AS & A Level Biology
A student wrote · Cell structureA student wrote: 'A light microscope can resolve ribosomes and the two membranes of the nuclear envelope, because when I change to the x40 objective the specimen is magnified 400 times.'
Why it loses marksMagnification and resolution are different things, and this answer runs them together. The wavelength of light, about 400-700 nm, limits a light microscope to a resolution of about 0.2 µm, and a ribosome is only about 25 nm across, so no amount of magnification will separate it from its surroundings. Increasing magnification beyond the resolution limit is empty magnification: the image becomes larger and blurrier, but no new detail appears.
The answer that scoresA light microscope resolves to about 0.2 µm, so it shows the nucleus, the cell wall, and at best the chloroplasts and mitochondria as shapes, but it cannot resolve ribosomes or the two membranes of the nuclear envelope. Because resolution depends on the wavelength of the radiation used, an electron microscope is needed: electrons have a far shorter wavelength than light, and a transmission electron microscope resolves to about 0.5 nm, which is enough to see ribosomes and the detail of membranes.
Revise this topicCell structure
A student wrote · Cell structureA student wrote: 'An electron micrograph of a chloroplast is printed at a magnification of x5000. The chloroplast measures 40 mm across on the print, so its actual width is 40 x 5000 = 200000 µm.'
Why it loses marksThe magnification equation rearranges to actual size = image size / magnification, so the image size must be divided by the magnification, not multiplied by it. The answer is also left in millimetres without being converted, and 200000 µm is 20 cm, which is far larger than any cell, let alone a chloroplast. A quick sanity check on the size would have shown the answer was impossible.
The answer that scoresactual size = image size / magnification = 40 mm / 5000 = 0.008 mm. Converting to micrometres: 0.008 mm x 1000 = 8 µm. A chloroplast about 8 µm across is a realistic size, and writing the unit with the value is part of the answer.
Revise this topicCell structure
A student wrote · Cell structureA student wrote: 'Plant cells do not contain mitochondria, because a plant makes its own glucose by photosynthesis and does not need to respire.'
Why it loses marksPhotosynthesis produces carbohydrate, but the cell still has to break that carbohydrate down in respiration to make ATP, and photosynthesis happens only in the light. Every living plant cell respires all the time, in darkness as well as in light, so every plant cell contains mitochondria. The misconception comes from treating chloroplasts and mitochondria as alternatives rather than as processes that run alongside each other.
The answer that scoresPlant cells contain mitochondria, just as animal cells do, and a plant cell that photosynthesises also contains chloroplasts. Chloroplasts make carbohydrate and mitochondria release energy from it as ATP, and the cell needs ATP for active transport, protein synthesis, the movement of vesicles and cell division. A cell that works hard, such as a root hair cell taking up mineral ions by active transport, is packed with mitochondria even though it has no chloroplasts at all.
Revise this topicCell structure
A student wrote · Cell structureA student wrote: 'A virus is the smallest kind of bacterium. It has a cell wall and ribosomes but no nucleus, so it cannot be killed by antibiotics.'
Why it loses marksA virus is not a cell at all, so it has no cell wall, no ribosomes, no cytoplasm and no cell surface membrane of its own, and it is far smaller than any bacterium. It is a nucleic acid core, either DNA or RNA but never both, inside a protein capsid, and some viruses have an outer phospholipid envelope. Antibiotics such as penicillin act on peptidoglycan walls and 70S ribosomes, so they have nothing to act on in a virus.
The answer that scoresA virus is a non-cellular structure made of a nucleic acid core surrounded by a protein capsid, and some viruses also have an outer envelope made of phospholipid. It has no cytoplasm, no ribosomes and no way of making ATP, so it cannot reproduce on its own and must use the ribosomes, ATP and enzymes of a host cell. Bacteria, by contrast, are prokaryotic cells with a peptidoglycan wall, circular DNA and 70S ribosomes, which is why antibiotics that target the wall or the ribosome work against bacteria but not against viruses.
Revise this topicCell structure
A student wrote · Biological moleculesA student wrote: 'Sucrose gives a negative result with Benedict's solution, so sucrose is not a sugar.'
Why it loses marksThe Benedict's test does not detect carbohydrates in general; it detects sugars that have a free reducing group. Sucrose contains two monosaccharides and is very much a sugar - it simply cannot reduce copper(II) ions.
The answer that scoresSucrose is a disaccharide of glucose and fructose joined by a glycosidic bond between carbon 1 of the glucose and carbon 2 of the fructose, so neither ring keeps a free reducing group. It is therefore a non-reducing sugar and gives a negative Benedict's result. Heating it with dilute hydrochloric acid hydrolyses the glycosidic bond, and after the acid has been neutralised with sodium hydrogencarbonate a Benedict's test on the products gives a brick-red precipitate, which shows that reducing sugars have been released.
Revise this topicBiological molecules
A student wrote · Biological moleculesA student wrote: 'To test a solution for a non-reducing sugar, add dilute hydrochloric acid, then add Benedict's solution and heat the mixture.'
Why it loses marksThe acid is needed to hydrolyse the glycosidic bond, but it must be neutralised before the Benedict's test. Benedict's solution relies on copper(II) ions being reduced in alkaline conditions, and in acid conditions the test stays blue whatever the sugar content, so the student would report a false negative.
The answer that scoresAdd dilute hydrochloric acid and heat the solution in a water bath to hydrolyse the glycosidic bonds and release the monosaccharides. Then add sodium hydrogencarbonate a little at a time until the solution stops fizzing and pH paper shows it is no longer acidic. Only then add Benedict's solution and heat in a water bath: a brick-red precipitate in this second test shows that reducing sugar has been released, so the original solution contained a non-reducing sugar.
Revise this topicBiological molecules
A student wrote · Biological moleculesA student wrote: 'Starch and cellulose are both polymers of glucose, so they have the same structure and both are digested by amylase.'
Why it loses marksStarch is built from alpha-glucose and cellulose from beta-glucose. The difference in the position of one -OH group makes alternate beta-glucose molecules in the chain turn through 180 degrees, so cellulose chains are straight and hydrogen bonded into microfibrils, while starch chains coil and branch. Amylase has an active site complementary to alpha-1,4 bonds and has no effect on beta-1,4 bonds.
The answer that scoresStarch is made of alpha-glucose joined by alpha-1,4 bonds, with alpha-1,6 branches in amylopectin, so the coils are compact and the branched ends allow rapid hydrolysis by amylase - good for storage. Cellulose is made of beta-glucose joined by beta-1,4 bonds, with alternate molecules inverted, so the chains are straight and are held in bundles by hydrogen bonds between their -OH groups. Those microfibrils have a high tensile strength and are resistant to hydrolysis, which is exactly what a plant cell wall needs. Humans digest neither beta-1,4 bonds nor the cellulose they form, because they have no cellulase.
Revise this topicBiological molecules
A student wrote · Biological moleculesA student wrote: 'Boiling a protein solution denatures the protein because the heat breaks the peptide bonds in the chain.'
Why it loses marksHeat breaks the weak interactions that hold the folded shape - hydrogen bonds, ionic bonds and hydrophobic interactions - not the covalent peptide bonds. Peptide bonds are only broken by hydrolysis, which needs a protease or prolonged boiling with acid or alkali.
The answer that scoresThe primary structure is held by peptide bonds, which are strong covalent bonds and survive boiling, so the sequence of amino acids is unchanged. What heat destroys is the tertiary structure: the hydrogen bonds, ionic bonds and hydrophobic interactions between R groups break, so the chain unfolds and the precise shape of the molecule is lost. Any protein that depends on that shape, such as an enzyme with an active site or an antibody with a binding site, stops working. Disulfide bonds are also covalent and usually survive, which is why the primary structure can be recovered while the function cannot.
Revise this topicBiological molecules
A student wrote · EnzymesA student wrote: 'The enzyme stopped working at 10 °C because it had been denatured by the cold.'
Why it loses marksA low temperature does not break the bonds that hold the tertiary structure, so it cannot denature an enzyme. The reaction is slow because the enzyme and substrate molecules have little kinetic energy, so they collide less often and with less energy and fewer enzyme-substrate complexes form. The effect is completely reversible.
The answer that scoresBelow the optimum temperature the enzyme is inactivated but not denatured: the active site keeps its shape and full activity returns when the mixture is warmed. Only a temperature above the optimum gives enough kinetic energy to break the hydrogen bonds and ionic bonds holding the tertiary structure. That changes the shape of the active site so that it is no longer complementary to the substrate, and the enzyme is permanently denatured.
Revise this topicEnzymes
A student wrote · EnzymesA student wrote: 'I measured the rate of reaction by taking the absorbance reading from the colorimeter after five minutes and recording that value as the rate.'
