Syllabus coverage
- Give ratios in their simplest form, for example 20 : 30 : 40 in its simplest form is 2 : 3 : 4
- Divide a quantity in a given ratio
- Use proportional reasoning and ratios in context, for example adapt recipes, use map scales and determine best value
- Use common measures of rate, including hourly rates of pay and exchange rates between currencies
- Apply other measures of rate, including flow rates, fuel consumption, pressure, density and population density
- Solve problems involving average speed, using the speed, distance and time relationship (required formulas are given in the question where they are not standard)
- Use rate notation such as m/s (metres per second) and g/cm3 (grams per cubic centimetre)
- Extended only: find the lower bound of a speed calculated from rounded values of distance and time (E1.10)
Part of the IGCSE Maths syllabus 0580.
What a ratio is, and how to simplify one
A ratio compares quantities of the same kind. Writing says the three amounts are in the same proportion as . Because a ratio compares like with like, the numbers carry no units: is the same ratio whether the amounts are grams, minutes or dollars.
To simplify a ratio, divide every part by the same number until the parts share no common factor other than 1. has a common factor of 10, so dividing every part by 10 gives . The numbers have been scaled down, but the relationship between them has not changed.
The units must match before you simplify. A ratio of 250 g to 1.5 kg is not 250 to 1.5: convert first so both parts are in grams, giving , which simplifies to . Cambridge expects whole numbers in the simplest form wherever possible, so multiply out decimals and fractions first: becomes , and becomes .
Dividing by the highest common factor gets you there in one step. For the highest common factor is 15, and dividing every part by 15 gives . If you cannot spot the highest common factor, divide by anything that goes into all the parts and repeat until nothing else does.
| Ratio | What to do first | Simplest form |
|---|---|---|
| divide every part by 10 | ||
| divide every part by 15 | ||
| multiply both parts by 2 | ||
| multiply both parts by 2 | ||
| 250 g to 1.5 kg | convert to grams, then divide by 250 |
Dividing a quantity in a given ratio
Dividing in a ratio means splitting a total into parts whose sizes are in that ratio. The method has three steps: add the numbers in the ratio to find the number of equal parts, divide the total by that number to find the value of one part, then multiply by each number in the ratio.
Share 90 sweets in the ratio . The number of parts is , so one part is sweets. The shares are , and . The check is always the same: the shares must add back to the amount you started with, and .
For a two-part ratio, share 3.5 kg in the ratio . There are 7 parts, so one part is kg and the shares are 2 kg and 1.5 kg. Notice that the answer keeps the unit of the original quantity - the ratio itself has none, so the shares of a mass are masses.
The same method works when the total is money. Share in the ratio : there are 5 parts, one part is , so the shares are and . Keep the ratio in the order the question gives it, because a question that asks for the larger share is marked on the share you name, not just on the arithmetic.
- 90 sweets in : 9 parts, so 1 part is 10 - shares 20, 30 and 40
- in : 5 parts, so 1 part is - shares and
- 3.5 kg in : 7 parts, so 1 part is 0.5 kg - shares 2 kg and 1.5 kg
- 2.4 m in : 6 parts, so 1 part is 0.4 m - shares 0.4 m and 2.0 m
- Always check that the shares add back to the quantity you started with
Ratio in context: recipes, map scales and best value
Cambridge names three contexts for proportional reasoning: adapting recipes, using map scales and deciding which of two offers is better value. All three are the same skill, which is keeping a ratio fixed while the total changes.
In a recipe, every ingredient is scaled by the same factor. A recipe for 12 flapjacks uses 300 g of oats; for 20 flapjacks the factor is , so the oats needed are g. Scaling only the ingredient named in the question is a common error, because the other ingredients may be needed for a later part of the same question.
A map scale such as is a ratio: 1 cm on the map stands for 50 000 cm on the ground. Convert to a sensible unit first - 50 000 cm is 500 m - so 4 cm on the map is 2 km on the ground and 7.5 cm is 3.75 km. Divide the map measurement by the scale when you are finding a real distance, and multiply when you are finding how long a real distance would be on the map.
Best value questions compare cost per unit. If 3 kg of potatoes costs 4.50 dollars and 5 kg costs 7.20 dollars, the unit prices are dollars per kg and dollars per kg, so the 5 kg bag is better value. Comparing the two total prices tells you nothing, because the bags are different sizes.
| Map scale | 1 cm on the map represents | 6 cm on the map represents |
|---|---|---|
| 250 m | 1.5 km | |
| 500 m | 3 km | |
| 1 km | 6 km | |
| 2 km | 12 km |
Proportion and the unitary method
Two quantities are in direct proportion when multiplying one by a number multiplies the other by the same number. If 5 identical pens cost 3.75 dollars, then 10 pens cost 7.50 dollars and 20 pens cost 15.00 dollars, because the cost per pen has not changed.
