AS & A Level Chemistry · Area 1 · AS Level Content

Atomic structure

Atomic structure explains where the mass and the charge of an atom are found, how the electrons are arranged in shells, sub-shells and orbitals, and how that arrangement decides the electronic configuration of the elements up to krypton. Ionisation energy and the trends in it are covered too.

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Syllabus coverage

  • Understand that atoms are mostly empty space surrounding a very small, dense nucleus that contains protons and neutrons, with electrons found in shells in the empty space around the nucleus
  • Identify and describe protons, neutrons and electrons in terms of their relative charges and relative masses, describe the distribution of mass and charge within an atom, and describe the behaviour of beams of protons, neutrons and electrons moving at the same velocity in an electric field
  • Understand the terms atomic (proton) number and mass (nucleon) number, and determine the numbers of protons, neutrons and electrons present in both atoms and ions given the atomic number, the mass number and the charge
  • State and explain qualitatively the variations in atomic radius and ionic radius across a period and down a group
  • Define the term isotope in terms of numbers of protons and neutrons, use the notation in which the mass or nucleon number is written above the atomic or proton number, and explain why isotopes of the same element have the same chemical properties but different physical properties, limited to mass and density
  • Understand the terms shells, sub-shells and orbitals, principal quantum number (n), and ground state, and describe the number of orbitals making up s, p and d sub-shells and the number of electrons that can fill them
  • Describe the order of increasing energy of the sub-shells within the first three shells and the 4s and 4p sub-shells, and describe and sketch the shapes of s and p orbitals
  • Describe the electronic configurations of atoms and ions to include the number of electrons in each shell, sub-shell and orbital, using full and shorthand electronic configuration and the electrons in boxes notation, and explain those configurations in terms of the energy of the electrons and inter-electron repulsion, and describe a free radical as a species with one or more unpaired electrons
  • Define and use the term first ionisation energy, construct equations to represent first, second and subsequent ionisation energies, and explain ionisation energies in terms of the attraction between the nucleus and the outer electron
  • Identify and explain the trends in ionisation energies across a period and down a group and the variation in successive ionisation energies of an element, in terms of nuclear charge, atomic and ionic radius, shielding by inner shells and sub-shells and spin-pair repulsion, and deduce the electronic configuration and the position in the Periodic Table of an element from successive ionisation energy data

Part of the AS & A Level Chemistry syllabus 9701.

Atomic orbitals and the order of fillingAn orbital is a region of space that holds at most two electrons. An s orbital is spherical; the three porbitals are dumbbell shaped and lie at right angles to one another.1. The shapes of s and p orbitalsAn orbital holds at most two electrons, of opposite spin.1s orbital: a sphere2px along x2py along y2pz along zThe three p orbitals are identical in shape and energy; they differ only in direction.2. The order of filling of the subshells1s2s2p3s3p4s3d4pSubshells fill in order of increasing energy. Each subshell is filled before the next one starts.Note the order: 4s fills BEFORE 3d, because the 4s subshell is slightly lower in energy.Sequence: 1s 2s 2p 3s 3p 4s 3d 4p3. Arrows-in-boxes electron configuration: iron, Fe (Z = 26)Each box is one orbital. One arrow up plus one arrow down per box means the two electrons are paired with oppositespins.1s2s2p3s3p4s3dArrows up and down are the two opposite spins; the 3d boxes fill after 4s.Total: 2+2+6+2+6+2+6 = 26 e-
The shapes of s and p orbitals: an s orbital is a sphere drawn with the nucleus at its centre and a 2s orbital is a smaller sphere inside a larger one, while the three p orbitals are dumbbell shaped and lie at 90 degrees to one another along the x, y and z axes, each with a node of zero electron density at the nucleus.

Inside the atom: particles, mass, charge and the numbers that describe them

An atom is mostly empty space. Almost all of its mass is concentrated in a very small, dense nucleus at the centre, which contains protons and neutrons; the rest of the atom is the empty space through which the electrons move, arranged in shells around the nucleus. If an atom were scaled up to the size of a football stadium, the nucleus would be about the size of a pea on the centre spot, yet it would still carry more than 99.9% of the mass of the atom.

Protons and neutrons have almost exactly the same mass, and each is about 1840 times heavier than an electron, so nearly all the mass of an atom sits in its nucleus. The charge is just as unevenly distributed: a proton carries one unit of positive charge, an electron carries one unit of negative charge, and a neutron carries no charge at all. In a neutral atom the number of protons equals the number of electrons, so the positive and negative charges cancel and the atom as a whole has no charge. The electrons are held inside the atom by the electrostatic attraction between the negative electrons and the positive nucleus.