Why it loses marksA colorimeter measures absorbance, which is proportional to the concentration of the coloured substance in the tube. A rate is a change in amount divided by the time taken, so a single reading can never be a rate, and by five minutes the reaction may already have slowed because substrate has been used up, so the value is far too low.
The answer that scoresTake absorbance readings at fixed time intervals from the moment the enzyme is added, plot absorbance against time, and take the rate of reaction as the gradient of the initial straight part of the curve, where the reaction is fastest. For an iodine end point the rate is 1 / time taken for the starch to disappear. Repeat each experiment and take a mean so that the gradient is reliable.
Revise this topicEnzymes
A student wrote · EnzymesA student wrote: 'A competitive inhibitor lowers Vmax, because it blocks the active site so that the substrate cannot get in, and its effect cannot be overcome.'
Why it loses marksBoth parts are wrong. A competitive inhibitor competes with the substrate for the same active site, so raising the substrate concentration overcomes it and the reaction still reaches the original Vmax. What changes is Km, which appears to rise because a higher substrate concentration is now needed to reach half of the maximum rate.
The answer that scoresA competitive inhibitor binds to the active site and raises the apparent Km, but at a high enough substrate concentration the substrate out-competes the inhibitor and the reaction still reaches the original Vmax. A non-competitive inhibitor is the one that lowers Vmax, because it binds away from the active site and changes the shape of the enzyme so that the active site is no longer complementary; adding more substrate does not overcome it, and Km is unchanged.
Revise this topicEnzymes
A student wrote · EnzymesA student wrote: 'Immobilising an enzyme in alginate beads makes it work faster, because the enzyme is held in one place and stays close to the substrate.'
Why it loses marksImmobilisation usually makes an enzyme work more slowly. Trapped enzyme molecules cannot move freely to meet the substrate and the substrate must diffuse into the gel to reach the active sites, so fewer collisions occur, and some active sites are partly blocked by the alginate. The advantages of immobilisation concern separation, reuse and stability, not a faster rate.
The answer that scoresThe same mass of immobilised enzyme normally breaks down less substrate in a given time than the free enzyme, for the reasons above. Immobilisation is still worthwhile because the enzyme can be recovered and reused many times, it does not contaminate the product so no purification step is needed to remove it, it is more stable to heat and to changes in pH so the reaction can be run at a higher temperature, and the process can be run continuously in a packed column.
Revise this topicEnzymes
A student wrote · Cell membranes and transportA student wrote: 'Osmosis is the movement of water from a concentrated sugar solution to a dilute sugar solution, because water always moves towards the water.'
Why it loses marksWater potential is not solute concentration, and the direction has been reversed. Adding sugar makes the water potential more negative, so the concentrated sugar solution has the lower water potential. Water moves from the dilute solution, which has the higher water potential, to the concentrated solution, which has the lower water potential.
The answer that scoresOsmosis is the net movement of water molecules from a region of higher water potential to a region of lower water potential, through a partially permeable membrane. A dilute sugar solution has the higher (less negative) water potential and a concentrated sugar solution has the lower (more negative) water potential, so water moves from the dilute solution into the concentrated one, down the water potential gradient.
Revise this topicCell membranes and transport
A student wrote · Cell membranes and transportA student wrote: 'Facilitated diffusion and active transport both use carrier proteins and both use ATP, so a cell short of ATP cannot carry out either process.'
Why it loses marksFacilitated diffusion is passive and uses no ATP at all. Only active transport hydrolyses ATP to move a substance against its concentration gradient. The two processes do share carrier proteins, but that is where the similarity ends.
The answer that scoresFacilitated diffusion moves a substance down its concentration gradient through a channel protein or on a carrier protein and needs no ATP, so a cell short of ATP can still carry it out. Active transport uses a carrier protein that hydrolyses ATP to move a substance against its concentration gradient, so it stops when ATP is unavailable, for example when a root is treated with a respiratory inhibitor or the soil becomes waterlogged.
Revise this topicCell membranes and transport
A student wrote · Cell membranes and transportA student wrote: 'A 3 cm cube of agar has a larger surface area to volume ratio than a 1 cm cube, because its surface area is larger.'
Why it loses marksThe ratio is what matters, not the surface area on its own. The 3 cm cube does have the larger surface area, 54 cm2 against 6 cm2, but its volume is 27 cm3 against 1 cm3, so its ratio is 2:1 while the small cube has 6:1. Surface area increases as the square of the length while the volume increases as the cube, so the ratio always falls as the object gets bigger.
The answer that scoresThe 1 cm cube has the larger surface area to volume ratio. Its surface area is 6 x 1 x 1 = 6 cm2 and its volume is 1 cm3, giving 6:1. The 3 cm cube has a surface area of 6 x 3 x 3 = 54 cm2 and a volume of 27 cm3, giving 2:1. In the agar experiment the 1 cm cube changes colour first, because the acid reaches its centre over a shorter distance and every part of it is close to the surface.
Revise this topicCell membranes and transport
A student wrote · Cell membranes and transportA student wrote: 'The potato cylinders in 0.6 mol/dm3 sucrose lost mass, so water must have moved out of the sucrose solution into the cylinders.'
Why it loses marksA loss in mass means water left the tissue, so the direction has been reversed. The 0.6 mol/dm3 sucrose solution has a more negative water potential than the potato cell contents, so water moves out of the cells into the solution by osmosis, and the cylinders lose mass. Sucrose cannot cross the partially permeable membrane, and that is exactly why the solution outside the cells has the lower water potential.
The answer that scoresWater moved out of the potato cells by osmosis, from the higher water potential of the cell contents to the lower water potential of the 0.6 mol/dm3 sucrose solution, so the cylinders lost mass. The sucrose molecules are too large to cross the partially permeable cell surface membrane, so they stay outside the cells and lower the water potential there. If the cylinders are not blotted dry before they are reweighed, surface water adds mass and makes the loss look smaller than it really is.
Revise this topicCell membranes and transport
A student wrote · The mitotic cell cycleA student wrote: 'Interphase is the resting phase of the cell cycle, when the cell does not carry out any activity before it divides.'
Why it loses marksInterphase is not a rest. It is the metabolically busiest part of the cycle: the cell grows and synthesises proteins and organelles in G1, replicates all its DNA in S phase and prepares for division in G2. Describing it as resting also hides the fact that interphase is the longest part of the cycle, which is why most cells seen in a photomicrograph are in it.
The answer that scoresInterphase is the part of the cell cycle between divisions, and it is when the cell carries out its normal functions and prepares to divide. In G1 the cell grows and synthesises proteins and organelles, in S phase the DNA is replicated so that every chromosome consists of two sister chromatids, and in G2 the cell grows further and makes the proteins needed for the spindle. Interphase is much longer than mitosis, so most cells in a dividing tissue are in interphase at any moment.
Revise this topicThe mitotic cell cycle
A student wrote · The mitotic cell cycleA student wrote: 'In the photomicrograph of the onion root tip, the cells whose chromosomes are lined up along the middle are in anaphase, and most of the cells in the field of view are in anaphase.'
Why it loses marksChromosomes lined up along the middle of the cell is the definition of metaphase, not anaphase; anaphase is the stage in which the centromeres have split and the chromatids are moving to the poles. The second half of the answer is wrong for a different reason: the stage seen in the greatest number of cells is the stage that lasts longest, and that is interphase, not anaphase. A single field of view is also a poor sample.
The answer that scoresCells with their chromosomes arranged along the equator of the cell are in metaphase, and cells with two sets of chromosomes moving apart towards the poles are in anaphase. In a root tip squash most of the cells are in interphase, because interphase is much the longest part of the cell cycle, and only a small proportion are in prophase, metaphase, anaphase or telophase. Score the proportions by counting several fields of view and dividing the number of cells in mitosis by the total number of cells counted.
Revise this topicThe mitotic cell cycle
A student wrote · The mitotic cell cycleA student wrote: 'A plant cell divides its cytoplasm in the same way as an animal cell, by forming a cleavage furrow that pinches the cell in two.'
Why it loses marksA plant cell has a rigid cellulose cell wall, so the cell surface membrane cannot be drawn inwards to form a furrow. The mark is for the mechanism that plant cells actually use, and for the reason they cannot use the animal one.
The answer that scoresIn an animal cell, cytokinesis happens when a ring of microfilaments inside the cell surface membrane contracts and forms a cleavage furrow, drawing the membrane inwards until the cell is pinched in two. In a plant cell, vesicles from the Golgi apparatus carry wall material to the equator and fuse to form a cell plate, which grows outwards to meet the existing cell wall. The plate becomes the middle lamella and a new cell surface membrane and cellulose cell wall are laid down on each side of it, so each daughter cell has its own wall.
Revise this topicThe mitotic cell cycle
A student wrote · The mitotic cell cycleA student wrote: 'A benign tumour is just a small malignant tumour, and once it grows large enough it starts to spread through the blood.'
