AS & A Level Marine Science · Area 2 · A Level content

Cell structure, movement of substances, gas exchange and osmoregulation

Every marine organism is a cell or a collection of cells, and everything else in physiology follows from how substances cross the membrane that surrounds each one. This page takes you from the organelles and the fluid mosaic model, through diffusion, facilitated diffusion, osmosis and active transport, to surface area to volume ratio, the three methods of gas exchange seen in coral polyps, grouper and tuna, and the osmoregulation of mussels, tuna and salmon. Marks are lost here by describing a structure without its function, by getting the direction of water movement the wrong way round, and by explaining gas exchange or osmoregulation without linking it to the organism's habitat and how it moves.

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Syllabus coverage

  • Recognise the cell surface membrane, nucleus, rough and smooth endoplasmic reticulum, ribosomes, Golgi body, mitochondria, chloroplasts, cell wall and large permanent vacuole, and outline their functions
  • Describe the fluid mosaic model of membrane structure, including the structure and functions of phospholipids and proteins, limited to carrier and channel proteins
  • Understand the selectively permeable nature of membranes and relate it to the active and passive transport of substances across a membrane
  • Describe and interpret photomicrographs, electron micrographs and drawings of typical animal and plant cells, and recall and apply the formula: magnification = image size / actual size
  • Make observations, drawings and magnification calculations from unfamiliar structures or specimens
  • Describe and explain diffusion, facilitated diffusion, osmosis and active transport
  • Understand water potential and explain how dissolved solutes affect the water potential of a solution or cell (solute potential is not required)
  • Calculate surface areas and volumes of simple shapes to show that surface area to volume ratio decreases with increasing size
  • Explain the movement of water between cells and solutions of different water potentials, and the different effects on plant and animal cells
  • Understand that the raw materials and waste products of respiration must be moved to and from the surface of organisms
  • Discuss how surface area to volume ratio depends on the size and shape of an organism, and relate this to the need for specialised gas exchange surfaces and transport systems in larger animals
  • Describe gas exchange by simple diffusion, pumped ventilation and ram ventilation, using coral polyps, grouper and tuna
  • Relate an organism's method of gas exchange to its habitat and motility
  • Explain osmoconformer and osmoregulator with reference to marine mussels and tuna, and euryhaline and stenohaline with reference to salmon, marine mussels and tuna

Part of the AS & A Level Marine Science syllabus 9693.

Osmoregulation at the gillCounter-current exchangeMarine bony fishgill lamellawater flowblood flowwater outsalt insalt outactive transportWater and blood flow in opposite directions
Osmoregulation at the gill: water is lost passively to the sea, salt enters passively and is excreted actively by chloride cells, with blood and water flowing in opposite directions.

The organelles of a typical cell

All living organisms are formed of units called cells, and every cell has the same basic organisation. Each one is separated from its immediate environment by the cell surface membrane, and inside it the cytoplasm contains the genetic material and a set of membrane-bound structures called organelles. The same organelles turn up again and again in marine organisms: the gill cells of a mussel, a cell in a seagrass leaf and a white blood cell in a tuna all have a nucleus, mitochondria and a membrane, even though they do very different jobs.

The organelles work as a production line. The nucleus holds the DNA and so controls which proteins the cell makes; the ribosomes are the machines that actually assemble those proteins; the rough endoplasmic reticulum is the network of membranes the new proteins are threaded into and carried along; the Golgi body modifies and packages them into vesicles; and the vesicles fuse with the cell surface membrane to release their contents outside the cell, or to deliver membrane proteins into it. Once you can follow that route, the function of each organelle is easy to remember.

Plant cells differ from animal cells in three structures. A plant cell has a cell wall of cellulose outside the membrane, one large permanent vacuole filled with cell sap that keeps the cell firm, and chloroplasts for photosynthesis. Animal cells have none of these, which is why an animal cell can change shape and squeeze through a capillary while a plant cell cannot, and why a plant cell does not burst when it takes in water.

StructureFunctionWhat to look for
Cell surface membraneControls the entry and exit of substances; partially permeableThe boundary of every cell; a single dark line in an electron micrograph, too thin to see clearly with a light microscope
NucleusContains the chromosomes (DNA); controls the activities of the cellLarge, round, with a double membrane (nuclear envelope) and pores; a darker nucleolus inside
Rough endoplasmic reticulumFolds and transports proteins made by the ribosomes on its surfaceLayers of parallel membranes studded with ribosomes
Smooth endoplasmic reticulumSynthesises lipids, including steroids, and transports themThe same layered membranes, but without ribosomes
RibosomesSite of protein synthesisVery small granules, free in the cytoplasm or on the rough ER; visible only with an electron microscope
Golgi bodyModifies proteins, packages them into vesicles and prepares them for secretionA stack of flattened, curved sacs with vesicles budding off the edges
MitochondriaSite of aerobic respiration; releases energy as ATPOval, with an inner membrane folded into cristae that give a large surface area
ChloroplastsSite of photosynthesis; contains chlorophyllGreen in a light micrograph; in an electron micrograph, stacked thylakoids (grana) in a stroma, inside a double membrane
Cell wallGives strength and support and prevents the cell bursting; fully permeableA thick layer outside the cell surface membrane; cellulose in plant cells
Large permanent vacuoleStores cell sap and maintains turgor pressure, keeping the cell firmA large pale area filling much of a plant cell, bounded by the tonoplast
The syllabus says recognise these structures and outline their functions, so a labelled diagram alone is never enough. Every organelle you name in an answer needs its job attached to it.