Two numbers describe every atom. The atomic number (or proton number), symbol Z, is the number of protons in the nucleus, and it identifies the element: every carbon atom has Z = 6. The mass number (or nucleon number), symbol A, is the total number of protons and neutrons, so the number of neutrons is A - Z. A chlorine atom with A = 35 and Z = 17 therefore has 17 protons, 35 - 17 = 18 neutrons and 17 electrons. For an ion only the electron count changes: an ion with a charge of n+ has lost n electrons and has Z - n electrons, while an ion with a charge of n- has gained n electrons and has Z + n electrons. A 56Fe3+ ion has 26 protons, 30 neutrons and 26 - 3 = 23 electrons; the mass number is untouched by the charge, because only electrons have been gained or lost.

Because the force on a moving particle in an electric field depends on its charge, a beam containing protons, neutrons and electrons all travelling at the same velocity is split into three. Protons are deflected towards the negative plate, and electrons are deflected towards the positive plate, in the opposite direction. Neutrons are not deflected at all, because they carry no charge. The electron beam is deflected far more than the proton beam: a proton has the same size of charge as an electron but about 1840 times the mass, so its charge-to-mass ratio is much smaller and the field bends its path much less.

  • Neutrons = mass number A - atomic number Z.
  • Electrons in a neutral atom = Z; in an ion of charge n+ they are Z - n, and in an ion of charge n- they are Z + n.
  • Almost all the mass and all of the positive charge of an atom are in the nucleus; the electrons occupy the empty space around it.
  • The deflection of a particle in an electric field depends on its charge-to-mass ratio, which is why electrons are bent far more than protons.
PropertyProtonNeutronElectron
Relative charge+10-1
Relative mass11about 1/1840
Position in the atomIn the nucleusIn the nucleusIn shells in the empty space around the nucleus
Deflection in an electric fieldTowards the negative plate, a small deflectionNone, because it has no chargeTowards the positive plate, a large deflection
Nearly all the mass and all of the positive charge sit in the nucleus; the electrons fill the empty space and carry all the chemistry.

Isotopes: the same element with a different mass

Isotopes are atoms of the same element that have the same number of protons but different numbers of neutrons. They therefore have the same atomic number but different mass numbers. The symbol for an isotope carries the mass (nucleon) number at the top left and the atomic (proton) number at the bottom left of the element symbol, so the two isotopes of chlorine are written with 35 above 17 and 37 above 17 in front of Cl, and on a single line as Cl-35 and Cl-37. Chlorine-35 has 17 protons and 18 neutrons, and chlorine-37 has 17 protons and 20 neutrons.

Isotopes of an element have identical chemical properties, because chemistry is controlled entirely by the number and arrangement of the electrons, and isotopes of the same element have exactly the same number of electrons in exactly the same configuration. Chlorine-35 and chlorine-37 both form chloride ions, both form hydrogen chloride, and both bleach litmus in the same way. The extra neutrons in chlorine-37 sit in the nucleus and take no part in bonding.

Their physical properties differ wherever mass matters: the two isotopes have different masses, and a sample enriched in the heavier isotope has a greater density. Heavy water, D2O, is made from deuterium, the isotope of hydrogen with one proton and one neutron, and it is denser than ordinary water and boils at a slightly higher temperature. Because mass is practically the only difference, isotopes can be separated by physical methods that depend on mass, such as the gaseous diffusion or gas centrifugation of uranium hexafluoride, which separates uranium-235 from uranium-238.

The relative atomic mass you find on the Periodic Table is the weighted mean of the masses of the isotopes, so it is rarely a whole number. Copper, for example, has a relative atomic mass of 63.5 because it is a mixture of Cu-63 and Cu-65, and chlorine has 35.5 because it is roughly three parts Cl-35 to one part Cl-37. The mass number, by contrast, is always a whole number, because it counts particles in one particular atom.

  • Isotopes: same number of protons and the same number of electrons, different number of neutrons.
  • Identical chemical properties, because the electrons are arranged identically.
  • Different mass and density, because the masses of the atoms differ.
  • Relative atomic mass is the weighted mean of the isotope masses, so it is usually not a whole number, unlike the mass number.
Same protons, different neutrons: identical chemistry, different mass and density.

Atomic radius and ionic radius

Atomic radius decreases across a period from left to right. In Period 3 the radius falls steadily from sodium to chlorine, because the nuclear charge rises from +11 to +17 while the outer electrons stay in the same shell. The inner shells shield the outer electrons by the same amount in each element, so the steady increase in nuclear charge pulls the same shell in more tightly and the atom gets smaller.

Down a group the atomic radius increases. Each element down the group has one more occupied shell than the element above it, so the outer electrons begin further from the nucleus. The extra inner shells also shield the outer electrons from the nuclear charge more effectively. Both effects weaken the pull of the nucleus on the outer electron, and they outweigh the increase in nuclear charge, so the atom gets larger as you go down a group.

A cation is smaller than the atom it came from, because electrons have been removed from the outer shell while the nuclear charge is unchanged, so the same positive charge is now pulling in fewer electrons. A sodium atom is about 186 pm across and a sodium ion only about 102 pm. An anion is larger than its atom, because extra electrons have been added into the outer shell and the increased electron-electron repulsion spreads them out: a chlorine atom is about 99 pm across and a chloride ion about 181 pm.