Why it loses marksBenign and malignant describe the behaviour of a tumour, not its size. A benign tumour does not invade the tissue around it and does not metastasise, however large it becomes, whereas a malignant tumour invades and its cells can spread. Confusing the two loses the marks for both the nature of uncontrolled division and the meaning of metastasis.
The answer that scoresBoth benign and malignant tumours are masses of cells formed by uncontrolled cell division, but they behave differently. A benign tumour stays as a compact, encapsulated mass and does not invade the surrounding tissue or spread elsewhere, although it can cause problems by pressing on other structures. A malignant tumour invades and destroys the tissue around it, and its cells break away and travel in the blood or lymph to form secondary tumours, which is metastasis. The loss of control in both cases begins with a mutation in a gene that regulates the cell cycle, such as a proto-oncogene becoming an oncogene or the loss of a tumour suppressor gene such as TP53.
Revise this topicThe mitotic cell cycle
A student wrote · Nucleic acids and protein synthesisA student wrote: 'On the lagging strand DNA polymerase works in the 3' to 5' direction, so both new strands can be made at the same time as the replication fork opens.'
Why it loses marksDNA polymerase can only add a nucleotide to a free 3' end, so a new strand can only be built in the 5' to 3' direction. The lagging strand template is antiparallel to the leading strand template, so the enzyme has to work away from the replication fork and cannot produce a continuous strand.
The answer that scoresThe leading strand is built continuously in the 5' to 3' direction, in the same direction as the fork is opening. DNA polymerase can only add nucleotides to a free 3' end, so on the lagging strand it must add nucleotides in short lengths in the 5' to 3' direction away from the fork, restarting each time more template is exposed. The short fragments are then joined into one continuous strand by DNA ligase, which forms the phosphodiester bonds between them.
Revise this topicNucleic acids and protein synthesis
A student wrote · Nucleic acids and protein synthesisA student wrote: 'After the bacteria had been grown in nitrogen-15 and then in nitrogen-14 for one generation, the DNA separated into two bands, one heavy and one light, so replication is conservative.'
Why it loses marksThe observation after one generation is a single band of intermediate density, not two bands. Two bands, one heavy and one light, would be the conservative result, and the two bands seen after two generations are one intermediate and one light. The student has remembered the second generation result and attached it to the wrong model.
The answer that scoresAfter one generation in nitrogen-14 there is a single band of intermediate density, because every DNA molecule contains one strand of the original heavy DNA and one newly synthesised light strand, which is semi-conservative replication. After two generations there are two bands, one intermediate and one light, and the presence of the light band shows that the strands made in the second generation were copied from light templates as well as heavy ones.
Revise this topicNucleic acids and protein synthesis
A student wrote · Nucleic acids and protein synthesisA student wrote: 'The change of glutamic acid to valine in sickle cell disease cannot be caused by a single base substitution, because the genetic code is degenerate and a change in one base never changes the amino acid the codon codes for.'
Why it loses marksDegeneracy means that many substitutions are silent, not that all of them are. Some codons are altered into a triplet that codes for a different amino acid, and others are altered into a stop codon that shortens the polypeptide.
The answer that scoresThe code is degenerate because there are 64 possible triplets and only 20 amino acids, so some substitutions do not change the amino acid that is coded for. In the HBB gene the substitution changes the coding triplet from GAG to GTG, and although both triplets start with G, the third base G codes for glutamic acid while GUG codes for valine. The altered codon gives the beta chain a different amino acid, so the haemoglobin molecules stick together and the shape of the red cell changes.
Revise this topicNucleic acids and protein synthesis
A student wrote · Nucleic acids and protein synthesisA student wrote: 'If one base is deleted from near the start of a gene, only the codon containing that base is changed, so one amino acid is missing from the polypeptide.'
Why it loses marksThis confuses a deletion of one base with a deletion of a whole triplet. Removing one base shifts the reading frame at that point, so every codon after the mutation is read from the wrong starting position.
The answer that scoresThe three bases after the deletion are read as a new triplet, so the reading frame is shifted from the mutation onwards. Nearly every amino acid after that point is different from the one the gene specified, and a stop codon is usually reached prematurely, so the polypeptide is both wrong in sequence and much shorter than normal. A deletion of three bases removes one whole amino acid without shifting the frame: the common mutation causing cystic fibrosis deletes three bases of the CFTR gene, so the protein lacks phenylalanine at position 508 and cannot fold correctly.
Revise this topicNucleic acids and protein synthesis
A student wrote · Transport in plantsA student wrote: 'Water evaporates from the waxy cuticle on the outside of the leaf, and the water vapour then diffuses away through the stomata.'
Why it loses marksThe cuticle is the waterproof covering of the epidermis, so very little water evaporates from it; if it were the evaporating surface, a thick cuticle would not reduce water loss. The evaporation happens inside the leaf, from the moist surfaces of the mesophyll cells and their cell walls that line the air spaces.
The answer that scoresTranspiration has two stages. First, water evaporates from the internal surfaces of the leaf: the film of water on the mesophyll cells and the cellulose walls exposed to the air spaces. Second, water vapour diffuses from the air spaces, which are saturated with water vapour, through the open stomata into the drier atmosphere outside, down a water vapour concentration gradient. The waxy cuticle is almost impermeable, which is why nearly all the water leaves through the stomata.
Revise this topicTransport in plants
A student wrote · Transport in plantsA student wrote: 'Water is pushed up the xylem by root pressure, and this is strong enough to raise water to the top of a tall tree.'
Why it loses marksRoot pressure is real but small and it is not the main mechanism. It is produced only while the roots are actively pumping ions into the xylem, it raises water a short distance at most, and it is weakest when the plant is transpiring fastest, which is exactly when water is needed at the top.
The answer that scoresWater is pulled up the xylem by the transpiration pull. Evaporation from the mesophyll cells lowers the water potential in the leaf, so water is drawn out of the xylem and a tension is set up in the column of water inside the vessel. Hydrogen bonding between water molecules (cohesion) transmits that tension down the column without it breaking, and adhesion of the water to the cellulose and lignin of the vessel wall holds the column against the walls and against gravity. Water then enters the root hair cells by osmosis from the soil, keeping the column continuous. Root pressure adds only a small amount, mainly when transpiration is slow, such as at night.
Revise this topicTransport in plants
A student wrote · Transport in plantsA student wrote: 'The Casparian strip blocks the apoplast pathway, so no water can reach the xylem through the endodermis.'
Why it loses marksThe strip does not stop water, it diverts it. Suberin makes the radial and transverse walls of the endodermal cells waterproof, so water travelling in the cell walls cannot continue along the apoplast, but it can and does cross the endodermal cell membrane and continue through the symplast.
The answer that scoresThe Casparian strip of suberin is impermeable to water, so it blocks the apoplast pathway through the endodermal cell walls. Water must therefore enter the cytoplasm of an endodermal cell, crossing its partially permeable cell membrane, and continue through the symplast pathway into the xylem. This makes the endodermis a checkpoint: because a membrane has to be crossed, the root controls which ions and how much water enter the xylem, and the mineral ions that have been actively pumped into the xylem cannot leak back out through the cortex.
Revise this topicTransport in plants
A student wrote · Transport in plantsA student wrote: 'Sucrose is loaded into phloem sieve tubes by diffusion, and the sieve tube elements make the ATP that is needed.'
Why it loses marksLoading is not diffusion: the sucrose concentration inside a sieve tube is higher than in the surrounding cells, so sucrose has to be moved against its concentration gradient, which needs energy. And the mature sieve tube element has lost its nucleus and almost all its organelles, so it cannot make ATP.
The answer that scoresThe companion cell loads the sucrose. It uses ATP from its many mitochondria to drive proton pumps that move hydrogen ions (H+) out of the cell into the apoplast. The H+ then flows back in down its concentration gradient, through a cotransporter protein, and the energy released carries sucrose into the companion cell at the same time, against the sucrose concentration gradient (cotransport). The sucrose then passes through the plasmodesmata into the sieve tube element, lowering its water potential so that water follows by osmosis from the xylem.
Revise this topicTransport in plants
A student wrote · Transport in mammalsA student wrote: 'The wall of the left ventricle is thicker than the wall of the right ventricle because the left ventricle holds a larger volume of blood.'
Why it loses marksThe two ventricles hold roughly the same volume of blood, so the volume is not the reason. Wall thickness is about the pressure that has to be generated, not about the volume contained. The left ventricle has to drive blood all the way around the long systemic circulation, which offers much more resistance, so it needs far more muscle and a higher pressure.
