Syllabus coverage
- Identify physical and chemical changes, and describe the differences between them
- Describe the effect on the rate of reaction of changing the concentration of solutions, changing the pressure of gases, changing the surface area of solids, changing the temperature, and adding or removing a catalyst, including enzymes
- State that a catalyst increases the rate of a reaction and is unchanged at the end of a reaction, and that a catalyst decreases the activation energy, Ea, of a reaction
- Describe practical methods for investigating the rate of a reaction, including change in mass of a reactant or a product and the formation of a gas, and interpret data, including graphs, from rate of reaction experiments
- Describe collision theory in terms of the number of particles per unit volume, the frequency of collisions between particles, the kinetic energy of particles and activation energy, Ea, and use it to explain the effect of changing conditions on the rate of reaction
- State that some chemical reactions are reversible, as shown by the equilibrium symbol, and describe how changing the conditions can change the direction of a reversible reaction, including the effect of heat on hydrated compounds and the addition of water to anhydrous compounds, limited to copper(II) sulfate and cobalt(II) chloride
- State that a reversible reaction in a closed system is at equilibrium when the rate of the forward reaction is equal to the rate of the reverse reaction and the concentrations of reactants and products are no longer changing, and predict and explain how the position of equilibrium is affected by changing temperature, changing pressure, changing concentration and using a catalyst
- State the symbol equations for the production of ammonia in the Haber process and for the conversion of sulfur dioxide to sulfur trioxide in the Contact process, including the sources of the reactants and the typical conditions used, and explain why those conditions are used
- Define redox reactions as involving simultaneous oxidation and reduction, define oxidation and reduction in terms of gain and loss of oxygen, loss and gain of electrons and changes in oxidation number, and identify oxidising and reducing agents in redox reactions
Part of the IGCSE Chemistry syllabus 0620 / 0971.
Physical and chemical changes
A physical change alters the form of a substance but not its chemical identity. Ice melting, water boiling, salt dissolving and glass shattering are all physical changes: no new substance is made, the particles are simply rearranged or spread further apart, and the change is usually easy to reverse.
A chemical change produces one or more new substances with different properties from the starting materials. Burning magnesium, rusting iron and neutralising an acid with an alkali are chemical changes. The atoms are rearranged into new combinations, which is why the new substance has a different formula from the old one.
You can tell the two apart from the evidence. A chemical change usually gives one or more of: a colour change, a gas given off, a solid precipitate formed, a change in temperature, or a new smell. A physical change such as melting shows none of these, only a change of state.
The clearest test is reversibility. Melting, freezing, dissolving and boiling can all be reversed by changing the conditions back, but a chemical change is normally not reversed by simple physical means. Heating blue hydrated copper(II) sulfate turns it white and drives off the water, and adding water brings the blue colour back, but this is still a chemical change because a new compound, anhydrous copper(II) sulfate, has been formed.
- Physical change: no new substance, usually reversible, chemical identity unchanged.
- Chemical change: a new substance is formed, usually irreversible, atoms rearranged.
- Evidence of chemical change: colour change, gas, precipitate, temperature change, new smell.
- Dissolving is physical; burning, rusting and neutralising are chemical.
Collision theory: why reactions happen at all
For a reaction to take place the reacting particles must collide, and they must collide with at least a certain minimum energy. That minimum is the activation energy, Ea. A collision with enough energy is an effective collision and leads to a reaction; a gentle collision simply bounces the particles apart.
The rate of reaction is the number of effective collisions per unit time. Anything that increases the number of effective collisions per second increases the rate. There are only three ways to do that: raise the number of particles per unit volume, raise the frequency of collisions between particles, or raise the kinetic energy of the particles so that more of them carry at least the activation energy.
A catalyst works by a different route. It provides an alternative pathway with a lower activation energy, so a greater fraction of the collisions that are already happening now carry enough energy to react. The catalyst itself is not changed or used up.
This one idea explains every factor in this topic. If you can say what a change does to the number, the frequency or the energy of collisions, you can explain any rate question.
- Particles must collide with energy greater than or equal to the activation energy.
- Rate = number of effective collisions per unit time.
- More particles per unit volume and a higher temperature both increase the collision frequency.
- A catalyst lowers the activation energy, so more collisions are effective.
The factors that affect the rate of reaction
Concentration and pressure. Increasing the concentration of a solution puts more particles into the same volume, so there are more particles per unit volume, collisions are more frequent and the rate increases. On a graph of rate against concentration the line rises. For gases, increasing the pressure squeezes the same number of particles into a smaller volume, which is exactly the same effect: more particles per unit volume, more frequent collisions and a faster rate.