Ions that contain the same number of electrons, called isoelectronic ions, can be compared directly. N3-, O2-, F-, Na+, Mg2+ and Al3+ all have 10 electrons in the same arrangement, but the nuclear charge increases from +7 to +13 across the series. The same ten electrons are pulled in more strongly as the charge rises, so the ionic radius falls along the series N3- > O2- > F- > Na+ > Mg2+ > Al3+. Down a group the ionic radius increases for the same reason the atomic radius does: an extra shell has been added, and the extra shielding outweighs the extra protons.

Across a period the radius falls because the nuclear charge rises while shielding stays the same; down a group it rises because an extra shell is added.

Shells, sub-shells and orbitals

The electrons in an atom are arranged in shells, each labelled by a number called the principal quantum number, n. The shell with n = 1 lies closest to the nucleus and is lowest in energy, and the energy of a shell increases as n increases, so the 3s sub-shell is higher in energy than the 2s sub-shell. A shell is not a simple ring of electrons: each shell contains one or more sub-shells, and each sub-shell contains one or more orbitals.

An orbital is a region of space around the nucleus that can hold a maximum of two electrons with opposite spins. The type of sub-shell decides how many orbitals it contains. An s sub-shell contains one orbital and holds two electrons, a p sub-shell contains three orbitals and holds six electrons, and a d sub-shell contains five orbitals and holds ten electrons. Watch the wording here: it is the p sub-shell that holds six electrons, spread over three separate p orbitals, and each single p orbital still holds only two.

The sub-shells fill in order of increasing energy, which for the elements up to krypton gives the sequence 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p. Notice that 4s lies below 3d in energy, so 4s is filled first even though it belongs to the fourth shell. The reason is shielding: the 3d sub-shell is screened from the nucleus by the electrons already present in 3s and 3p, which raises the energy of 3d above that of 4s. The ground state of an atom is the arrangement of its electrons that has the lowest possible energy, and every configuration you write for this course is a ground state configuration.

Type of sub-shellNumber of orbitalsMaximum number of electrons
s12
p36
d510
One orbital holds two electrons. An s sub-shell is one orbital, a p sub-shell is three orbitals and a d sub-shell is five.

Electronic configurations of atoms and ions, and electrons in boxes

To write the electronic configuration of an atom, fill the sub-shells in order of increasing energy, 1s 2s 2p 3s 3p 4s 3d 4p, and put in as many electrons as the atom has. Sodium has 11 electrons, so its configuration is 1s2 2s2 2p6 3s1, which shows 2 electrons in the first shell, 8 in the second and 1 in the third. Iron has 26 electrons and its full electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d6 4s2, while the shorthand electronic configuration replaces the first 18 electrons with the symbol of the noble gas that has the same arrangement, giving [Ar] 3d6 4s2.

Electrons in boxes notation shows the arrangement orbital by orbital. Each box is one orbital, and inside a sub-shell the boxes are filled singly first, with all the single electrons given parallel spins, before any box receives a second electron. Iron in boxes is [Ar] followed by five boxes for 3d holding 1, 1, 1, 1 and 2 electrons, and one box for 4s holding a pair. The arrangement with single electrons in separate orbitals is preferred because electrons repel one another and keep as far apart as possible, which lowers the energy of the atom.

Two elements in the first row of the transition elements do not follow the simple filling pattern, because a half-filled or completely filled d sub-shell is lower in energy. Chromium is [Ar] 3d5 4s1 and copper is [Ar] 3d10 4s1, not the [Ar] 3d4 4s2 and [Ar] 3d9 4s2 that the filling order alone would suggest. Spreading the six or eleven outer electrons out this way reduces inter-electron repulsion between electrons in the same orbital, so the half-filled and completely filled arrangements are the ground states.

For an ion, add or remove electrons where the energy change is smallest. When a transition element forms a positive ion the 4s electrons are lost first, even though 4s was filled first, because once the 3d orbitals are occupied the 3d sub-shell lies lower in energy than 4s. So iron is [Ar] 3d6 4s2, Fe2+ is [Ar] 3d6 and Fe3+ is [Ar] 3d5. For a negative ion such as O2- or Cl-, add the extra electrons to the next available orbital in the usual filling order: chlorine is [Ne] 3s2 3p5 and the chloride ion is [Ne] 3s2 3p6.

  • Fill in the order 1s 2s 2p 3s 3p 4s 3d 4p and check that the electrons add up to the atomic number.
  • Shorthand configuration replaces the inner electrons with the previous noble gas in square brackets: [Ar] 3d6 4s2 for iron.
  • Chromium is [Ar] 3d5 4s1 and copper is [Ar] 3d10 4s1, because a half-filled or filled d sub-shell has a lower energy.
  • When a transition element is ionised, the 4s electrons are removed before the 3d electrons.
4s fills first, but 3d electrons are held more tightly once the d sub-shell is occupied, so a transition element loses its 4s electrons first when it is ionised.