The answer that scoresThe left ventricle pumps blood into the systemic circulation and around the whole body, whereas the right ventricle pumps blood only to the lungs, which are close by. The systemic circulation is much longer and offers much greater resistance to flow, so a much higher pressure is needed and therefore a much thicker layer of cardiac muscle to produce the greater force of contraction. The pressure in the pulmonary circulation is kept low because the walls of the alveoli are extremely thin and a high pressure would force tissue fluid out of the lung capillaries into the alveoli. The atria have the thinnest walls of all because they only push blood a short distance into the ventricle below them.
Revise this topicTransport in mammals
A student wrote · Transport in mammalsA student wrote: 'The atrioventricular valves close because the muscles in the valve contract, and they open again at the start of ventricular systole because the ventricle pulls them open.'
Why it loses marksHeart valves contain no muscle at all. They are passive flaps that open and close only because of the pressure difference across them. The AV valves close at the START of ventricular systole, not at the start of diastole, and they open during diastole when the pressure in the relaxing ventricle falls below the pressure in the atrium.
The answer that scoresValves are passive: each one opens when the pressure on the side it leads to falls below the pressure behind it, and closes when that pressure reverses. At the start of ventricular systole the ventricles contract and the pressure inside them rises above the pressure in the atria, so the AV valves are forced shut, which makes the first heart sound; their chordae tendineae and papillary muscles stop them turning inside out. During diastole the ventricles relax, the pressure inside them falls below the atrial pressure, and the AV valves are pushed open again so that the ventricles refill. The semilunar valves do the same job at the base of the aorta and the pulmonary artery.
Revise this topicTransport in mammals
A student wrote · Transport in mammalsA student wrote: 'Tissue fluid is formed by osmosis at the arterial end of the capillary, and all of it returns to the blood at the venous end.'
Why it loses marksOsmosis moves water only, and it moves it towards a lower water potential, so it cannot push water, glucose, amino acids and ions OUT of a capillary. Tissue fluid is formed by pressure filtration driven by the hydrostatic pressure of the blood. And not all of it does return, which is why a blocked lymph vessel causes swelling.
The answer that scoresAt the arterial end of the capillary the hydrostatic pressure of the blood is higher than the osmotic pull of the plasma proteins, so water, glucose, amino acids, ions and oxygen are forced out through the capillary wall and its pores by pressure filtration, forming tissue fluid. Blood cells and large plasma proteins cannot fit through, so they stay in the capillary. At the venous end the hydrostatic pressure has fallen and the plasma proteins give the blood a lower water potential than the tissue fluid, so water re-enters by osmosis. The fluid that is not returned is collected by lymph capillaries and returned to the blood through the lymphatic system and the subclavian vein.
Revise this topicTransport in mammals
A student wrote · Transport in mammalsA student wrote: 'Carbon dioxide is carried mainly combined with haemoglobin as carbaminohaemoglobin, and the chloride shift happens so that red blood cells can take up carbon dioxide.'
Why it loses marksOnly a small fraction of the carbon dioxide is carried as carbaminohaemoglobin. Most of it travels in the plasma as hydrogencarbonate ions, which are made inside the red blood cell by carbonic anhydrase and then diffuse out. The chloride shift is not about taking up carbon dioxide at all: carbon dioxide enters the cell by diffusing down its concentration gradient.
The answer that scoresA small fraction of the carbon dioxide dissolves in the plasma, a small fraction combines with the amino groups of haemoglobin to form carbaminohaemoglobin, and the great majority is carried in the plasma as hydrogencarbonate ions. Inside the red blood cell, carbonic anhydrase catalyses CO2 + H2O -> H2CO3, which dissociates into H+ and HCO3-. The H+ ions are buffered by haemoglobin, forming haemoglobinic acid, and the hydrogencarbonate diffuses out into the plasma. The chloride shift is the inward movement of chloride ions that accompanies this, and its importance is that it keeps the charge inside the cell balanced so that a large amount of carbon dioxide can be carried as hydrogencarbonate without an electrical gradient stopping the process.
Revise this topicTransport in mammals
A student wrote · Gas exchangeA student wrote: 'When you breathe in, the diaphragm moves down and pushes the air into the lungs.'
Why it loses marksThere is no air in the thorax for the diaphragm to push, and the diaphragm is a sheet of muscle separating the thorax from the abdomen. Contraction of the diaphragm increases the volume of the thorax, which lowers the pressure inside it below atmospheric pressure, and it is that pressure difference, not a push from the muscle, that moves air into the lungs.
The answer that scoresDuring inspiration the diaphragm contracts and flattens and the external intercostal muscles raise the ribs, so the volume of the thorax increases. Because the volume has increased, the pressure inside the thorax and the airways falls below atmospheric pressure, and air flows down that pressure gradient through the trachea and bronchi into the alveoli. In the bell-jar model the same thing happens when the rubber sheet is pulled down: the balloons inflate because the pressure inside the jar has fallen, not because the sheet pushes air into them.
Revise this topicGas exchange
A student wrote · Gas exchangeA student wrote: 'Cartilage is present throughout the gas exchange system, including the walls of the bronchioles and the alveoli, to stop them collapsing.'
Why it loses marksCartilage is found only in the trachea and the bronchi. The bronchioles have smooth muscle in their walls instead, and the alveoli have no cartilage and no muscle at all. Cartilage in an alveolar wall would add thickness to the barrier that gases have to cross, which would slow diffusion instead of helping it.
The answer that scoresCartilage forms C-shaped rings in the trachea and irregular plates in the bronchi, and it holds those airways open against the fall in pressure that occurs during inhalation. The bronchioles have no cartilage; their diameter is controlled by smooth muscle. The alveolar wall is only one squamous cell thick, so that the diffusion distance is kept to a minimum, and the alveoli are prevented from collapsing by surfactant and by the pressure in the pleural cavity, not by cartilage.
Revise this topicGas exchange
A student wrote · Gas exchangeA student drew a plan diagram of a transverse section of the trachea with the cartilage shaded grey, individual epithelial cells drawn in with their nuclei, and the names of the tissues written as short descriptions such as 'this cartilage stops the tube collapsing'.
Why it loses marksA plan diagram shows the outlines of the tissue layers and nothing else. Shading and individual cells are not drawn, because a plan is not a copy of what the slide looks like but a diagram of the layers. Label lines must give the name of a structure, not describe its function, and they must not cross or end in arrowheads.
The answer that scoresThe diagram should be drawn with a sharp pencil in single, continuous, unbroken lines showing the boundaries between the layers, in proportion and filling the space available, with no shading, no colour and no individual cells. Each label line should touch the structure it names and carry only that name, such as 'cartilage', 'ciliated epithelium' or 'smooth muscle', and the drawing should carry a title such as 'transverse section of the wall of the trachea'.
Revise this topicGas exchange
A student wrote · Gas exchangeA student wrote: 'Oxygen is actively pumped from the alveolar air into the blood, because the concentration of oxygen in the blood is higher than in the air.'
Why it loses marksTwo errors in one sentence. The movement is by diffusion, not by any pump, so it needs no energy from the lungs; and the concentration of oxygen in the blood arriving at the lungs is lower than in the alveolar air, not higher. Stating the gradient the wrong way round removes the reason why the gas moves at all.
The answer that scoresOxygen diffuses from the alveolar air into the blood because the concentration of oxygen in the alveolar air is higher than in the blood arriving in the pulmonary capillaries, which has just returned from the respiring tissues. Ventilation keeps the oxygen concentration in the alveolar air high and blood flow carries the oxygen away, so the difference in concentration is maintained. Because the alveolar wall and the capillary wall are each one cell thick, the distance is short and the diffusion is very rapid.
Revise this topicGas exchange
A student wrote · Infectious diseasesA student wrote: 'HIV is a pathogen, so an HIV-positive patient can be given antibiotics to stop the virus multiplying, and a patient with TB can be given the same drugs.'
Why it loses marksThe argument is right only for the bacterium. Antibiotics act on structures and processes that bacteria have and human cells lack, such as the peptidoglycan cell wall and the transpeptidase enzyme that cross-links it. HIV has no cell wall, no peptidoglycan, no ribosomes of its own and no metabolism of its own, because it uses the host cell's machinery, so there is no target for an antibiotic to attack.
The answer that scoresAntibiotics work on bacteria, so they are effective against Mycobacterium tuberculosis, which has a peptidoglycan cell wall that penicillin-type drugs can disrupt. They have no effect on HIV, which is a retrovirus: with no cell wall, no ribosomes and no enzymes of its own, it offers no target. HIV is treated with antiretroviral drugs such as reverse transcriptase inhibitors, which block an enzyme the virus brings with it and the human cell does not have.
Revise this topicInfectious diseases
A student wrote · Infectious diseasesA student wrote: 'Malaria is caused by a virus that is spread when a mosquito bites a person, so malaria passes directly from one person to another through the mosquito, just like a dirty needle.'