Surface area. A solid can only react where its surface touches the other reactant. Breaking a lump into smaller pieces, or using a powder instead of chips, exposes far more surface. There are more collisions per unit time, so the rate increases, even though the total mass of solid is unchanged.
Temperature. Raising the temperature gives every particle more kinetic energy. The particles move faster, so they collide more often, and each collision is more energetic, so a larger fraction of collisions exceed the activation energy. Both effects increase the rate, which is why temperature has such a large effect.
Catalyst. Adding a catalyst lowers the activation energy, so more collisions are effective and the rate increases. Removing it reverses the effect. Enzymes are biological catalysts and behave in exactly the same way.
| Change | What it does to the particles | Effect on the rate |
|---|---|---|
| Increase the concentration of a solution | More particles in the same volume | Increases, because collisions are more frequent |
| Increase the pressure of a gas | The same particles in a smaller volume | Increases, because the particles are closer together |
| Increase the surface area of a solid | More of the solid is exposed | Increases, because more collisions happen each second |
| Increase the temperature | Particles gain kinetic energy | Increases, because collisions are more frequent and more energetic |
| Add a catalyst | The activation energy is lowered | Increases, because more collisions are effective |
Measuring the rate of reaction
Loss of mass. When a gas escapes, the mass of the reaction mixture falls. Put a flask of marble chips and dilute hydrochloric acid on a balance and record the mass every 30 seconds. Carbon dioxide escapes and the reading drops. The steeper the curve on a mass-time graph, the faster the reaction.
Volume of gas collected. Use a gas syringe or an inverted measuring cylinder. Magnesium ribbon and dilute hydrochloric acid give off hydrogen, which you can collect and read off at intervals. The volume-time graph rises quickly at first and then levels off when the reaction finishes.
Disappearing cross. Mix sodium thiosulfate solution with dilute acid; a pale yellow precipitate of sulfur slowly forms and the mixture turns cloudy. Time how long it takes before a black cross drawn on a tile under the flask can no longer be seen. The rate is proportional to 1 / time.
Interpreting the graph. The gradient of a rate graph is the rate at that moment. A steep gradient means a fast reaction, and a curve that flattens to a plateau means the reaction has stopped because a reactant has been used up. A curve that starts steeper, or reaches the plateau sooner, shows a faster reaction, and the same final level means the same amount of product was formed.
- Measure the rate by the loss in mass when a gas escapes, or by the volume of gas collected.
- The gradient of the curve gives the rate at that instant.
- The steeper the initial gradient, the faster the reaction.
- A plateau means the reaction has finished because a reactant has been used up.
Reversible reactions and dynamic equilibrium
Some reactions are reversible: the products can react together to re-form the reactants. A reversible reaction is written with the equilibrium symbol ⇌. The forward reaction goes from left to right and the reverse reaction goes from right to left.
Heating blue hydrated copper(II) sulfate, CuSO4.5H2O, drives off the water of crystallisation and leaves white anhydrous copper(II) sulfate: CuSO4.5H2O(s) ⇌ CuSO4(s) + 5H2O(l). Adding water reverses the change and the blue colour returns. Cobalt(II) chloride behaves in the same way: pink hydrated CoCl2.6H2O turns blue anhydrous CoCl2 on heating, and the pink colour returns when water is added, which is why blue cobalt(II) chloride paper is used to test for water.
If a reversible reaction happens in a closed system, where nothing can escape, it eventually reaches dynamic equilibrium. At equilibrium the rate of the forward reaction equals the rate of the reverse reaction, so the concentrations of the reactants and products stop changing. Both reactions are still happening - dynamic means they have not stopped - they simply cancel each other out.
Equilibrium does not mean equal amounts. There may be much more product than reactant, or the other way round; what is constant is the concentrations, not their ratio. Changing the conditions moves the equilibrium to a new position. Raising the temperature favours the endothermic direction, because the system absorbs the extra heat. Raising the pressure favours the side with fewer gas molecules, because that relieves the pressure. Adding a reactant pushes the equilibrium towards the products. A catalyst speeds up the forward and reverse reactions equally, so it reaches equilibrium faster but does not change the position of equilibrium or the final yield.
| Change | Direction the equilibrium moves | Reason |
|---|---|---|
| Raise the temperature | Towards the endothermic reaction | The system absorbs the added heat |
| Lower the temperature | Towards the exothermic reaction | The system releases heat to replace what was lost |
| Raise the pressure | Towards the side with fewer gas molecules | This relieves the increased pressure |
| Lower the pressure | Towards the side with more gas molecules | This relieves the decreased pressure |
| Add a reactant | Towards the products | The extra reactant is used up as the forward reaction speeds up |
| Add a catalyst | No change to the position | It speeds up both directions equally |
The Haber process and the Contact process
The Haber process makes ammonia, which is used to make fertilisers: N2(g) + 3H2(g) ⇌ 2NH3(g). The nitrogen comes from the air and the hydrogen comes from methane, which is natural gas. The typical conditions are about 450 °C, 200 atm (20 000 kPa) and an iron catalyst.