The shapes of s and p orbitals, and free radicals

An s orbital is spherical. The chance of finding the electron is the same in every direction at a given distance from the nucleus, so an s orbital is drawn as a sphere with the nucleus at its centre, and every shell has exactly one s orbital: 1s, 2s and 3s. A 2s orbital is not just a bigger 1s orbital: it also has an inner region of electron density, so it is drawn as a smaller sphere inside a larger one, with a radial node between them.

A p orbital is dumbbell shaped: two lobes on opposite sides of the nucleus, with a node at the nucleus where the electron density is zero. Each p sub-shell contains three p orbitals, which lie at 90 degrees to one another and are usually labelled px, py and pz after the axis each one lies along. When you sketch a p orbital, show the two lobes of equal size on opposite sides of the nucleus and make it clear that the nucleus sits at the gap between them, not inside a lobe.

The shape of an orbital matters because bonding happens where orbitals overlap, and the direction of the lobes of a p orbital is what gives molecules such as water and ammonia their three-dimensional shapes. It also explains the difference between a sigma bond, formed by end-on overlap, and a pi bond, formed by the sideways overlap of two p orbitals above and below the line joining the nuclei.

A free radical is a species with one or more unpaired electrons. A chlorine atom, Cl, is a free radical, and it is produced in the first step of the reaction between chlorine and methane when ultraviolet light splits a Cl2 molecule into two chlorine atoms: Cl2 -> 2Cl. The unpaired electron makes a free radical extremely reactive, because pairing that electron with another one in an orbital lowers the energy of the species, so the radical will attack almost anything that can supply an electron. In electrons in boxes notation a free radical is shown by a box containing a single arrow, for example the 3p sub-shell of a chlorine atom has one box with a single unpaired electron.

  • An s orbital is spherical; a p orbital is dumbbell shaped with a node at the nucleus.
  • A p sub-shell holds three orbitals at 90 degrees to one another; a d sub-shell holds five.
  • A free radical is a species with one or more unpaired electrons, which makes it very reactive, for example a chlorine atom Cl.
An s orbital is a sphere, a p orbital is a dumbbell with a node at the nucleus, and an unpaired electron in a box means you are looking at a free radical.

Ionisation energy: definition, factors and trends

The first ionisation energy of an element is the energy required to remove one electron from each atom in one mole of gaseous atoms to form one mole of gaseous 1+ ions: Na(g) -> Na+(g) + e-. The word gaseous matters, because the definition is about isolated, well-separated atoms, and so does the word one mole, because the energy is quoted per mole. The second ionisation energy removes the second electron from a gaseous 1+ ion, Na+(g) -> Na2+(g) + e-, and the third from a gaseous 2+ ion, Mg2+(g) -> Mg3+(g) + e-. Successive ionisation energies are measured in kJ mol-1.

Ionisation energy is the energy needed to overcome the attraction between the nucleus and the outer electron, so anything that strengthens that attraction raises the ionisation energy. Three factors decide the size of the attraction. Nuclear charge: the more protons in the nucleus, the more strongly the outer electron is pulled. Distance from the nucleus, described by the atomic or ionic radius: the further away the electron is, the weaker the attraction. Shielding by inner shells and inner sub-shells: the inner electrons repel the outer electron and screen it from part of the nuclear charge, so the outer electron only feels an effective attraction, which is smaller than the true nuclear charge. A fourth factor matters when two electrons share an orbital: spin-pair repulsion, the repulsion between the two electrons of a pair, which raises the energy of one of them and makes it easier to remove.

Across a period the first ionisation energy generally increases, and down a group it decreases. In Period 3 the values are 496 (Na), 738 (Mg), 577 (Al), 786 (Si), 1012 (P), 1000 (S), 1251 (Cl) and 1521 (Ar) kJ mol-1. Moving from left to right, the nuclear charge increases by one proton for each element while the outer electron remains in the same shell, so shielding is roughly constant and the atomic radius falls, and the outer electron is held more strongly, so more energy is needed to remove it. Going down a group the outer electron moves into a shell with a larger principal quantum number, so it starts further from the nucleus, and the extra inner shells shield it from the nuclear charge; both effects weaken the attraction and together they outweigh the extra protons, so the value falls from 520 kJ mol-1 for lithium to 496 for sodium and 419 for potassium.

The trend is not perfect, and the two dips have different causes. Aluminium (577) is lower than magnesium (738) because the extra electron in aluminium is the first electron in a 3p orbital. A 3p orbital is higher in energy than the filled 3s orbital below it and is shielded by the 3s electrons, so it is easier to remove than the 3s electron of magnesium. Sulphur (1000) is lower than phosphorus (1012) for a different reason: phosphorus has a 3p3 arrangement with one electron in each p orbital, while sulphur has a 3p4 arrangement containing one pair, and the spin-pair repulsion between the two electrons in that pair makes one of them easier to remove.