Why it loses marksTwo errors. Plasmodium is a protoctist, not a virus, and the mosquito is a vector rather than a contaminated needle. Part of the parasite's life cycle, including sexual reproduction, happens inside the mosquito, so the mosquito is a host as well as a carrier. Malaria is not passed directly from person to person at all.
The answer that scoresMalaria is caused by protoctists of the genus Plasmodium, such as Plasmodium falciparum, and is transmitted by the bite of an infected female Anopheles mosquito. The mosquito picks up gametocytes when it feeds on an infected person; sexual reproduction takes place in the mosquito gut and the parasite reaches the salivary glands as sporozoites. When the mosquito feeds again, sporozoites are injected into the blood of a new host, where the parasite multiplies in the liver and then inside red blood cells.
Revise this topicInfectious diseases
A student wrote · Infectious diseasesA student wrote: 'Cholera is caused by dirty water, so the way to control it is to give antibiotics to everyone living in the area.'
Why it loses marksCholera is caused by the bacterium Vibrio cholerae, and contaminated water is only the vehicle that carries it, so the cause has been misidentified. Mass antibiotics would not close the transmission route, would be impractical and expensive, and would add to the selection pressure for antibiotic resistance. Antibiotics are also not the first treatment: replacing the water and ions the patient has lost is what saves life.
The answer that scoresThe control measures work by breaking the faecal-oral route: treat drinking water by filtration, chlorination or boiling; build and maintain sewage disposal and sanitation so that faeces cannot reach a water supply; and educate people about hand washing and about not using rivers for both waste and drinking water. Treatment of individual patients is oral rehydration therapy to replace water and ions, with antibiotics only as an additional measure in severe cases.
Revise this topicInfectious diseases
A student wrote · Infectious diseasesA student wrote: 'A patient becomes resistant to antibiotics after taking them for too long, and the bacteria learn how to survive by changing their behaviour.'
Why it loses marksResistance is a property of the bacterial population, not of the patient, and bacteria do not learn. Random mutations arise in bacterial DNA all the time, so some bacteria already carry an allele that makes them less sensitive to the antibiotic. The antibiotic then acts as a selection pressure: sensitive bacteria are killed while resistant mutants survive and reproduce, so the frequency of the resistance allele rises.
The answer that scoresMutations that give resistance occur at random, before the antibiotic is used, so a bacterial population contains variation. When the antibiotic is present the sensitive bacteria are killed while the resistant mutants survive, and because bacteria reproduce rapidly by binary fission the resistant genotype quickly becomes the most common in the population. Resistance genes can also pass between bacteria on plasmids, which is why resistance spreads so fast. Using antibiotics only when necessary, completing the course and reducing their use in farming lower the selection pressure.
Revise this topicInfectious diseases
A student wrote · ImmunityA student wrote: 'Phagocytes are specific, because a neutrophil recognises the antigens on the surface of one particular pathogen and destroys only that pathogen.'
Why it loses marksThat confuses the non-specific defence with the specific one. A neutrophil does bind to antigens on a pathogen, but its receptors are not complementary to one antigen only: the response is the same whichever pathogen has entered, which is why it is described as non-specific. Only B-lymphocytes and T-lymphocytes are specific, because the binding site of their receptor fits one antigen.
The answer that scoresPhagocytes such as neutrophils and macrophages carry out the same non-specific response to any pathogen. The phagocyte is attracted to the site by chemicals, binds to non-self antigens on the surface of the pathogen, engulfs it by endocytosis to form a phagosome, and digests it with hydrolytic enzymes released from lysosomes. The specific response is provided by lymphocytes, and the link between the two is that a macrophage displays the antigens of the digested pathogen on its own surface membrane, which activates the T-helper cell whose receptor fits that antigen.
Revise this topicImmunity
A student wrote · ImmunityA student wrote: 'Antibodies destroy pathogens by digesting them, so an antibody works like an enzyme.'
Why it loses marksAn antibody is a binding protein and has no hydrolytic activity, so it cannot digest anything. The digestion is carried out by the hydrolytic enzymes inside the lysosomes of a phagocyte. Worse, an enzyme has an active site that catalyses a reaction and is reused, whereas an antibody binds an antigen and is not a catalyst.
The answer that scoresAn antibody binds to an antigen on the surface of a pathogen or to a toxin. Binding can agglutinate pathogens into clumps, neutralise a toxin by covering its active site or a virus by covering its attachment proteins, or act as a marker so that the constant region binds to receptors on a phagocyte and stimulates phagocytosis. Antibodies bound to a bacterial surface can also activate the complement system, which makes pores in the cell surface membrane so that the bacterium bursts. The antibody does not digest the pathogen; the phagocyte's lysosomes do that.
Revise this topicImmunity
A student wrote · ImmunityA student wrote: 'A vaccine gives passive immunity, because the vaccine contains the antibodies that protect you.'
Why it loses marksA vaccine contains antigens, not antibodies, and that is the whole point of vaccination. Passive immunity is the transfer of antibodies made by another organism; it produces no memory cells, so it gives immediate but short-lived protection. A vaccination is artificial active immunity because the person's own lymphocytes make the antibody and the memory cells.
The answer that scoresA vaccine contains antigens - killed or weakened pathogens, toxoids or purified antigen subunits, often with an adjuvant. Those antigens stimulate the person's own macrophages, T-helper cells and B-lymphocytes, so plasma cells secrete antibody and memory cells are produced without the person suffering the disease. Because the person's own lymphocytes did the work, this is active immunity and it is long-lasting. Passive immunity is different: it results from antibodies made elsewhere being injected, such as tetanus antitoxin after a wound or anti-D immunoglobulin for a rhesus-negative mother, and it protects at once but only for a few weeks.
Revise this topicImmunity
A student wrote · ImmunityA student wrote: 'T-helper cells destroy infected body cells, and T-killer cells stimulate the B-lymphocytes to divide.'
Why it loses marksThe two types of T-lymphocyte have been swapped. T-helper cells do not kill anything: they release cytokines that coordinate the response. T-killer cells are the ones that destroy infected cells, and they do not stimulate B-lymphocytes.
The answer that scoresA T-helper cell carries receptors complementary to an antigen presented on the surface of a macrophage. When it binds, it is activated, divides by mitosis and releases cytokines, which stimulate phagocytes, the T-killer cells and the B-lymphocyte whose antibody receptor fits the same antigen. A T-killer cell, once activated, binds to a body cell that is displaying that antigen - an infected cell or a cancer cell - and makes its cell surface membrane permeable, so hydrolytic enzymes inside the target cell are activated and the cell dies. Destroying the infected cell prevents the pathogen from multiplying inside it.
Revise this topicImmunity
A student wrote · Energy and respirationA student wrote: 'The link reaction and the Krebs cycle take place on the inner mitochondrial membrane, and oxidative phosphorylation takes place in the mitochondrial matrix.'
Why it loses marksThe locations are the wrong way round. The link reaction and the Krebs cycle are catalysed by enzymes dissolved in the matrix, whereas oxidative phosphorylation needs the electron transport chain and ATP synthase embedded in the inner membrane, and the matrix is where the proton gradient is set up across that membrane.
The answer that scoresGlycolysis happens in the cytoplasm; the link reaction and the Krebs cycle happen in the mitochondrial matrix, where their enzymes are dissolved; oxidative phosphorylation happens on the inner mitochondrial membrane, where the carriers of the electron transport chain and the ATP synthase molecules are embedded. The inner membrane is folded into cristae to provide a large surface area for those proteins.
Revise this topicEnergy and respiration
A student wrote · Energy and respirationA student wrote: 'In the respirometer, the soda lime absorbs the oxygen taken in by the germinating seeds, so the distance moved by the fluid measures the carbon dioxide produced.'
Why it loses marksSoda lime and potassium hydroxide absorb carbon dioxide, not oxygen. Nothing in the tube removes oxygen, because the seeds are using it, so the volume and pressure fall for the opposite reason to the one the student gives.
The answer that scoresThe alkali absorbs the carbon dioxide that the seeds produce, so the only gas that changes the volume in the tube is oxygen. As the seeds use oxygen the pressure inside falls and the fluid droplet moves towards the seeds, so the distance moved divided by the time gives the rate of oxygen uptake. To find the RQ you also need a second respirometer with no alkali, where the movement shows the difference between the carbon dioxide produced and the oxygen used, and then RQ = carbon dioxide produced / oxygen used.
Revise this topicEnergy and respiration
A student wrote · Energy and respirationA student wrote: 'In anaerobic respiration in a sprinter's muscle, glucose is broken down to lactate and carbon dioxide, releasing a small amount of ATP.'
Why it loses marksLactate fermentation produces no carbon dioxide. Pyruvate is simply reduced to lactate by hydrogen taken from reduced NAD, so all three carbon atoms of pyruvate are still in the lactate. Carbon dioxide is the product of the link reaction, the Krebs cycle and ethanol fermentation in yeast, not of lactate fermentation.