The cell surface membrane and the fluid mosaic model

The membrane is far too thin to see with a light microscope, but its structure explains everything it does. It is built from phospholipids, each of which has a hydrophilic head containing a phosphate group and two hydrophobic tails made of fatty acids. In water the molecules arrange themselves tail to tail, with the heads facing outwards into the watery environment on both sides, and this double layer is the phospholipid bilayer.

The bilayer is the reason membranes are selectively permeable. Very small molecules such as oxygen and carbon dioxide, and non-polar substances, dissolve in the lipid and pass straight through. Water molecules are small enough to pass between the phospholipids.

Ions and larger polar molecules such as glucose and amino acids are repelled by the hydrophobic interior and cannot cross the bilayer on their own. They can only get through with the help of proteins.

Proteins are scattered through the bilayer like tiles in a mosaic, some sitting on the surface and some spanning the whole width, and because both the phospholipids and the proteins can move sideways, the model is described as fluid. Channel proteins form water-filled pores through the membrane, so small ions and water-soluble molecules can pass through.

Carrier proteins bind to a specific substance on one side and change shape to carry it across to the other, and they are also the proteins that use ATP to pump substances against a concentration gradient. This combination of a fluid bilayer and a shifting mosaic of proteins is the fluid mosaic model.

  • Phospholipid: hydrophilic phosphate head, two hydrophobic fatty acid tails.
  • Bilayer: tails inward, heads outward, so both surfaces are compatible with water.
  • Selectively permeable: oxygen, carbon dioxide and other small non-polar molecules cross freely; ions and large polar molecules cannot cross the lipid and need proteins.
  • Channel protein: a water-filled pore through the membrane, used by small ions and water-soluble molecules.
  • Carrier protein: binds a specific molecule, changes shape and releases it on the other side; can move substances down the gradient, or use ATP to move them against it.
  • Fluid: the phospholipids and proteins move laterally within the membrane.
  • Mosaic: the proteins are embedded in the bilayer in a patchy, scattered pattern.
Fluid mosaic refers to two different things - fluid because the components move, mosaic because the proteins are scattered through the lipid. Answers that only define one half of the name lose the mark.

Microscopes, magnification and interpreting cell images

Cells were discovered with a light microscope, which shines light through a stained specimen. A light microscope is cheap, it can be used on living cells, and it magnifies up to about 1500 times, but its resolution is limited to about 200 nm, so mitochondria and ribosomes appear only as faint dots or not at all.

The electron microscope uses a beam of electrons instead of light, which gives a much shorter wavelength and a resolution small enough to show the internal membranes of an organelle. Electron micrographs are always black and white, because the image is formed by electrons rather than light.

All magnifications are worked out from the same relationship: magnification = image size / actual size. The formula is rearranged for whatever the question gives you - actual size = image size / magnification, and image size = actual size x magnification - and you must convert the two sizes into the same unit before you divide. There are 1000 µm in a millimetre and 1000 nm in a µm, and mixing these up is the single most common arithmetic error in the paper.

Reading an unfamiliar micrograph is a skill of its own, because you may be shown a cell from an organism you have never studied. Work from the largest, most obvious features inwards: a thick rigid outer layer means a cell wall, so the cell is a plant or algal cell; a stack of parallel membranes with dots on them is rough ER; oval bodies with internal folds are mitochondria; a large pale area bounded by a single membrane is a vacuole. Then use the scale bar, or the stated magnification, to check that the sizes are sensible.

When you make your own drawing, use a sharp pencil, draw continuous unbroken lines with no shading, keep the proportions correct, and add straight label lines that do not cross, with the labels written outside the drawing. Give the drawing a title and state the magnification.

  • magnification = image size / actual size - the same formula written three ways.
  • 1 mm = 1000 µm; 1 µm = 1000 nm.
  • A scale bar gives the actual size directly: measure the bar, then measure the structure, and divide.
  • Plant cell clues: cell wall, chloroplasts, large permanent vacuole, regular shape.
  • Animal cell clues: no wall, irregular shape, small or no vacuole, many mitochondria if the cell is active.
  • Drawing rules: pencil, continuous lines, no shading, correct proportions, straight uncrossed label lines, title and magnification.
If you are givenRearrange toWatch out for
Image size and magnificationActual size = image size / magnificationThe answer is smaller than the image; convert to µm at the end if asked
Actual size and magnificationImage size = actual size x magnificationMultiply, do not divide; keep the units consistent
Image size and actual sizeMagnification = image size / actual sizeMagnification has no units - it is a ratio, so write 'x 4000', not '4000 µm'
A scale bar and an imageMeasure both in mm, then actual size = structure / bar x bar valueMeasure with a ruler on the printed page, then convert
If your magnification comes out as a tiny fraction such as 0.02, you divided the wrong way round. A microscope image is always larger than the real object, so a magnification must be greater than 1.