ElementFirst ionisation energy / kJ mol-1Why it fits the trend
Na496First element of Period 3, one 3s electron
Mg738Two 3s electrons, higher nuclear charge than Na
Al577Dip: the electron being removed is in the higher-energy 3p sub-shell
P10123p3, one electron in each p orbital
S1000Dip: 3p4, spin-pair repulsion in one p orbital
Cl1251High nuclear charge, small radius, no paired 3p electrons until the fourth
Ar1521Highest in Period 3, filled 3p sub-shell close to the nucleus
Nuclear charge, distance and shielding explain every ionisation energy trend; add spin-pair repulsion when the electron being removed is one of a pair in the same orbital.
First ionisation energy trendsThe energy needed to remove one mole of electrons from one mole of gaseous atoms: X(g) -> X+(g) + e-. AcrossPeriod 3 it rises, with two dips; down Group 2 it falls.Across Period 3 (Na to Ar)0500100015002000elementfirst I.E. / kJ mol-1NaMgAlSiPSClArdip at Al: the outer electron movesfrom 3p down to 3s, which is lowerdip at S: the two 3p electronsare paired and repel each otherAll the outer electrons are in shell n = 3, so thenuclear charge grows and they are pulled in moretightly. The two dips are exceptions of structure,not of trend.Down Group 2 (Be to Ba)04008001200elementBeMgCaSrBaFurther out and more shielded, so lessenergy is needed to remove it.Across the group the atoms get larger andthe outer electron is in a new, moreshielded shell, so the ionisation energyfalls.What decides the first ionisation energyNuclear chargeMore protons pull the outerelectron in more strongly, so itrises across a period.e.g. Na 496 to Ar 1521Distance from the nucleusThe further out the outerelectron is, the weaker thepull, so it falls down a group.e.g. Be 899 to Ba 503Shielding by the inner shellsInner electrons repel the outerelectron and cancel part of thenuclear charge.the effective charge felt is smaller
First ionisation energy plotted against atomic number: the values rise across each period, with small dips at the group 3 and group 6 elements where the electron is removed from a higher-energy sub-shell or from a spin-paired orbital, and they fall sharply at the start of each new period when a new shell is begun.

Successive ionisation energies: reading the structure of the atom from the data

The second ionisation energy removes an electron from a gaseous 1+ ion, the third from a gaseous 2+ ion, and so on, so the tenth ionisation energy of an element is the energy needed to remove one electron from each ion in one mole of gaseous 9+ ions. Successive ionisation energies always increase, because every electron is removed from an ion that is already positive. With fewer electrons left to share the nuclear charge there is less electron-electron repulsion, and the remaining electrons are held more strongly, so each removal costs more energy than the one before.

The size of the jump between consecutive values tells you which shell the electron came from. While electrons are being removed from the same shell the values rise steadily, but the first electron removed from a shell closer to the nucleus produces a large jump, typically a factor of five or more. For sodium the first ionisation energy is 496 kJ mol-1 and the next eight values climb steadily to about 29 000 kJ mol-1, but the tenth is above 141 000 kJ mol-1. The first electron comes from the 3s sub-shell, whereas the tenth comes from the 1s sub-shell, which is much closer to the nucleus and much more strongly held.

This is how ionisation energy data reveal an electronic configuration. The element with successive ionisation energies of 738, 1451, 7733, 10540 and 13630 kJ mol-1 has a big jump between the second and third values, because 7733 / 1451 is about 5.3 while the earlier step is only about 2.0. Only two electrons are therefore being removed from the outer shell, and the third electron comes from a shell nearer the nucleus. An element with two outer electrons is in Group 2 of the Periodic Table, and these values are those of magnesium, whose full configuration 1s2 2s2 2p6 3s2 confirms it.

The rule to remember is that the number of electrons removed before the first big jump is the number of electrons in the outer shell, which for a main-group element is the group number. Sketching a graph of the logarithm of the ionisation energy against the number of electrons removed makes the pattern obvious, because the values on each completed shell fall on a straight line and the change of shell shows as a break in the line. A transition element shows a jump after the 4s electrons have been removed and then a further break when the 3d electrons are finished, so the same method works for the d block.

Electron removed1st2nd3rd4th5th
Ionisation energy / kJ mol-1738145177331054013630
Ion left behindMg+Mg2+Mg3+Mg4+Mg5+
Count the electrons removed before the first big jump: that number is the number of outer electrons, and for a main-group element it is the group number.

Key terms you must be able to define

Atomic (proton) number
The number of protons in the nucleus of an atom, given the symbol Z; it identifies the element, and in a neutral atom it also equals the number of electrons.
Mass (nucleon) number
The total number of protons and neutrons in the nucleus of an atom, given the symbol A; the number of neutrons present is A - Z.
Isotopes
Atoms of the same element that have the same number of protons but different numbers of neutrons, so they have the same atomic number and different mass numbers.
Relative atomic mass
The weighted mean mass of the atoms of an element compared with one twelfth of the mass of an atom of carbon-12; it takes account of the relative abundance of each isotope, so it is usually not a whole number and it has no units.
Orbital
A region of space around the nucleus that can hold a maximum of two electrons with opposite spins; an s sub-shell contains one orbital, a p sub-shell three and a d sub-shell five.
Principal quantum number (n)
The number that labels the shell an electron occupies; the shell with n = 1 is closest to the nucleus and lowest in energy, and the energy of a shell increases as n increases.
First ionisation energy
The energy required to remove one electron from each atom in one mole of gaseous atoms to form one mole of gaseous 1+ ions; measured in kJ mol-1.
Free radical
A species that has one or more unpaired electrons, which makes it very reactive because pairing the unpaired electron with another electron in an orbital lowers the energy of the species.
Spin-pair repulsion
The repulsion between the two electrons that share an orbital, which raises the energy of one of them and so lowers the ionisation energy of an element below the value the trend would otherwise predict.