The answer that scoresIn a muscle that is short of oxygen, glycolysis still converts glucose to pyruvate with a net gain of two ATP per glucose and two molecules of reduced NAD. The pyruvate is then reduced to lactate, using hydrogen from the reduced NAD, which regenerates NAD so that glycolysis can continue. No carbon dioxide is produced. The lactate passes into the blood to the liver, is converted back to pyruvate, and can be respired aerobically later.
Revise this topicEnergy and respiration
A student wrote · Energy and respirationA student wrote: 'The RQ of a fatty acid such as oleic acid is greater than 1, because lipids contain a lot of hydrogen and release more energy per gram than carbohydrates.'
Why it loses marksThe reasoning is backwards. Having a lot of hydrogen means the substrate needs a great deal of oxygen to oxidise it, so the oxygen taken in is larger than the carbon dioxide produced and the RQ is less than 1, not more. A high energy value per gram says nothing about the RQ.
The answer that scoresFor oleic acid, C18H34O2 + 25.5O2 -> 18CO2 + 17H2O, the RQ is 18/25.5 = 0.71, well below 1. An RQ greater than 1 only happens when carbon dioxide is produced without oxygen being used, which occurs when some respiration is anaerobic, or when the substrate is an organic acid that already contains a great deal of oxygen, such as malic acid with an RQ of 4/3 = 1.33.
Revise this topicEnergy and respiration
A student wrote · PhotosynthesisA student wrote: 'The oxygen released during photosynthesis comes from carbon dioxide, because carbon dioxide is split in the light-dependent stage.'
Why it loses marksCarbon dioxide is not split in the light-dependent stage and it is not the source of the oxygen. The oxygen comes from water, and carbon dioxide is not used at all until the Calvin cycle in the stroma.
The answer that scoresIn non-cyclic photophosphorylation the oxygen-evolving complex catalyses the photolysis of water: 2H2O -> 4H+ + 4e- + O2. The electrons replace those lost by the reaction centre of photosystem II and the protons are released into the thylakoid space. Carbon dioxide is fixed much later, in the stroma, where rubisco combines it with RuBP to give two molecules of GP.
Revise this topicPhotosynthesis
A student wrote · PhotosynthesisA student wrote: 'Cyclic photophosphorylation produces ATP and reduced NADP, because both photosystems are involved.'
Why it loses marksCyclic photophosphorylation involves photosystem I only. The photoactivated electron passes along the electron transport chain and returns to PSI, so NADP is never reduced, water is not split and no oxygen is released.
The answer that scoresCyclic photophosphorylation uses only PSI, and the only product is ATP. It is needed because the Calvin cycle uses more ATP than reduced NADP, so the extra ATP is made this way. Non-cyclic photophosphorylation is the route that uses both PSI and PSII, splits water and produces ATP, reduced NADP and oxygen.
Revise this topicPhotosynthesis
A student wrote · PhotosynthesisA student wrote: 'Chlorophyll absorbs green light best, which is why leaves look green.'
Why it loses marksThe reasoning is back to front. Chlorophyll absorbs blue-violet and red light strongly and green light poorly, so green light is largely reflected and transmitted, and it is the light that is not absorbed that we see.
The answer that scoresThe absorption spectrum of chlorophyll a has peaks at about 430 nm in the blue-violet and about 660 nm in the red, with a trough in the green. The action spectrum for photosynthesis matches these peaks, which shows that the pigments absorbing the light are the ones driving photosynthesis; the small amount of photosynthesis that happens in green light is the contribution of the accessory pigments carotene and xanthophyll.
Revise this topicPhotosynthesis
A student wrote · PhotosynthesisA student wrote: 'When the grower raised the temperature of the glasshouse the crop went on growing faster, so the warmest glasshouse always gives the largest yield.'
Why it loses marksThe rate of photosynthesis only rises with temperature up to an optimum. Above it the enzymes of the Calvin cycle, including rubisco, are denatured, so the rate falls sharply. Temperature is also only the limiting factor when light and carbon dioxide are in good supply, and at night a warm glasshouse increases respiration instead of photosynthesis.
The answer that scoresThe grower's result shows only that temperature was the limiting factor over the range tested. The rate of photosynthesis has an optimum temperature, because the Calvin cycle is enzyme-catalysed: up to the optimum the enzymes and substrates collide more often, and above it the tertiary structure of rubisco and the other enzymes is destroyed by denaturation, so carbon fixation slows and then stops. A warmer glasshouse also increases the rate of respiration, which uses up the products of photosynthesis, so the net gain in yield is smaller than the increase in gross photosynthesis.
Revise this topicPhotosynthesis
A student wrote · HomeostasisA student wrote: 'ADH is secreted by the posterior pituitary gland and reduces the reabsorption of water, so a small quantity of ADH produces a large volume of dilute urine.'
Why it loses marksADH increases water reabsorption rather than reducing it, and the posterior pituitary releases ADH but does not synthesise it. The effect of ADH is to add aquaporins to the collecting duct membrane, so more water is reabsorbed and a smaller volume of more concentrated urine is produced.
The answer that scoresNeurosecretory cells in the hypothalamus synthesise ADH, which is stored in and released from the posterior pituitary gland into the blood. ADH binds to receptors on the cells of the collecting duct and increases the number of aquaporins in their cell surface membranes, so more water is reabsorbed by osmosis down the water potential gradient into the blood. A high concentration of ADH therefore produces a small volume of concentrated urine, and a low concentration, which is what follows drinking a large volume of water, produces a large volume of dilute urine.
Revise this topicHomeostasis
A student wrote · HomeostasisA student wrote: 'The glomerular filtrate contains red blood cells and plasma proteins, because the basement membrane is a filter with holes in it.'
Why it loses marksA filter holds back anything whose molecules are too large to pass through it. Red blood cells and plasma proteins such as albumin are far too large to pass between the endothelial cells or through the mesh of collagen and glycoproteins in the basement membrane, so a normal filtrate contains neither of them.
The answer that scoresUltrafiltration is filtration under pressure. Water, glucose, amino acids, salts and urea are forced out of the fenestrated glomerular capillaries, through the basement membrane and between the pedicels of the podocytes, into the capsular space. Blood cells and large plasma proteins remain in the capillary, so a healthy glomerular filtrate contains no cells and no protein. Protein appearing in the urine is therefore a sign that the filtration barrier has been damaged.
Revise this topicHomeostasis
A student wrote · HomeostasisA student wrote: 'Glucagon is a steroid hormone, so it passes through the cell surface membrane of a liver cell and activates glycogen phosphorylase directly.'
Why it loses marksGlucagon is a peptide hormone. It is water-soluble and cannot cross the phospholipid bilayer, so it binds to a receptor on the cell surface membrane and the signal is passed on inside the cell by a G-protein and a second messenger. It does not act directly on the final enzyme either, because several enzymes in a cascade are activated first.
The answer that scoresGlucagon binds to a specific receptor on the cell surface membrane of the liver cell, and the binding causes a conformational change that activates a G-protein, which in turn stimulates adenylyl cyclase. Adenylyl cyclase converts ATP into cyclic AMP, the second messenger, and cAMP activates protein kinase A, which begins an enzyme cascade. The cascade ends with the activation of glycogen phosphorylase, which catalyses the breakdown of glycogen to glucose, so the blood glucose concentration rises.
Revise this topicHomeostasis
A student wrote · HomeostasisA student wrote: 'When a plant is short of water, abscisic acid causes water to be actively transported out of the guard cells so that they become flaccid and the stomata close.'
Why it loses marksWater never moves by active transport: it moves by osmosis down a water potential gradient. Abscisic acid changes the solute content of the guard cells, and the water then follows the new gradient.
The answer that scoresAbscisic acid binds to receptors on the guard cell membrane and causes calcium ions to be released into the cytosol, where they act as a second messenger. The calcium ions open channels so that chloride and potassium ions leave the guard cells, which raises the water potential inside them, so water leaves by osmosis. The guard cells become flaccid, they straighten, and the stoma closes, which reduces transpiration during water stress.
Revise this topicHomeostasis
A student wrote · Control and coordinationA student wrote: 'During an action potential the sodium-potassium pump moves sodium ions out of the axon and potassium ions in, and this is what makes the inside of the axon positive.'
Why it loses marksThe pump moves three sodium ions out for every two potassium ions in, so its net effect is to make the inside of the axon more negative, not more positive, and it works continuously to maintain the resting potential. It is also much too slow: an action potential takes about a millisecond, while the pump restores the gradients over a much longer time afterwards.