Diffusion, facilitated diffusion and active transport

Diffusion is the net movement of particles from a region of higher concentration to a region of lower concentration, down a concentration gradient, and it happens because the particles are in constant random motion. It needs no energy from the cell, so it is a passive process. The rate depends on the steepness of the gradient, the distance or thickness the particles must cross, the surface area available, the temperature and the size of the particles.

In a marine organism, oxygen diffusing from sea water into a gill and carbon dioxide diffusing out of it are both simple diffusion.

Facilitated diffusion is still passive, and it still moves substances down their concentration gradient, but it uses a channel or carrier protein in the membrane. It is needed for substances that cannot dissolve in the phospholipid bilayer - ions such as sodium and chloride, and polar molecules such as glucose and amino acids. Each protein is specific to one substance or one group of substances, and because there is a limited number of them, the rate levels off at high concentrations when every protein is occupied.

Active transport moves substances against their concentration gradient, from a lower concentration to a higher one. It uses carrier proteins and it requires metabolic energy in the form of ATP from respiration, so it is the only one of the four processes that can make a gradient steeper rather than letting it run down. It is how a gill cell takes up the last traces of an ion from very dilute water, and how marine fish pump excess salts out of their bodies against a gradient.

ProcessDirectionEnergy neededMembrane proteinExample
DiffusionDown the concentration gradientNone - passiveNoneOxygen entering a cell across the body surface, carbon dioxide leaving it
Facilitated diffusionDown the concentration gradientNone - passiveChannel or carrier proteinGlucose or an amino acid entering a cell through a carrier protein
OsmosisDown the water potential gradientNone - passiveNone, though water also passes through channel proteinsWater entering a gill cell from dilute sea water
Active transportAgainst the concentration gradientATP from respirationCarrier proteinA gill cell pumping chloride ions out of the blood into the sea water
The difference between facilitated diffusion and active transport is not the protein - both use one. It is the direction and the energy: active transport goes against the gradient and costs ATP, facilitated diffusion goes down it and costs nothing.

Osmosis and water potential

Water potential is a measure of the relative number of water molecules in a solution and their freedom to move. It is given the symbol psi and measured in units of pressure, usually kilopascals. Pure water has a water potential of zero. Dissolving any solute in water lowers the water potential, because the solute particles get in the way of the water molecules and reduce their freedom to move, so every solution has a negative water potential and the more concentrated the solution, the more negative it is.

Osmosis is the net movement of water molecules from a region of higher water potential (less negative, closer to zero) to a region of lower water potential (more negative), through a partially permeable membrane. It is a passive process, a special case of diffusion that applies to water only. Water therefore always moves towards the more concentrated solution, and the size of the movement depends on the size of the difference between the two water potentials.

In a plant cell, water entering the vacuole pushes the cytoplasm and membrane outwards against the cell wall. The wall pushes back, and the cell becomes turgid, which is what keeps leaves and algal fronds firm. Water leaving has the opposite effect: the vacuole shrinks, the cytoplasm and membrane pull away from the cell wall, and the cell is plasmolysed.

In an animal cell there is no wall to push back, so a cell in a solution of higher water potential swells and may burst, and a cell in a solution of lower water potential shrinks and becomes distorted.

External solutionWater movesPlant cellAnimal cell
Higher water potential than the cell (e.g. fresh water)Into the cellVacuole swells, cell becomes turgid; the wall prevents burstingCell swells and may burst (lyse), because there is no cell wall
Same water potential as the cellNo net movementCell is flaccid; at the point where plasmolysis is just about to start it is at incipient plasmolysisCell keeps its normal volume and shape
Lower water potential than the cell (e.g. concentrated sea water)Out of the cellVacuole shrinks, membrane pulls away from the wall - plasmolysisCell shrinks and becomes crenated; the cytoplasm becomes more concentrated
Water potential is a negative scale with zero at the top, so 'high' water potential means close to zero and 'low' means a large negative number. Water moves from high to low, which means from the less negative solution to the more negative one. Say it that way in an answer and you cannot go wrong.

Surface area to volume ratio and the need for exchange surfaces

As a shape gets bigger, its surface area increases in proportion to the square of its length, but its volume increases in proportion to the cube. The result is that surface area to volume ratio falls as size increases: a cube 1 cm on each side has a ratio of 6:1, and a cube 4 cm on each side has a ratio of only 1.5:1. The same arithmetic applies to organisms, and it is the single most important idea in the whole of this topic.