Applied to the real world

Cambridge sets 9701 in named contexts - an industrial plant, a laboratory, a hospital, a car battery, a water treatment works. Use these as models for how to apply the chemistry, then write your own.

In a laboratory

A mass spectrometer is used to find the relative atomic mass of magnesium. The sample is vaporised and ionised by a beam of high-energy electrons, the positive ions are accelerated and then separated by mass-to-charge ratio in a magnetic field, and the detector records three peaks at m/z = 24, 25 and 26 with relative abundances of 79.0%, 10.0% and 11.0%. The weighted mean is (24 x 79.0) + (25 x 10.0) + (26 x 11.0) divided by 100, which gives a relative atomic mass of 24.3.

In an industrial plant

Uranium-235 has to be separated from the much more abundant uranium-238 before it can be used as a nuclear fuel, and the two isotopes are chemically identical, so no chemical method can do it. The uranium is converted into uranium hexafluoride and the gas is spun in high-speed centrifuges, or allowed to diffuse through porous barriers, because the molecules containing U-235 are slightly lighter and therefore travel or diffuse slightly faster. The separation works only because isotopes differ in mass, which is exactly the physical property that distinguishes them.

In a hospital

Magnetic resonance imaging builds pictures of the soft tissue inside a patient by probing the nuclei of hydrogen-1 atoms in water and fat. A hydrogen-1 atom is the simplest possible nucleus: a single proton carrying one unit of positive charge, with one electron in a 1s orbital around it. The technique depends on the magnetic behaviour of that proton, and it is the same proton that decides that hydrogen is in Group 1, so the physics of the nucleus and the chemistry of the electron are being used side by side.

In the atmosphere

The relative amounts of the oxygen isotopes in carbon dioxide and in water vapour depend on temperature, because molecules containing the heavier isotope oxygen-18 evaporate and condense slightly differently from those containing oxygen-16. Air bubbles trapped in ice sheets preserve these ratios, and by measuring the oxygen-18 to oxygen-16 ratio down a core, scientists reconstruct how the temperature of the atmosphere changed over hundreds of thousands of years. The two isotopes are chemically indistinguishable, but their physical behaviour differs because their masses differ.

Flashcards

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Q1Give the relative charge and the relative mass of a proton, a neutron and an electron.
Proton: charge +1, mass 1. Neutron: charge 0, mass 1. Electron: charge -1, mass about 1/1840 of a proton.
Q2What is the difference between the atomic number and the mass number of an atom?
The atomic (proton) number is the number of protons in the nucleus and identifies the element; the mass (nucleon) number is the total number of protons and neutrons, so the number of neutrons is mass number minus atomic number.
Q3How do you work out the number of electrons in an ion?
Start from the atomic number Z. A neutral atom has Z electrons, an ion with a charge of n+ has Z - n electrons, and an ion with a charge of n- has Z + n electrons. The number of protons and neutrons never changes.
Q4Define the term isotope.
Atoms of the same element that have the same number of protons but different numbers of neutrons, so they have the same atomic number and different mass numbers.
Q5Why do isotopes of the same element have identical chemical properties?
Chemistry is controlled by the number and arrangement of the electrons, and isotopes of the same element have the same number of electrons in exactly the same configuration. Only the number of neutrons in the nucleus differs.
Q6Describe the shapes of s and p orbitals.
An s orbital is spherical with the nucleus at its centre; a 2s orbital also has an inner sphere of electron density. A p orbital is dumbbell shaped, with two lobes on opposite sides of the nucleus and a node of zero electron density at the nucleus.
Q7How many orbitals does each type of sub-shell contain, and how many electrons does each hold?
An s sub-shell has 1 orbital and holds 2 electrons, a p sub-shell has 3 orbitals and holds 6, and a d sub-shell has 5 orbitals and holds 10. Each individual orbital holds a maximum of two electrons with opposite spins.
Q8Give the order of increasing energy of the sub-shells up to 4p.
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p. The 4s sub-shell is lower in energy than 3d because 3d is shielded by the filled 3s and 3p sub-shells.
Q9Write the full and the shorthand electronic configuration of an iron atom.
Full: 1s2 2s2 2p6 3s2 3p6 3d6 4s2. Shorthand: [Ar] 3d6 4s2. In boxes, 3d shows one pair and four unpaired electrons and 4s shows a pair.
Q10Why is the configuration of chromium [Ar] 3d5 4s1 and not [Ar] 3d4 4s2?
A half-filled d sub-shell has a lower energy than the alternatives, because the five electrons occupy separate d orbitals and keep further apart, so inter-electron repulsion is reduced. Copper is [Ar] 3d10 4s1 for the same reason.
Q11Define the first ionisation energy of an element.
The energy required to remove one electron from each atom in one mole of gaseous atoms to form one mole of gaseous 1+ ions, measured in kJ mol-1.
Q12Name the factors that decide the size of an ionisation energy.
Nuclear charge (more protons, stronger attraction), distance of the electron from the nucleus (further away, weaker attraction), shielding by inner shells and sub-shells (reduces the effective nuclear charge), and spin-pair repulsion when the electron removed shares an orbital with another.
Q13Why does atomic radius decrease across a period but increase down a group?
Across a period the nuclear charge increases while the outer electrons stay in the same shell and shielding is roughly constant, so the shell is pulled in more tightly. Down a group an extra shell is added and the outer electron is further from the nucleus and better shielded, so the atom gets larger.
Q14What does a large jump between successive ionisation energies tell you?
That the electron removed after the jump comes from a shell closer to the nucleus. The number of electrons removed before the jump is the number of electrons in the outer shell, which gives the group of a main-group element.
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Exam-style questions