The answer that scoresThe action potential is produced by diffusion through voltage-gated channels, not by the pump. A stimulus opens voltage-gated sodium channels, and sodium ions diffuse into the axon down their electrochemical gradient, so the inside becomes less negative and then positive, reaching about +40 mV. The sodium channels then inactivate and voltage-gated potassium channels open, so potassium ions diffuse out and the inside becomes negative again, which is the repolarisation. The sodium-potassium pump then restores the sodium and potassium concentration gradients, using ATP, so that the neurone can conduct another impulse.
Revise this topicControl and coordination
A student wrote · Control and coordinationA student wrote: 'In a myelinated neurone the impulse travels inside the myelin sheath, because myelin conducts the current much faster than the axon membrane does.'
Why it loses marksMyelin is a lipid-rich insulator, so it does the opposite of conducting: no ions can cross the membrane and no action potential can be generated where the membrane is covered. The time saving comes from missing out the covered stretches of membrane, not from conduction through the myelin itself.
The answer that scoresThe myelin sheath insulates the axon, so the only places where ions can cross the membrane and an action potential can be generated are the nodes of Ranvier. Depolarisation at one node sets up a local circuit of current that flows through the axoplasm of the myelinated stretch to the next node and depolarises the membrane there, so the action potential appears to jump from node to node: this is saltatory conduction. Because action potentials are generated only at the nodes, fewer sodium and potassium ions cross the membrane, so fewer sodium-potassium pump cycles are needed and the neurone uses less ATP, as well as conducting much faster.
Revise this topicControl and coordination
A student wrote · Control and coordinationA student wrote: 'In a reflex action such as the knee-jerk, the brain is not involved at all, so the brain never receives information about the stimulus.'
Why it loses marksThe brain is not involved in deciding the response, and that is exactly what makes a reflex fast, but it is wrong to say it never receives the information. Branches of the sensory neurone carry impulses up the spinal cord to the brain, so the person becomes aware of the tap just after the leg has kicked; a reflex is not an unconscious event.
The answer that scoresIn the knee-jerk reflex the tap stretches the quadriceps tendon and stimulates stretch receptors in the muscle. Impulses travel along a sensory neurone into the spinal cord, where the sensory neurone synapses directly with a motor neurone, and the motor neurone carries impulses out to the quadriceps, which contracts so that the lower leg kicks forward. Only two neurones are involved and the pathway is short, so the response happens before the brain can be consulted, and the same stimulus at the same time inhibits the motor neurones of the antagonistic flexor muscles so that they do not oppose the movement. Branches of the sensory neurone also pass impulses up to the brain, so the person is aware of the tap, but the brain plays no part in producing the movement and cannot prevent it.
Revise this topicControl and coordination
A student wrote · Control and coordinationA student wrote: 'When a sarcomere contracts, the actin and myosin filaments become shorter, so both the A band and the I band get narrower.'
Why it loses marksThe length of the filaments does not change at all: the actin filaments slide over the myosin filaments. The A band is the length of the myosin filaments, so it keeps exactly the same width during contraction; only the I band and the H zone narrow as the actin is pulled further in among the myosin.
The answer that scoresThe myosin heads attach to the exposed binding sites on the actin filaments to form cross-bridges and then change angle, pulling the actin filaments towards the centre of the sarcomere, so the actin filaments slide over the myosin filaments and the filaments themselves stay the same length. The Z lines are drawn closer together and the sarcomere therefore shortens. Because the actin filaments slide further in among the myosin filaments, the I band and the H zone become narrower and can almost disappear, while the A band remains exactly the same width.
Revise this topicControl and coordination
A student wrote · InheritanceA student wrote: 'A gamete is haploid, but it still contains pairs of homologous chromosomes so that the offspring has a full set of genes.'
Why it loses marksA gamete contains one chromosome from each homologous pair, not the pairs themselves. Pairing of homologous chromosomes happens in the diploid cell during prophase I and again in the zygote; it is not carried in the gamete. The phrase 'a full set of genes' is also misleading, because one copy of each gene is a complete set.
The answer that scoresA gamete is haploid (n) and contains one chromosome from each homologous pair - 23 chromosomes in a human sperm or egg. The pairs exist in the diploid (2n) parent cell before meiosis and are separated in anaphase I, so one chromosome of each pair goes into each gamete. At fertilisation the two haploid sets come together and restore the diploid number, so the homologous pairs are re-formed in the zygote.
Revise this topicInheritance
A student wrote · InheritanceA student wrote: 'In a dihybrid cross between two RrYy pea plants the ratio is 9 : 3 : 3 : 1, so from 64 offspring 9 will be round and yellow and 3 will be round and green.'
Why it loses marksThe ratio is out of 16, the number of boxes in the Punnett square, not out of the total number of offspring. The student has treated the ratio numbers as actual counts, which gives an expected total of 16 offspring rather than 64.
The answer that scoresConvert the ratio to proportions first. Round and yellow is 9/16, so out of 64 offspring you expect 9/16 x 64 = 36 round and yellow. Round and green is 3/16 x 64 = 12, wrinkled and yellow is 3/16 x 64 = 12, and wrinkled and green is 1/16 x 64 = 4, and the four expected numbers add up to 64.
Revise this topicInheritance
A student wrote · InheritanceA student wrote: 'Two organisms that look the same must have the same genotype, so two purple-flowered pea plants must both be PP.'
Why it loses marksThis ignores dominance. A dominant phenotype can be produced by two different genotypes, PP or Pp, because one dominant allele is enough for the purple colour. The student has confused the phenotype, which is what is observed, with the genotype, which is the alleles carried.
The answer that scoresTwo purple-flowered plants could be PP or Pp. A test cross distinguishes them: cross each plant with a white-flowered plant, which must be pp. If all the offspring are purple the parent was probably PP, because every offspring received a P allele; if about half the offspring are white the parent was Pp, because its p gametes produced white offspring with the pp parent.
Revise this topicInheritance
A student wrote · InheritanceA student wrote: 'The chi-squared value came out as 2.13, which is small, so the results do not fit the expected 3 : 1 ratio.'
Why it loses marksThe interpretation is reversed. A small chi-squared value means a small difference between the observed and expected numbers, and it must be compared with the critical value at the 0.05 probability level with the right degrees of freedom before any conclusion can be drawn.
The answer that scoresWith 1 degree of freedom the critical value of chi-squared at the 0.05 probability level is 3.84. The calculated value of 2.13 is smaller than 3.84, so the difference between the observed and expected numbers is not significant: the results are consistent with a 3 : 1 ratio, and the deviation is due to chance. The number of degrees of freedom and the probability level must both be stated.
Revise this topicInheritance
A student wrote · Selection and evolutionA student wrote: 'Bacteria become resistant to an antibiotic because they are exposed to it, and the antibiotic causes the mutation that makes them resistant.'
Why it loses marksMutations arise at random and arise before the antibiotic is ever encountered. The antibiotic does not cause or direct the mutation, and selection cannot create a new allele - it can only change the frequency of alleles that already exist in the population.
The answer that scoresA random mutation has already given a few bacteria an allele for resistance before the antibiotic is used. When the antibiotic is given, the bacteria without the allele are killed while the resistant ones survive and reproduce rapidly by binary fission, so the frequency of the resistance allele in the population rises and the antibiotic no longer works. Resistance can also be passed between bacteria on plasmids by conjugation, which spreads it even faster.
Revise this topicSelection and evolution
A student wrote · Selection and evolutionA student wrote: 'In the Hardy-Weinberg equation q2 is the frequency of the recessive allele.'
Why it loses marksThis confuses an allele frequency with a genotype frequency. q is the frequency of the recessive allele; q2 is the frequency of the homozygous recessive genotype, which is the proportion of individuals showing the recessive phenotype.
The answer that scoresp and q are allele frequencies that add up to 1, while p2, 2pq and q2 are genotype frequencies: p2 for homozygous dominant, 2pq for heterozygous and q2 for homozygous recessive. If 9 people in every 100 show the recessive phenotype then q2 = 0.09, so q = 0.3 and p = 0.7; 2pq = 0.42 means 42 people in every 100 are carriers who show no sign of the condition.
Revise this topicSelection and evolution
A student wrote · Selection and evolutionA student wrote: 'Geographical separation on its own produces two new species, so any population that is split by a barrier immediately becomes two species.'
Why it loses marksA barrier only stops gene flow, which is genetic isolation, not speciation. The two populations must also diverge, because of different selection pressures and independent mutations, and then become reproductively isolated, which takes many generations. If the barrier disappears before reproductive isolation has occurred, the two populations interbreed again and remain one species.
The answer that scoresAllopatric speciation needs three things: a barrier that stops gene flow between the two populations; different selection pressures and independent mutations, so the allele frequencies of the two gene pools diverge; and finally reproductive isolation, so that even if the populations meet again they can no longer interbreed to produce fertile offspring. Only then are they separate species. Sympatric speciation, by contrast, can occur with no barrier at all, through ecological or behavioural isolation between groups living in the same area.