The surface is where substances are exchanged, and the volume is the living tissue that needs supplying. A small organism therefore has a large surface for every unit of tissue it has to feed, and the distance from its surface to its centre is short, so diffusion alone can supply its oxygen and remove its carbon dioxide.

A large organism has the opposite problem: a small surface for a large volume, and a long diffusion distance to the middle of the body. Diffusion through the body surface becomes far too slow, and the organism needs two things - a specialised exchange surface with a large area and a thin barrier, and a transport system to carry gases between that surface and the tissues.

Shape matters as well as size. An organism that is long, flat and thin, such as a ribbon-shaped worm or a flattened frond of seaweed, keeps a short diffusion distance from the water to every cell even when it is large overall. An organism that is compact and rounded, such as a tuna, cannot, which is why the tuna needs gills with a huge surface area and a circulation to match.

Every efficient exchange surface shares the same four features: a large surface area, a thin barrier so the diffusion distance is short, a moist, permeable surface, and a steep concentration gradient maintained by ventilation and by the blood carrying substances away.

  • Cube: surface area = 6 x length²; volume = length³; ratio = 6 / length.
  • Sphere: surface area = 4 x pi x r²; volume = 4/3 x pi x r³; ratio = 3 / r.
  • Cylinder (closed): surface area = (2 x pi x r²) + (2 x pi x r x h); volume = pi x r² x h.
  • Always calculate both values and divide the surface area by the volume, then write the answer as a ratio to 1.
  • Agar block experiment: cubes of different sizes in acid, or in a dye, show that the smallest block changes colour throughout first, because it has the largest surface area to volume ratio and the shortest diffusion distance to its centre.
Cube sideSurface areaVolumeSurface area : volume
1 cm6 cm²1 cm³6 : 1
2 cm24 cm²8 cm³3 : 1
3 cm54 cm²27 cm³2 : 1
4 cm96 cm²64 cm³1.5 : 1
A question that asks you to explain the effect of size wants the arithmetic and the consequence: the ratio falls, so the surface is no longer enough for the volume, so a specialised exchange surface and a transport system are needed.

Gas exchange: simple diffusion, pumped ventilation and ram ventilation

Aerobic respiration needs oxygen and produces carbon dioxide, and both gases have to cross the body surface, in one direction or the other. This exchange is gas exchange. The gases move by diffusion, so they move down their concentration gradients: oxygen is used up inside the organism, which keeps the oxygen concentration in the tissues lower than in the water, and carbon dioxide is produced, which keeps its concentration higher inside than outside.

Anything that maintains those gradients speeds the process up.

Simple diffusion across the whole body surface is enough for small, thin marine organisms with a large surface area to volume ratio and a low demand for oxygen. A coral polyp is the classic example: it is small and its tissues are thin, so every cell is close to the sea water and no cell is more than a short distance from the surface; it is sessile, so its oxygen demand is low and fairly constant; and it has no gills, no blood system and no ventilation mechanism. Water movements over the colony, helped in some species by beating cilia, keep the water around the polyp refreshed so that the gradients do not fade.

Pumped ventilation is used by fish that can afford to stop moving. A grouper is an ambush predator that lies still on the reef for long periods, then makes a short, explosive strike. It draws water in through the mouth by expanding the buccal cavity, closes the mouth, and then raises the floor of the mouth and squeezes the opercula so that the water is pushed over the gills.

Because the pump works whether or not the fish is moving, the grouper can ventilate while stationary, which is exactly what its hunting method requires. The cost is that pumping uses energy, and the volume of water moved per minute is limited.

Ram ventilation is used by fish that never stop swimming. A tuna swims with its mouth open, and the forward movement forces water through the mouth and over the gills, so no pumping muscles are needed and the faster the fish swims, the more water passes over the gills. Adult tuna cannot ventilate by pumping effectively, so they are obligate ram ventilators and must keep swimming all their lives, even when resting.

This suits a fast, continuous cruiser in the open ocean with a very high oxygen demand, and it is paired with a large gill surface area, thin gill lamellae and a powerful circulation. The water and the blood flow in opposite directions across the gill lamellae, which keeps a diffusion gradient along the whole length of the gill rather than only at one end.

OrganismMethodHow it worksHabitat and motility link
Coral polypSimple diffusion across the body surfaceThin tissue with a large surface area to volume ratio, no specialised surface, no ventilation mechanismSessile, colonial, low and steady oxygen demand in warm, well-moved tropical water; being small keeps the diffusion distance short
GrouperPumped ventilationMuscles expand the buccal cavity to suck water in, then force it over the gills and out under the operculaSits still on the reef as an ambush predator, so it must be able to ventilate without swimming; short bursts of activity
TunaRam ventilationSwims with the mouth open, so forward movement drives water over the gills; no pumping neededContinuous fast cruising in the open ocean with a very high oxygen demand; an obligate ram ventilator that cannot stop swimming
The last mark in any gas exchange question is usually the link to habitat and motility. Ram ventilation is not just a different method - it is the only option for a fish that swims fast all its life, and pumped ventilation is what allows a fish to breathe while it waits for its prey.

