinct points - pick the ones you actually made.
Examiner tip: Keep the factors apart: nano is 10-9 and micro is 10-6, while mega and giga are 10^6 and 10^9. The prefix letter is part of the answer, so n, mu, M and T must be given.
Show thatAO23 marks
The Boltzmann constant has a value of 1.38 x 10-23 J K-1. Show that the unit J K-1 can be written in SI base units as kg m2 s-2 K-1.

Mark scheme — tick each point you actually made

Examiner tip: Work from the defining equations rather than from memory, and show each step. The K-1 simply comes along for the ride once the joule is reduced to base units.
Show thatAO23 marks
A suggested equation for the period T of a simple pendulum of length l is T = 2 pi sqrt(l / g), where g is the acceleration of free fall. Use SI base units to show that this equation is homogeneous.

Mark scheme — tick each point you actually made

Examiner tip: Divide the units of l by the units of g and take the square root, exactly as the equation tells you to. Mentioning that 2 pi is a pure number is worth making explicit.
ExplainAO24 marks
A student finds the time for 20 oscillations of a pendulum with a digital stopwatch and measures the length of the pendulum with a metre rule whose zero end is worn away. (a) Explain why the student's reaction time gives a random error and why timing 20 oscillations reduces its effect. (b) State the type of error caused by reading from the worn end of the rule and describe how the student should deal with it.

Mark scheme — tick each point you actually made

Examiner tip: Part (a) needs the word random and a reason tied to the scatter, then the arithmetic of dividing a fixed error by 20. In part (b), averaging will not help a systematic error, so you must say that the reading is corrected or subtracted.
CalculateAO23 marks
A student measures the mass of a small metal cylinder as 54.0 g with a percentage uncertainty of 1.0 per cent, and its volume as 20.0 cm3 with a percentage uncertainty of 3.0 per cent. Calculate the density of the metal and give its value with its absolute uncertainty.

Mark scheme — tick each point you actually made

Examiner tip: Give the density with its unit and then add the two percentages; do not subtract them. Quote the uncertainty to two significant figures and give the density to the same decimal place.
CalculateAO24 marks
A box of weight 180 N is pulled along a horizontal floor by a rope held at 30 degrees above the horizontal, with a tension of 250 N. (a) Calculate the horizontal and the vertical components of the tension. (b) Deduce, with a calculation, whether the box is lifted off the floor.

Mark scheme — tick each point you actually made

Examiner tip: Cosine goes with the direction the angle is measured from, so the component along the floor is 250 cos 30 and the component perpendicular to it is 250 sin 30. Part (b) needs the numbers compared, not just a statement.
DiscussAO35 marks
Two students each measure the diameter of the same wire five times with a micrometer screw gauge. The accepted value is 0.54 mm. Student A records 0.58, 0.59, 0.58, 0.57 and 0.58 mm. Student B records 0.52, 0.56, 0.49, 0.61 and 0.54 mm. Discuss the accuracy and the precision of each student's results, and suggest what each student should do next.

Mark scheme — tick each point you actually made

Examiner tip: Keep the two words separate all the way through: spread means precision, distance from the accepted value means accuracy. Work out both means and quote them, because the numbers are the evidence for your judgement.
CalculateAO25 marks
A car travels 3.0 km due north and then 4.0 km due east. (a) State whether displacement is a scalar or a vector and explain your answer. (b) Calculate the magnitude of the resultant displacement. (c) Calculate the direction of the resultant displacement as an angle east of north.

Mark scheme — tick each point you actually made

Examiner tip: Name the reference direction, and say which side of it the angle lies on: 53 degrees east of north is a complete answer, 53 degrees is not. Check your trigonometry gives a sensible value, since 4 / 3 is close to 1 and the angle must be close to 45 degrees.