The unitary method finds the value of one unit first and then multiplies. From 5 pens at 3.75 dollars, one pen costs dollars, so 8 pens cost dollars. This is the safest method when the question does not scale by a whole number, such as asking for the cost of 7 pens.
The same method handles currency, pay and recipe questions, which is why ratio and proportion are one topic rather than three. Find the value of one hour, one litre or one serving, then multiply by the number you actually need. Keep the unrounded value on the calculator display and round only at the end.
Not every proportion is direct. If 4 workers take 9 days to build a wall, 12 workers do not take 27 days - more workers means less time. The total work is worker-days, so 12 workers take days. When one quantity goes up while the other goes down, the product stays constant instead of the ratio.
Rates: pay, currency, flow, fuel, density and pressure
A rate compares two different quantities, which is what separates it from a ratio. 14.50 dollars per hour, 12 km per litre and 200 people per square kilometre are all rates, and the word per tells you that a division has happened. Someone paid 14.50 dollars an hour who works 7 hours 30 minutes earns dollars.
Currency conversion is a rate. The question always gives you the rate, so use the one in the question and never one you remember from the news. At 1 pound = 1.25 dollars, 240 pounds is dollars, and 450 dollars is pounds. Decide the direction by asking whether the answer should be a bigger or a smaller number than the one you started with.
Flow rate and fuel consumption use the same idea. A tap that fills 12 litres in 4 minutes has a rate of litres per minute, so filling 45 litres takes 15 minutes. A car using 45 litres over 540 km does km per litre, and at 1.40 dollars per litre that journey costs dollars.
Density is mass divided by volume, and pressure is force divided by area. A metal block of mass 240 g and volume 30 cm has a density of g/cm, and a force of 600 N over an area of 0.5 m gives a pressure of N/m. Population density is people divided by area: 96 000 people spread over 480 km is people per km.
| Rate | What is divided by what | Example |
|---|---|---|
| Pay | money by time | dollars per hour |
| Exchange rate | one currency by the other | 1 pound = 1.25 dollars |
| Flow rate | volume by time | 12 litres in 4 minutes is 3 litres per minute |
| Fuel consumption | distance by fuel | 540 km on 45 litres is 12 km per litre |
| Density | mass by volume | 240 g in 30 cm is 8 g/cm |
| Pressure | force by area | 600 N over 0.5 m is 1200 N/m |
| Population density | people by area | 96 000 people in 480 km is 200 per km |
Average speed: distance, time and units
The syllabus requires you to know the speed, distance and time relationship, and it is not given in the question. Average speed is total distance divided by total time, . Rearranged, and . If you forget which is which, remember that speed is how far you travel in one unit of time.
Units decide the answer. A distance in km with a time in hours gives a speed in km/h, and metres with seconds gives m/s. A time of 2 hours 20 minutes is hours, so 84 km in that time is km/h. Convert minutes to a fraction of an hour before dividing: 15 minutes is 0.25 hours, 30 minutes is 0.5 hours and 45 minutes is 0.75 hours.
Average speed is not the average of the speeds. A driver covers 180 km at 90 km/h, which takes 2 hours, and then 45 km at 45 km/h, which takes 1 hour. The whole journey is 225 km in 3 hours, so the average speed is km/h - while the mean of 90 and 45 is only 67.5 km/h. The mean is wrong because the two speeds were not held for equal times.
Converting between speed units is worth learning as a rule. To turn km/h into m/s, multiply by , which is the same as dividing by 3.6, so 72 km/h is 20 m/s. To go the other way, multiply by 3.6: 15 m/s is 54 km/h.
Part to part, part to whole: the two ways a ratio is used
A ratio such as describes the parts, not the whole. The whole is parts, so the first share is of the total and the second is . Writing because the ratio says is the mistake that costs the most marks in this topic.
Different questions give you different pieces of the picture. If you are given the total, divide it by the number of parts. If you are given one share, divide that share by its own number of parts. If you are given the difference between the shares, divide by the difference between the ratio numbers.
In the ratio the shares differ by parts. If a question says the two amounts differ by 8, then 2 parts is 8, so 1 part is 4 and the shares are 12 and 20. The same ratio with a total of 48 gives for each part and shares of 18 and 30.
The same reasoning answers questions where an amount is missing. If A : B = and A is 21, then 3 parts is 21, so 1 part is 7 and B is 28. Name the quantity that one part represents before you divide, because that one sentence is what keeps the arithmetic honest.