Osmoregulation: conformers, regulators, euryhaline and stenohaline

Sea water contains about 35 g of dissolved salts per kilogram, roughly 3.5%, mostly sodium and chloride ions with smaller amounts of magnesium, sulfate, potassium and calcium. Because it is so concentrated, sea water has a fairly low (negative) water potential.

The body fluids of most marine invertebrates have almost the same concentration as sea water, so there is little or no water potential gradient between the animal and the sea, and water does not tend to flood in or drain out. That is why many marine species can survive without regulating their water content at all.

A species whose body fluid concentration simply follows the concentration of the surrounding water is an osmoconformer. A marine mussel is the example: its body fluids are isosmotic with sea water, it does not spend energy holding them at a different concentration, and its cells tolerate the water that moves in or out when the tide brings fresher or saltier water over it.

A species that holds its body fluids at a different concentration from the surrounding water, by active transport, is an osmoregulator. A tuna is the example: its body fluids are far more dilute than sea water, at roughly a third of the concentration, so it is constantly losing water by osmosis and gaining salts, and it must spend energy correcting both.

Salinity tolerance is a separate idea from regulation. Stenohaline species tolerate only a narrow range of salinity, and most marine organisms are stenohaline, because their cells and enzymes are adapted to a nearly constant internal concentration - the tuna is an example. Euryhaline species tolerate a wide range of salinity - the marine mussel is one, which is why it can live in estuaries, and the salmon is the other, because it spends part of its life in fresh water and part in the sea.

A species can therefore be a euryhaline osmoconformer (the mussel) or a euryhaline osmoregulator (the salmon), and those two labels are not interchangeable.

Osmoregulation in the salmon. Salmon hatch in fresh water, migrate to sea to feed and grow, and return to fresh water to spawn, so they must reverse their physiology twice. In fresh water the body fluids are more concentrated than the surrounding water, so water enters by osmosis, mainly across the gills.

The salmon therefore drinks little, produces large volumes of dilute urine, and actively takes up sodium and chloride ions from the water across its gill cells. In sea water the situation is reversed: the body fluids are more dilute than the sea, so water is lost by osmosis.

The salmon now drinks sea water, absorbs the water in its gut, excretes the surplus ions actively across its gills, and produces only a small volume of urine, so that water is conserved. The switch between the two sets of mechanisms happens during the migration, when the gills and kidneys remodel.

MediumWater potential of the water compared with the bloodMovement of waterWhat the salmon does
Fresh waterHigher (less negative) than the bloodWater enters the body by osmosis, mainly across the gillsDrinks little or nothing; produces large volumes of dilute urine; actively takes up sodium and chloride ions across the gills
Sea waterLower (more negative) than the bloodWater leaves the body by osmosis, mainly across the gillsDrinks sea water and absorbs water in the gut; excretes excess ions actively across the gills; produces a small volume of urine
Conformer and regulator describe what the animal does; euryhaline and stenohaline describe what it can tolerate. Keeping those two pairs apart is the difference between two marks and four in a question on this section.

Key terms you must be able to define

Fluid mosaic model
The model of membrane structure in which a bilayer of phospholipids, with hydrophilic heads facing outwards and hydrophobic tails facing inwards, has proteins scattered through it. It is fluid because the components move laterally, and a mosaic because the proteins are arranged in a patchy pattern.
Selectively permeable
Allowing some substances to cross a membrane freely while restricting others. Small non-polar molecules such as oxygen and carbon dioxide cross the phospholipid bilayer; ions and large polar molecules need channel or carrier proteins.
Channel and carrier proteins
Membrane proteins that allow substances the phospholipid bilayer would block to cross. Channel proteins form water-filled pores through the bilayer and are used by small ions and water-soluble molecules. Carrier proteins bind a specific substance and change shape to move it across, and are also the proteins that use ATP in active transport.
Diffusion
The net movement of particles from a region of higher concentration to a region of lower concentration, down a concentration gradient. It is passive and needs no energy from the cell.
Facilitated diffusion
The passive movement of substances down a concentration gradient through specific channel or carrier proteins in the membrane, used by ions and polar molecules that cannot cross the phospholipid bilayer.
Active transport
The movement of substances across a membrane against their concentration gradient, using carrier proteins and energy provided by the cell as ATP from respiration.
Water potential
A measure of the relative number of water molecules in a solution and their freedom to move. Pure water has a water potential of zero; dissolved solutes lower it, so every solution has a negative water potential and the more concentrated the solution the more negative it is.
Osmosis
The net movement of water molecules from a region of higher water potential to a region of lower water potential, through a partially permeable membrane. It is a passive process and a special case of diffusion.
Surface area to volume ratio
The surface area of an object divided by its volume. It falls as an object gets larger, because surface area increases with the square of length while volume increases with the cube, which is why large organisms need specialised exchange surfaces and transport systems.
Pumped ventilation
Ventilation of the gills by muscular pumping, in which water is drawn into the buccal cavity and then forced over the gills, so that a fish such as a grouper can exchange gases while it is stationary.
Ram ventilation
Ventilation of the gills by the forward movement of a swimming fish with its mouth open, so that water is forced over the gills without muscular pumping. Tuna are obligate ram ventilators and must keep swimming.
Osmoconformer and osmoregulator
An osmoconformer has body fluids whose concentration follows that of the surrounding water, so it does not actively regulate its water content - for example a marine mussel, which is isosmotic with sea water. An osmoregulator holds its body fluids at a different concentration from the surrounding water by active transport - for example a tuna, whose body fluids are far more dilute than sea water.
Euryhaline
Tolerating a wide range of salinity. Examples are the salmon, which moves between fresh water and sea water, and the marine mussel, which lives in estuaries.
Stenohaline
Tolerating only a narrow range of salinity. Most marine organisms are stenohaline, including the tuna, because their cells and enzymes are adapted to a nearly constant internal concentration.