9 questions, 29 marks. Write your answer, then reveal the mark scheme and tick each point you actually made. Answering honestly here is what makes the rest of the site useful.

DefineAO11 mark
Define the term first ionisation energy of an element.

Mark scheme — tick each point you actually made

Examiner tip: Three details carry the mark together: one mole, gaseous atoms and 1+ ions. An answer that says 'the energy to remove an electron from an atom' loses it.
DeduceAO22 marks
Iron has atomic number 26 and one of its isotopes has mass number 56. Deduce the number of protons, neutrons and electrons in a 56Fe3+ ion. Show your working.

Mark scheme — tick each point you actually made

Examiner tip: The mass number is not affected by the charge, because only electrons are gained or lost. Always subtract the charge for a positive ion and add it for a negative ion.
DescribeAO13 marks
A beam containing protons, neutrons and electrons, all travelling at the same velocity, passes between two charged plates. Describe what happens to each type of particle, and explain why the deflection of a proton is smaller than the deflection of an electron.

Mark scheme — tick each point you actually made

Examiner tip: Name the plate for each charged particle. Neutrons must be described as undeflected, so never leave the neutron out of a three-particle answer.
ExplainAO23 marks
Chlorine has two isotopes, Cl-35 and Cl-37. Explain why the two isotopes have identical chemical properties but different physical properties, including mass and density.

Mark scheme — tick each point you actually made

Examiner tip: Answer both halves of the question. 'Same number of protons' alone does not explain the chemistry, and the physical difference must be linked to the different number of neutrons and hence the different mass.
CalculateAO24 marks
A sample of magnesium is analysed in a mass spectrometer and gives three peaks, at m/z = 24, 25 and 26, with relative abundances of 79.0%, 10.0% and 11.0%. Calculate the relative atomic mass of the magnesium in the sample and give your answer to three significant figures.

Mark scheme — tick each point you actually made

Examiner tip: Show the weighted expression before you calculate. Dividing the sum of the isotope masses by the number of isotopes gives 25, and taking only the tallest peak gives 24; both are wrong.
DeduceAO24 marks
An element has successive ionisation energies of 738, 1451, 7733, 10540 and 13630 kJ mol-1. Deduce the number of electrons in the outer shell of the element, the group it belongs to, and its full electronic configuration. Explain how the data give your answer.

Mark scheme — tick each point you actually made

Examiner tip: Divide each value by the one before it rather than comparing bare numbers, and count the electrons removed before the first big jump, because that count is the number of outer electrons and hence the group.
ExplainAO23 marks
The first ionisation energy of aluminium (577 kJ mol-1) is lower than that of magnesium (738 kJ mol-1), even though aluminium has the larger nuclear charge. Explain this difference.

Mark scheme — tick each point you actually made

Examiner tip: The answer is about sub-shell energy and shielding, not about size. Aluminium is in fact the smaller atom, because its extra proton pulls the same shell and the 3p electrons in more tightly.
ExplainAO26 marks
Iron has atomic number 26. (a) Write the full electronic configuration and the shorthand electronic configuration of an iron atom. (b) Give the electrons in boxes notation for the outer sub-shells of iron. (c) Explain why the 4s sub-shell is filled before the 3d sub-shell, and state which electrons are lost when iron forms a 2+ ion.

Mark scheme — tick each point you actually made

Examiner tip: The filling order and the order of loss are opposite. The 4s sub-shell fills first, but once the 3d orbitals are occupied they lie lower in energy, so 4s electrons are removed first when a transition element is ionised.
ExplainAO33 marks
A mass spectrometer is used to find the relative abundance of the isotopes present in a sample of an element. Explain why the sample has to be vaporised and then ionised before analysis, and state how ions of different mass are separated and detected.