The forward reaction is exothermic and goes from four gas molecules to two, so a lower temperature and a higher pressure would both give a better yield of ammonia at equilibrium. Neither extreme is used, because the conditions are a compromise. At a low temperature the rate would be far too slow, so 450 °C is chosen to keep the rate high enough. A very high pressure would give a better yield but needs thicker, more expensive equipment and is more dangerous, so 200 atm is used. The iron catalyst speeds up both directions equally, so the reaction reaches equilibrium faster without changing the yield.
The Contact process makes sulfur trioxide, which is used to make sulfuric acid: 2SO2(g) + O2(g) ⇌ 2SO3(g). The sulfur dioxide comes from burning sulfur or roasting sulfide ores, and the oxygen comes from the air. The typical conditions are about 450 °C, 2 atm (200 kPa) and a vanadium(V) oxide catalyst.
The forward reaction is again exothermic and goes from three gas molecules to two, so a lower temperature and a higher pressure would give a better yield of sulfur trioxide. A pressure of only 2 atm is used because the yield is already high enough at this pressure, so the extra cost and hazard of high pressure are not worth it. The temperature of 450 °C is again a compromise between a good yield and a usable rate, and the vanadium(V) oxide catalyst lowers the activation energy so the reaction is fast enough at that temperature.
- Haber: N2(g) + 3H2(g) ⇌ 2NH3(g), about 450 °C, 200 atm, iron catalyst.
- Contact: 2SO2(g) + O2(g) ⇌ 2SO3(g), about 450 °C, 2 atm, vanadium(V) oxide catalyst.
- High pressure and low temperature favour the product in both processes, because both forward reactions are exothermic and lose gas molecules.
- The chosen conditions are a compromise between yield, rate, cost and safety.
Redox: oxidation, reduction and redox agents
A redox reaction is one in which oxidation and reduction happen at the same time. If one substance is oxidised, another must be reduced, because the oxygen or the electrons lost by one are gained by the other.
At Core level, oxidation is gain of oxygen and reduction is loss of oxygen. In 2Mg + O2 -> 2MgO the magnesium is oxidised because it gains oxygen. At Supplement level you must also use electrons and oxidation numbers. Oxidation is loss of electrons and reduction is gain of electrons, remembered as OIL RIG. Oxidation also means an increase in oxidation number, and reduction means a decrease.
An oxidation number shows the charge an atom would have if the bonding were fully ionic. Four rules let you work one out: the oxidation number of an element in its uncombined state is zero; the oxidation number of a monatomic ion is the same as the charge on the ion; the sum of the oxidation numbers in a compound is zero; and the sum of the oxidation numbers in an ion equals the charge on the ion. Roman numerals in names, such as copper(II) oxide and iron(III) oxide, tell you the oxidation number of the metal. For example, in the manganate(VII) ion, MnO4-, let the oxidation number of manganese be x. Then x + 4(-2) = -1, so x = +7. In sulfur dioxide, SO2, x + 2(-2) = 0, so the sulfur is +4.
An oxidising agent is a substance that oxidises another substance and is itself reduced; it takes electrons from the other substance. Common oxidising agents are oxygen, chlorine, hydrogen peroxide and acidified potassium manganate(VII). A reducing agent is a substance that reduces another substance and is itself oxidised; it gives electrons to the other substance. Common reducing agents are hydrogen, carbon, carbon monoxide and reactive metals such as zinc and magnesium. The direction is the trap - the name tells you what the substance does to the other substance, not what happens to itself. Two colour changes let you spot a redox reaction: acidified potassium manganate(VII) is reduced from purple MnO4- to almost colourless Mn2+, so a solution that turns it from purple to colourless is a reducing agent, while aqueous potassium iodide is oxidised from colourless iodide ions to brown iodine, so a solution that turns it brown is an oxidising agent.
- Oxidising agent: oxidises another substance and is itself reduced.
- Reducing agent: reduces another substance and is itself oxidised.
- Acidified potassium manganate(VII) goes from purple to colourless when reduced.