Applied to the sea

9693 marks the named marine example and the data in front of you. These show how to move from a definition to a worked marine case, then you do the same with the examples your teacher gives you.

Ram ventilation: the tuna

Tuna are fast, continuous swimmers of the open ocean, with one of the highest oxygen demands of any fish. They use ram ventilation: they swim with the mouth open and the opercula held out, so water flowing past the body is forced over the gills without any pumping, and because adult tuna cannot ventilate effectively by pumping they are obligate ram ventilators that must keep swimming all their lives. Everything about the fish supports this - a streamlined body, a very large gill surface area with fine thin lamellae, mitochondria-rich swimming muscle and a large heart - which is why the tuna is the example to use when a question asks you to link gas exchange to habitat and motility.

Pumped ventilation: the grouper

Groupers are ambush predators of coral reefs that rest on the reef and make a single fast strike when prey comes close. Because they are often not moving at all, they ventilate by pumping: muscles expand the buccal cavity to draw water in through the mouth, the mouth closes, and the water is squeezed out over the gills under the opercula. The pump costs energy, and the grouper can also ram ventilate when it swims, but being able to breathe while stationary is exactly what its hunting method requires.

Simple diffusion: the coral polyp

A coral colony is built of thousands of small polyps, each only a few millimetres across and with tissue only a few cells thick. Because each polyp is small its surface area to volume ratio is very large and no cell is far from the sea water, so oxygen diffuses in and carbon dioxide diffuses out across the whole body surface, with no gills, no blood system and no ventilation mechanism. Being sessile it has a low and steady oxygen demand, and water moving over the colony, helped in some species by beating cilia, keeps the gradients in place - the clearest example in the syllabus of an organism that needs nothing more than simple diffusion.

Osmoregulation across a life cycle: the salmon

The salmon hatches in fresh water, migrates to the sea to feed and grow, and returns to a river to spawn, so it has to solve both osmotic problems in one lifetime. In fresh water its body fluids are more concentrated than the river, so water floods in by osmosis; it produces large volumes of dilute urine, drinks little, and takes up salts actively across its gills. In sea water its body fluids are more dilute than the sea, so it loses water; it drinks sea water, absorbs the water in its gut, excretes excess ions across its gills and produces very little urine, and the gill cells and kidney remodel during the migration between the two.

A euryhaline osmoconformer: the marine mussel

The marine mussel lives attached to rocks and pilings on the shore and in estuaries, where the salinity can change sharply with every tide and every spell of rain. Its body fluids are isosmotic with sea water, so it is an osmoconformer - it does not hold its internal concentration steady against the sea, and it does not spend energy doing so - and because the water around it can range from nearly fresh to fully saline it is also euryhaline, with cells that tolerate the swelling and shrinking that follow. The mussel therefore carries two labels at once, euryhaline and osmoconformer, while the tuna carries the opposite two, stenohaline and osmoregulator.