- Total given: divide the total by the sum of the ratio numbers
- One share given: divide that share by its own number of parts
- Difference given: divide the difference by the difference between the ratio numbers
- Check the answer is in the given ratio and that the shares add to the total
Key terms you must be able to define
- Ratio
- A comparison of two or more quantities of the same kind, written with colons, for example . A ratio has no units.
- Simplest form
- The form of a ratio in which every part has been divided by the same number so that the parts share no common factor other than 1. in its simplest form is .
- Proportion
- A statement that two ratios are equal, so the two pairs of quantities grow or shrink together.
- Direct proportion
- The relationship in which multiplying one quantity by a number multiplies the other by the same number.
- Unitary method
- Finding the value of one unit first, then multiplying to get the value you need.
- Map scale
- The ratio of a length on a map to the real length it represents, for example , so 1 cm on the map is 50 000 cm on the ground.
- Best value
- The option with the lowest cost per unit, found by dividing the cost by the quantity for each option.
- Rate
- A comparison of two quantities of different kinds, such as dollars per hour or kilometres per litre.
- Exchange rate
- The rate at which one currency is converted into another, for example 1 pound = 1.25 dollars.
- Average speed
- Total distance travelled divided by total time taken. It is not the mean of the speeds used.
- Density
- Mass per unit volume, found by dividing mass by volume and measured in g/cm3.
- Pressure
- Force per unit area, found by dividing force by area and measured in N/m2.
- Population density
- The number of people per unit of area, usually found by dividing the population by the area in km2.
- Flow rate
- The volume of liquid passing a point in each unit of time, such as litres per minute.
- Fuel consumption
- The distance a vehicle travels on each unit of fuel, such as kilometres per litre.
- Unit price
- The cost of one unit of an item, such as the price of 1 kg or 1 litre, used to compare offers of different sizes.
In context
Cambridge sets 0580 in real situations - a recipe, a bank statement, a map, a garden, a graph of a car's journey. These show how the mathematics appears in a question, then you write your own working for the numbers you are given.
Write and 250 g to 1.5 kg in their simplest forms. The three numbers share the factor 15, so . For the second, convert to the same unit first: , then divide both parts by 250 to get .
A 2.4 m length of timber is cut into two pieces in the ratio . There are parts, so one part is m. The pieces are 0.4 m and m, and , which is the check.
A recipe for 12 flapjacks uses 300 g of oats, 150 g of butter and 90 g of syrup. For 20 flapjacks the scale factor is , so the oats become g, the butter 250 g and the syrup 150 g. Every ingredient is scaled by the same factor.
A 4 kg bag of potatoes costs 5.20 dollars and a 6 kg bag costs 7.50 dollars. The unit prices are and dollars per kg, so the 6 kg bag is better value even though it costs more in total.
A train covers 84 km in 2 hours 20 minutes. The time is hours, so the average speed is km/h. Entering 2.20 instead of would give 38.2 km/h and lose the answer mark.
Flashcards
Click a card to flip it. Mark honestly — the tracker uses this.
Exam-style questions
8 questions, 23 marks. Write your answer, then reveal the mark scheme and tick each point you actually made. Answering honestly here is what makes the rest of the site useful.
Mark scheme — tick each point you actually made
- M1
- A1not checked yet
Mark scheme — tick each point you actually made
- M1
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- A1the longer piece is mnot checked yet
Mark scheme — tick each point you actually made
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- M1
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- A1the 6 kg bagnot checked yet
Mark scheme — tick each point you actually made
- M1
- M1
- M1
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- A160 km/hnot checked yet
Mark scheme — tick each point you actually made
- M1
- M1
- A1 dollarsnot checked yet
Mark scheme — tick each point you actually made
- B1
- M1
- A1
Mark scheme — tick each point you actually made
- B1density g/cmnot checked yet
Mark scheme — tick each point you actually made
- M1
- A1120 seconds minutesnot checked yet
Exam technique for this topic
- Write the ratio in the order the question gives it. A question about a mix that asks for the amount of cement is marked on the cement, not on whichever share you happened to work out first.
- Convert to the same unit before simplifying a ratio, and check that your final shares add back to the total. Both checks take seconds and between them catch most of the marks lost in this topic.
- In a rate question, work out the unit of the answer before you calculate. An answer in km/h needs a distance in km and a time in hours, so convert 2 hours 20 minutes to hours rather than typing 2.20.
- Use the exchange rate given in the question, even if it looks unrealistic. A rate you remember from elsewhere scores nothing, because the mark scheme works from the question's own rate.
- For an average speed over two parts of a journey, find the total distance and the total time. Never average the two speeds, because the parts usually last for different lengths of time.