- Aqueous potassium iodide goes from colourless to brown when oxidised to iodine.
| Oxidation | Reduction | |
|---|---|---|
| Oxygen | Gain of oxygen | Loss of oxygen |
| Electrons | Loss of electrons | Gain of electrons |
| Oxidation number | Increases | Decreases |
| Memory aid | OIL - Oxidation Is Loss of electrons | RIG - Reduction Is Gain of electrons |
Key terms you must be able to define
- Activation energy, Ea
- The minimum energy that colliding particles must have for a reaction to take place.
- Catalyst
- A substance that increases the rate of a reaction by providing an alternative pathway with a lower activation energy, and is not changed or used up by the reaction.
- Dynamic equilibrium
- The state of a reversible reaction in a closed system when the rate of the forward reaction equals the rate of the reverse reaction, so the concentrations of the reactants and products no longer change.
- Oxidation
- Gain of oxygen, loss of electrons, or an increase in oxidation number.
- Reduction
- Loss of oxygen, gain of electrons, or a decrease in oxidation number.
- Oxidation number
- The charge an atom would have if the bonding in the compound or ion were fully ionic.
- Oxidising agent
- A substance that oxidises another substance and is itself reduced.
- Reducing agent
- A substance that reduces another substance and is itself oxidised.
Applied to the real world
Cambridge sets chemistry in unfamiliar contexts - an industrial plant, a water-treatment works, a hospital, a laboratory. Use these as models for how to apply the chemistry, then write your own.
The Haber process makes ammonia from nitrogen and hydrogen: N2(g) + 3H2(g) ⇌ 2NH3(g). The nitrogen comes from the air and the hydrogen comes from methane. The plant runs at about 450 °C and 200 atm over an iron catalyst. The conditions are a compromise: a lower temperature and a higher pressure would give more ammonia at equilibrium, but the rate would be too slow and the plant too expensive and dangerous to run, so the chosen conditions give a fast enough reaction at an acceptable yield.
The Contact process makes sulfur trioxide, which is used to make sulfuric acid: 2SO2(g) + O2(g) ⇌ 2SO3(g). The sulfur dioxide comes from burning sulfur or roasting sulfide ores, and the oxygen from the air. The converter runs at about 450 °C and 2 atm over a vanadium(V) oxide catalyst. The forward reaction is exothermic and goes from three gas molecules to two, so a lower temperature and a higher pressure would give a better yield, but 450 °C is used to keep the rate high.
A student measures the rate of the reaction between magnesium and dilute hydrochloric acid by collecting the hydrogen in a gas syringe and reading the volume every 20 seconds. The gradient of the volume-time graph gives the rate at that moment. The gradient is steepest at the start, when the acid is most concentrated, and flattens to zero once the magnesium has all reacted.
A catalytic converter contains a thin coating of platinum and rhodium. These catalysts lower the activation energy of the reactions that convert carbon monoxide to carbon dioxide and nitrogen oxides to nitrogen and oxygen, so the harmful gases are removed at normal exhaust temperatures. Without the catalyst the reactions would be far too slow to matter, and because a catalyst is not used up it lasts the life of the car.
Rusting is a slow redox reaction in which iron is oxidised by oxygen in the presence of water to form hydrated iron(III) oxide. Painting or greasing the iron keeps out the oxygen and water, so the oxidation cannot take place. The same chemistry on a large scale is why steel bridges and ships are protected with paint or with a sacrificial metal such as zinc.
Flashcards
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Exam-style questions
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Exam technique for this topic
- Explain rate changes with collision theory, not with vague phrases. Say what happens to the number of particles per unit volume, the frequency of collisions and the energy of the collisions.
- A catalyst lowers the activation energy and is not used up. Writing that a catalyst is used up, or that it gives the particles more energy, loses the mark.
- For equilibrium, give both conditions: the rate of the forward reaction equals the rate of the reverse reaction, and the concentrations of the reactants and products are constant. Equilibrium does not mean the reactions have stopped.
- A catalyst never changes the position of equilibrium or the final yield, only the time taken to reach it. This is a common mark-scheme point in Haber and Contact questions.
- In Haber and Contact questions, explain the compromise between rate and yield, and mention the cost and safety problems of using very high pressures.
- For redox, use OIL RIG, and remember that the oxidising agent is itself reduced while the reducing agent is itself oxidised. Name both the substance oxidised and the substance reduced.
Why students lose marks here
Where this fits in IGCSE Chemistry
This page is one topic of Cambridge IGCSE Chemistry 0620 / 0971. IGCSE Chemistry is the course home: every area and every topic in Cambridge's own order, the papers you sit and what each one tests, and the exam-practice tools. The full topic list, with each topic linked to its revision page, is on the IGCSE Chemistry syllabus page.