Flashcards

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Q1State the functions of the nucleus, the mitochondria and the chloroplasts.
Nucleus: contains the chromosomes (DNA) and so controls the activities of the cell. Mitochondria: site of aerobic respiration, releasing energy as ATP; the inner membrane is folded into cristae to give a large surface area. Chloroplasts: site of photosynthesis, containing chlorophyll arranged in stacks of thylakoids (grana) in the stroma.
Q2What do the ribosomes, the rough endoplasmic reticulum, the smooth endoplasmic reticulum and the Golgi body do?
Ribosomes are the site of protein synthesis. Rough ER has ribosomes on its surface and folds and transports the proteins they make. Smooth ER has no ribosomes and synthesises and transports lipids. The Golgi body modifies proteins, packages them into vesicles and prepares them for secretion.
Q3What are the three structures a plant cell has that an animal cell does not, and what does each do?
A cellulose cell wall, which gives strength and support and stops the cell bursting. A large permanent vacuole, filled with cell sap, which maintains turgor and keeps the cell firm. Chloroplasts, which carry out photosynthesis. Animal cells have none of these, which is why they can change shape and why they burst in pure water.
Q4Describe the fluid mosaic model of the cell surface membrane.
A bilayer of phospholipids, with hydrophilic phosphate heads facing outwards into the watery environment and hydrophobic fatty acid tails facing inwards. Proteins are scattered through the bilayer, some on the surface and some spanning it - channels forming water-filled pores, carriers binding and changing shape to move substances. It is fluid because the phospholipids and proteins move laterally, and a mosaic because of the scattered protein pattern.
Q5State the magnification formula and the unit conversions you need for it.
magnification = image size / actual size, rearranged to actual size = image size / magnification and image size = actual size x magnification. 1 mm = 1000 µm and 1 µm = 1000 nm. Convert both sizes to the same unit before dividing; the magnification itself has no units, so it is written as 'x 4000'.
Q6Define diffusion and name the factors that affect its rate.
The net movement of particles from a region of higher concentration to a region of lower concentration, down a concentration gradient, by the random motion of the particles; it is passive and needs no ATP. The rate depends on the steepness of the concentration gradient, the distance or thickness to be crossed, the surface area available, the temperature and the size of the particles.
Q7Contrast facilitated diffusion with active transport.
Facilitated diffusion is passive and moves substances down their concentration gradient through specific channel or carrier proteins, with no ATP. Active transport moves substances against their concentration gradient through carrier proteins and uses ATP from respiration. Both use membrane proteins; only active transport can build up a gradient rather than let it run down.
Q8Define water potential and state its value for pure water.
A measure of the relative number of water molecules in a solution and their freedom to move, measured in units of pressure and given the symbol psi. Pure water has a water potential of zero. Dissolved solutes lower it, so every solution has a negative water potential, and the more concentrated the solution the more negative it is.
Q9What happens to a plant cell and to an animal cell in pure water, and in a solution of lower water potential?
In pure water water enters both by osmosis: the plant cell becomes turgid because the cell wall pushes back, while the animal cell swells and may burst because it has no wall. In a solution of lower water potential water leaves both: the plant cell plasmolyses, with the membrane pulling away from the wall, and the animal cell shrinks and becomes crenated.
Q10Why does surface area to volume ratio fall as an organism gets bigger, and why does that matter?
Surface area increases with the square of length while volume increases with the cube, so the ratio falls - a 1 cm cube is 6:1 and a 4 cm cube is 1.5:1. The surface is where exchange happens and the volume is the tissue that needs supplying, so a large organism cannot supply itself by diffusion over its body surface and needs a specialised exchange surface with a large area and a thin barrier, plus a transport system.
Q11How do a coral polyp, a grouper and a tuna each obtain oxygen?
The coral polyp uses simple diffusion across its whole body surface, because it is small and thin with a large surface area to volume ratio, it is sessile with a low oxygen demand, and it has no gills or ventilation mechanism. The grouper uses pumped ventilation, drawing water into the buccal cavity and forcing it over the gills, so it can breathe while stationary on the reef. The tuna uses ram ventilation, swimming with its mouth open so that forward movement drives water over the gills; it is an obligate ram ventilator that must keep swimming.
Q12Define osmoconformer, osmoregulator, euryhaline and stenohaline, and give the syllabus examples.
Osmoconformer: body fluid concentration follows the surrounding water - marine mussel. Osmoregulator: holds body fluids at a different concentration by active transport - tuna, whose body fluids are about a third as concentrated as sea water. Euryhaline: tolerates a wide range of salinity - salmon and marine mussel. Stenohaline: tolerates a narrow range - tuna. The salmon is a euryhaline osmoregulator; the mussel is a euryhaline osmoconformer.
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Exam-style questions

8 questions, 27 marks. Write your answer, then reveal the mark scheme and tick each point you actually made. Answering honestly here is what makes the rest of the site useful.

StateAO11 mark
State the formula used to calculate the magnification of a microscope image.

Mark scheme — tick each point you actually made

Examiner tip: One mark for the relationship, not for a worked example. Do not write 'times 1000' - that is a unit conversion, not the formula.
DefineAO12 marks
Define the term osmosis.

Mark scheme — tick each point you actually made

Examiner tip: Both halves are needed: the direction in terms of water potential, and the partially permeable membrane. Writing 'from a high concentration of water to a low concentration of water' is accepted only if the membrane is also named.
ExplainAO23 marks
Explain why an increase in the size of an organism increases its need for a specialised gas exchange surface.

Mark scheme — tick each point you actually made

Examiner tip: The arithmetic on its own scores one mark. The other two come from saying what the ratio means for supply and demand, and from mentioning the diffusion distance.
DescribeAO14 marks
Describe the fluid mosaic model of the cell surface membrane.