Revise this topicSelection and evolution
A student wrote · Selection and evolutionA student wrote: 'The founder effect and the bottleneck effect are examples of natural selection, because the allele frequencies change.'
Why it loses marksBoth are examples of genetic drift, in which allele frequencies change by chance rather than because of differences in fitness. Natural selection is non-random: the alleles that become commoner are the ones that give their carriers a better chance of surviving and reproducing.
The answer that scoresNatural selection is a non-random change in allele frequencies caused by differences in survival and reproductive success. Genetic drift is a random change caused by chance events, and both the founder effect and the bottleneck effect increase its importance because they reduce the population to a small sample of the original alleles: the colonists of a new area, or the few survivors of a disaster, carry only a random sample, so allele frequencies differ from the source population even though no allele is better than another.
Revise this topicSelection and evolution
A student wrote · Classification, biodiversity and conservationA student wrote: 'The two populations must belong to the same species, because every individual has the same visible features and they key out identically in a dichotomous key.'
Why it loses marksThis uses the morphological species concept alone and treats appearance as proof. Cryptic species look almost identical and key out identically, yet they do not interbreed, and within one species the sexes and the larval and adult stages can look completely different. Visible features are evidence, but in the biological species concept the test is interbreeding that produces fertile offspring.
The answer that scoresThe biological species concept defines a species as a group of organisms with similar characteristics that can interbreed to produce fertile offspring and that do not normally interbreed with other groups. If the two populations meet and interbreed freely, they are one species; if they do not interbreed, or their offspring are infertile, they are separate species even when they look alike. The common pipistrelle and the soprano pipistrelle are an example of two species that were separated only when their echolocation calls and DNA were compared, not by their appearance. Where the biological concept cannot be applied, for fossils or asexual organisms, morphology or ecology is used and the limitation is stated.
Revise this topicClassification, biodiversity and conservation
A student wrote · Classification, biodiversity and conservationA student wrote: 'In a quadrat, the counts of four species were 40, 30, 20 and 10, so the sum of (n / N)2 is 0.3 and the index of diversity is 0.3, which means the area has a low diversity.'
Why it loses marksTwo marks are lost. The student forgot to subtract the sum from 1, and the interpretation of the value is reversed as a result. Simpson's index of diversity is D = 1 - (sum of (n / N)2), and a value of 0.3 would mean a community dominated by one or two species, not a low diversity.
The answer that scoresThe total number of individuals is N = 40 + 30 + 20 + 10 = 100. The squares of the counts add to 1600 + 900 + 400 + 100 = 3000, so the sum of (n / N)2 is 3000 / 10000 = 0.30 and D = 1 - 0.30 = 0.70. A value of 0.70 is close to 1, so diversity is fairly high, which agrees with the data: four species are present and no single species makes up more than 40 per cent of the individuals.
Revise this topicClassification, biodiversity and conservation
A student wrote · Classification, biodiversity and conservationA student wrote: 'To find out how plant species change along a gradient of light intensity, I would throw a frame quadrat at random; a belt transect is a square frame used to count the number of individuals in one place.'
Why it loses marksThe two methods have been swapped and the wrong one chosen for the question. Random quadrats estimate average abundance across an area; they are placed independently of any gradient, so they cannot show a pattern as light intensity changes. A belt transect is not a frame placed in one place.
The answer that scoresA frame quadrat is a square frame of known area, placed at random coordinates to estimate abundance in an area, and its abundance can be recorded as density, percentage cover or frequency. A line transect is a tape stretched along the gradient, on which the species touching the tape or the points where each species begins are recorded, which shows distribution along the gradient but not abundance. A belt transect is a strip of known width sampled at regular intervals along the tape, so that both the distribution and the abundance of each species are recorded at each point along the gradient; light intensity is measured at the same points with a light meter so that the two sets of data can be correlated.
Revise this topicClassification, biodiversity and conservation
A student wrote · Classification, biodiversity and conservationA student wrote: 'There is no need to protect tropical forest, because the species that live there can be kept in zoos and seed banks instead, and then reintroduced later.'
Why it loses marksThis treats ex situ conservation as an alternative to protecting the habitat, when it is only a back-up. A zoo or a seed bank can hold only a small number of species and a small number of individuals of each, so most of the genetic variation is lost, and the great majority of organisms in a tropical forest, including insects, fungi, soil organisms and microorganisms, cannot be kept this way at all. Even when the species survives, its role in the ecosystem, as pollinator, seed disperser, nutrient recycler and carbon store, is not preserved.
The answer that scoresIn situ conservation protects the habitat and the whole community at once, which is why conserved areas such as national parks and marine parks are the main method: they protect the species, the interactions between species and the potential for the population to keep evolving, and they protect species that could never be kept in captivity. Ex situ measures, including zoos, botanic gardens, frozen zoos and seed banks, are valuable back-ups that keep genetic material and provide animals for reintroduction, but they are used alongside habitat protection, not instead of it.
Revise this topicClassification, biodiversity and conservation
A student wrote · Genetic technologyA student wrote: 'The gene is cut out of the donor DNA with DNA ligase and then joined to the plasmid with a restriction endonuclease, which reforms the hydrogen bonds.'
Why it loses marksThe two enzymes have been swapped, and the bond has been named wrongly. A restriction endonuclease cuts DNA; it does not join anything. DNA ligase is the enzyme that joins, and it catalyses the formation of phosphodiester bonds, not hydrogen bonds.
The answer that scoresThe donor DNA and the plasmid are both cut with the same restriction endonuclease, which recognises a specific base sequence and cuts the sugar-phosphate backbone, leaving complementary sticky ends. The gene and the opened plasmid then base pair through those sticky ends, and DNA ligase catalyses the formation of phosphodiester bonds between the sugar of one nucleotide and the phosphate of the next, so the gene becomes part of one continuous DNA molecule with the plasmid.
Revise this topicGenetic technology
A student wrote · Genetic technologyA student wrote: 'Taq polymerase is used in PCR because it is faster than human DNA polymerase, and after 20 cycles there are 20 times as many copies of the target sequence.'
Why it loses marksTaq polymerase is chosen for its heat stability, not its speed: its tertiary structure is not denatured by the 95 °C step, whereas a human DNA polymerase would be destroyed in the first cycle. The number of copies also doubles each cycle rather than increasing by one copy, so the arithmetic is wrong.
The answer that scoresTaq polymerase comes from the thermophilic bacterium Thermus aquaticus and is not denatured at about 95 °C, so it survives the step that separates the two strands and does not have to be replaced every cycle. Each cycle doubles the number of copies of the target sequence, because every strand made in one cycle acts as a template in the next, so after 20 cycles there are 2 to the power of 20, about one million, copies rather than 20.
Revise this topicGenetic technology
A student wrote · Genetic technologyA student wrote: 'In gel electrophoresis the DNA fragments move towards the negative electrode, and the largest fragments travel furthest because they carry the most charge.'
Why it loses marksBoth halves of the sentence are wrong. DNA is negatively charged, so it is repelled by the negative electrode and attracted to the positive one. Charge does not decide how far a fragment travels, because the charge is proportional to the number of nucleotides; the size of the fragment decides it, and large fragments are held back by the pores of the gel.
The answer that scoresThe phosphate groups in the sugar-phosphate backbone give every DNA fragment a net negative charge, so the fragments move towards the positive electrode, the anode. The agarose gel acts as a sieve: small fragments pass through the pores easily and travel further in a given time, while large fragments are held back, so a band further from the wells contains shorter fragments. A sample of fragments of known length is run in one lane so that the distance moved can be converted into a length in base pairs.
Revise this topicGenetic technology
A student wrote · Genetic technologyA student wrote: 'The human insulin gene can simply be cut out of human DNA and put into a bacterium, because the genetic code is universal and the bacterial ribosomes will translate the human gene into human insulin.'
Why it loses marksThe universal code is only half of what is needed. A eukaryotic gene cut straight out of human DNA contains introns, and a bacterium has no mechanism for removing them, so the bacterium would translate the introns as well as the coding sequence and make a wrong and probably non-functional polypeptide. A gene transferred into a bacterium also needs a promoter that the bacterium recognises.
The answer that scoresThe gene is made as complementary DNA instead. mRNA is extracted from human cells that are expressing the gene, such as pancreatic beta cells, and reverse transcriptase makes a DNA copy of it. Because mRNA has already been spliced, the cDNA contains only the coding sequence, so the bacterial ribosomes can translate it correctly into human insulin exactly as the human cell does. A strong bacterial promoter is transferred with the gene at the same time, because RNA polymerase from the bacterium will not bind to a human promoter, and a marker gene is included so that the bacteria that have taken up the plasmid can be identified.
Revise this topicGenetic technology