Mark scheme — tick each point you actually made

Examiner tip: Answer each part separately: vaporising frees the atoms, ionising makes them respond to the fields, and the separation depends on mass-to-charge ratio rather than on mass alone.

Exam technique for this topic

  • Learn the definition of first ionisation energy exactly: the energy required to remove one electron from each atom in one mole of gaseous atoms to form one mole of gaseous 1+ ions. Leave out 'gaseous' or 'one mole' and the mark is lost, and remember the units, kJ mol-1.
  • Every ionisation energy explanation must name its factors: nuclear charge, distance from the nucleus and shielding, plus spin-pair repulsion when the electron removed is one of a pair in the same orbital. Answers that only say 'the atom is bigger' or 'there are more protons' score nothing.
  • Write electron configurations in the filling order 1s 2s 2p 3s 3p 4s 3d 4p, then check that the electrons add up to the number of electrons in the atom or ion. If the question asks for the shorthand form, start with the noble gas in square brackets.
  • In successive ionisation energy data, divide each value by the one before it. A step of about five times or more marks the first electron removed from a new shell, so the number of electrons removed before that jump is the number of outer electrons and gives the group.
  • Never confuse the mass number with the relative atomic mass. The mass number of one atom is a whole number counting protons and neutrons, while relative atomic mass is a weighted mean of all the isotopes of the element and has no units.
  • When you compare isotopes, answer the chemistry and the physics separately: identical electron configurations explain the identical chemistry, and the different number of neutrons explains the difference in mass and density.

Why students lose marks here

A student wroteA student wrote: 'The relative atomic mass of magnesium is 24, because the tallest peak in its mass spectrum is at m/z = 24.'
Why it loses marksRelative atomic mass is the weighted mean of the masses of all the isotopes present, not the mass of the most abundant one. In a sample of magnesium about 21% of the atoms are Mg-25 or Mg-26, so using the tallest peak alone ignores a fifth of the atoms and gives an answer that is too low.
The answer that scoresMultiply the mass of each isotope by its relative abundance, add the products and divide by 100: (24 x 79.0) + (25 x 10.0) + (26 x 11.0) = 1896 + 250 + 286 = 2432, and 2432 / 100 = 24.3. The relative atomic mass has no units, because it is a mass compared with one twelfth of the mass of an atom of carbon-12.
A mass spectrometer in use in a laboratory: the sample is vaporised and ionised, the positive ions are accelerated and then separated by mass-to-charge ratio in a magnetic field, and the detector records the relative abundance of each isotope as a separate peak.
A student wroteA student wrote: 'First ionisation energy increases down a group, because the atoms get bigger and hold more electrons.'
Why it loses marksGetting bigger works against the trend, not with it. Down a group the outer electron occupies a shell with a larger principal quantum number, so it is further from the nucleus, and the extra inner shells shield it from the nuclear charge. Both effects weaken the attraction between the nucleus and the outer electron, and they outweigh the extra protons.
The answer that scoresDown a group the first ionisation energy decreases. The outer electron is in a shell further from the nucleus and is shielded by more inner shells, so less energy is needed to remove it: the value falls from 520 kJ mol-1 for lithium to 496 for sodium and 419 for potassium. The number of electrons in the atom is irrelevant; what matters is how strongly the outer electron is held.
A student wroteA student wrote: 'The 4s sub-shell is filled before the 3d sub-shell, so the electronic configuration of chromium is [Ar] 4s2 3d4.'
Why it loses marksThe filling order tells you which sub-shell is occupied first when the atom is built up, not the final arrangement of the electrons. A half-filled 3d sub-shell with a single 4s electron is lower in energy than 3d4 4s2, because five electrons in five separate d orbitals keep further apart and there is less electron-electron repulsion.
The answer that scoresChromium is [Ar] 3d5 4s1 and copper is [Ar] 3d10 4s1, because the half-filled and completely filled d sub-shells have a lower energy than the alternatives. Because 3d lies below 4s in energy once it is occupied, a transition element loses its 4s electrons first when it forms a positive ion: iron is [Ar] 3d6 4s2, Fe2+ is [Ar] 3d6 and Fe3+ is [Ar] 3d5.
A student wroteA student wrote: 'A 2p orbital can hold six electrons, because a p sub-shell takes six electrons.'
Why it loses marksThe student has confused the sub-shell with the orbital. A p sub-shell is made up of three separate p orbitals, each lying along a different axis, and every orbital holds a maximum of two electrons with opposite spins. Six electrons therefore occupy the whole sub-shell, not one orbital.
The answer that scoresA 2p sub-shell contains three orbitals, labelled 2px, 2py and 2pz, and each holds a maximum of two electrons, so the sub-shell holds six electrons in total. An s sub-shell holds two electrons in its single orbital and a d sub-shell holds ten in its five orbitals. In electrons in boxes notation a 2p sub-shell is drawn as three boxes, filled singly with parallel spins before any box is given a second electron.

Where this fits in AS & A Level Chemistry

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