Exam technique for this topic

  • Check every equation by units before you use it, and write the base units of each term in the margin. A term that does not reduce to the same base units as the others proves the equation is wrong, and that reasoning scores on its own.
  • When uncertainties are combined, state the rule you are using: add the percentage uncertainties for a product or quotient, add the absolute uncertainties for a sum or difference. Subtracting an uncertainty is the single commonest way to lose a mark in this topic.
  • Give the unit with every answer, including estimates and intermediate steps. A calculation that ends at 5.0 when the question asked for a speed has not been answered.
  • In a zero-error question, quote both the reading and the correction: a micrometer reading of 0.52 mm with a zero error of +0.03 mm gives a true diameter of 0.49 mm. Do not simply say the reading is wrong.
  • For any vector answer, give the direction as well as the magnitude and name the reference direction, for example 53 degrees east of north. When you resolve, say which angle theta is measured from, so the examiner can see whether you need sine or cosine.
  • Estimate to the nearest power of ten and give one or two significant figures only. An estimate of the mass of a person written as 68.4 kg shows that you do not understand what an estimate is.

Why students lose marks here

A student wroteA student wrote: 'the current is 470 microA, which is 470 x 10-3 A.'
Why it loses marksThe prefix micro means x 10-6, not x 10-3. Writing the wrong factor makes the current a thousand times too large, and the same slip between milli and micro is a serious error in a dose or a capacitance.
The answer that scores470 microA = 470 x 10-6 A = 4.7 x 10-4 A. The factor for micro (mu) is 10-6, while milli (m) is 10-3, centi (c) is 10-2, nano (n) is 10-9 and pico (p) is 10-12. Convert to base units first, then substitute into the equation.
A student wroteA student wrote: 'the pascal is the same as N m, because pressure is force divided by area.'
Why it loses marksDividing by area means dividing by m2, not multiplying by m. The student has also mis-stated the defining equation in terms of units, which makes the answer wrong by a factor of m3.
The answer that scoresPressure p = F / A, so 1 Pa = 1 N / 1 m2 = 1 N m-2 = 1 kg m s-2 / m2 = 1 kg m-1 s-2. The newton itself is 1 kg m s-2, and dividing by m2 reduces the power of the metre by two.
A student wroteA student wrote: 'mass 60.0 +/- 0.6 g and volume 8.0 +/- 0.4 cm3 give a density of 7.5 g cm-3 with a percentage uncertainty of 5.0 - 1.0 = 4.0 per cent.'
Why it loses marksUncertainties are never subtracted. Density is a quotient, so the percentage uncertainties add, and subtracting them understates how uncertain the answer really is.
The answer that scoresThe percentage uncertainties are 0.6 / 60.0 x 100 = 1.0 per cent for the mass and 0.4 / 8.0 x 100 = 5.0 per cent for the volume. For a quotient they add, so the percentage uncertainty in the density is 1.0 + 5.0 = 6.0 per cent. The absolute uncertainty is 0.060 x 7.5 = 0.45 g cm-3, so the density is 7.5 +/- 0.5 g cm-3, quoted to the same decimal place as the value.
A laboratory bench with a top-pan balance and a measuring cylinder set up for a density measurement, the apparatus whose mass and volume uncertainties add to give the uncertainty in the derived density.
A student wroteA student wrote: 'student A's readings of the wire diameter are accurate, because 0.58, 0.59, 0.58, 0.57 and 0.58 mm are all very close to each other.'
Why it loses marksBeing close to each other is precision, not accuracy. Accuracy is closeness to the true value, and every one of these readings sits about 0.04 mm above the accepted 0.54 mm, so the set is precise but inaccurate.
The answer that scoresThe readings are precise: their spread is only 0.02 mm, so random errors are small. They are not accurate, because their mean of 0.58 mm differs from the accepted value of 0.54 mm by 0.04 mm, which is far more than the spread. A constant shift of every reading in the same direction indicates a systematic error such as a zero error on the micrometer, which has to be measured and subtracted rather than averaged away.

Where this fits in AS & A Level Physics

This page is one topic of Cambridge AS & A Level Physics 9702. AS & A Level Physics is the course home: every area and every topic in Cambridge's own order, the papers you sit and what each one tests, and the exam-practice tools. The full topic list, with each topic linked to its revision page, is on the AS & A Level Physics syllabus page.