Mark scheme — tick each point you actually made

Examiner tip: The syllabus limits protein function to carrier and channel proteins, so spend your marks on those two and on the arrangement of the phospholipids. A description that never explains why the model is 'fluid' or 'mosaic' cannot reach full marks.
ExplainAO23 marks
A plant cell and an animal cell are each placed in a solution that has a lower water potential than their cytoplasm. Explain the effect on each cell.

Mark scheme — tick each point you actually made

Examiner tip: Say which way the water moves and why, using water potential, before describing the two cells. The comparison is the mark: the wall is the only real difference between the two outcomes.
CompareAO24 marks
Compare gas exchange by pumped ventilation in a grouper with gas exchange by ram ventilation in a tuna.

Mark scheme — tick each point you actually made

Examiner tip: Compare means both similarities and differences, so the point about the shared gill structure is worth a mark. Finish with the habitat and motility link, because that is the learning outcome the question is testing.
ExplainAO25 marks
The salmon is a euryhaline osmoregulator. Explain how a salmon maintains its water balance in fresh water and in sea water.

Mark scheme — tick each point you actually made

Examiner tip: Take the two media one at a time and give the direction of water movement before the response. An answer that describes 'osmoregulation' without saying which way the water is moving and which way the fish corrects it scores very little.
DescribeAO35 marks
A student investigates the effect of surface area to volume ratio on diffusion using cubes of agar containing an indicator. Describe how the investigation would be carried out and what the results would show.

Mark scheme — tick each point you actually made

Examiner tip: Control the variables explicitly - same concentration, same volume, same temperature - and measure something quantitative. The final mark is for linking the result to the ratio, not for saying 'the small one went clear first'.

Exam technique for this topic

  • Pair every structure with its function. The learning outcome for cell structure says recognise and outline functions, so a labelled diagram with no jobs attached cannot score more than half. Learn the protein route - nucleus, ribosome, rough ER, Golgi body, vesicle, membrane - as a sequence, because it answers most organelle questions in one go.
  • Get the direction of osmosis right by thinking in negatives. Water potential is zero in pure water and negative in every solution, so water moves from the less negative side to the more negative side. Write 'from a region of higher water potential to a region of lower water potential' rather than 'from a high concentration to a low concentration', which is ambiguous when water is the substance moving.
  • In any surface area to volume question, show the calculation. Work out the surface area, work out the volume, divide, and write the ratio as something to 1. Then say what follows: the ratio falls with size, so diffusion over the body surface cannot supply the volume, so a specialised exchange surface and a transport system are needed.
  • Finish gas exchange and osmoregulation answers with the link the syllabus asks for. For gas exchange that is habitat and motility - a sessile polyp, an ambush predator that waits, a continuous cruiser. For osmoregulation it is the direction of water movement and the specific response that corrects it: drink or do not drink, large dilute urine or small concentrated urine, ions taken up or excreted across the gills.
  • Keep the four transport processes in a table in your head: diffusion (no protein, no ATP), facilitated diffusion (protein, no ATP, down the gradient), osmosis (water only, no ATP, down the water potential gradient) and active transport (protein, ATP, against the gradient). Most lost marks in this topic come from mixing up which of them uses energy and which direction each one goes.

Why students lose marks here

A student wroteA student wrote: 'Water moves by osmosis from a region of low water potential to a region of high water potential, because it moves towards the stronger solution.'
Why it loses marksThe direction is reversed. Water potential is zero in pure water and becomes more negative as solute is added, so the stronger solution has the lower water potential. Water moves towards it, which means from higher water potential to lower, not the other way round.
The answer that scoresWater potential is a measure of the number of water molecules in a solution and their freedom to move. Pure water has a water potential of zero, and adding solute lowers it, so a concentrated solution has a more negative water potential than a dilute one. Osmosis is the net movement of water from a region of higher water potential (less negative, closer to zero) to a region of lower water potential (more negative), through a partially permeable membrane. So water does move towards the more concentrated solution, but that solution is the one with the lower water potential. For example, a marine fish in sea water loses water because its body fluids are more dilute, and therefore have a higher water potential, than the sea around it.
A student wroteA student wrote: 'Facilitated diffusion uses carrier proteins and ATP to move glucose into the cell, while active transport uses channel proteins.'
Why it loses marksBoth halves are wrong. Facilitated diffusion is passive and uses no ATP, and it can use either channel or carrier proteins. Active transport is the one that uses ATP, and it always uses carrier proteins, because a channel cannot change shape to push a substance against its gradient.
The answer that scoresFacilitated diffusion is a passive process: glucose, amino acids and ions move down their concentration gradient through specific channel or carrier proteins in the membrane, and no ATP is used. It is needed because these substances are polar or charged and cannot cross the phospholipid bilayer. Active transport is different in two ways: it moves substances against their concentration gradient, and it uses ATP from respiration to do so. It works through carrier proteins, which bind the substance, use the energy from ATP to change shape, and release it on the other side of the membrane. A gill cell pumping chloride ions out into sea water, against a gradient, is active transport; glucose entering a cell down its gradient through a carrier is facilitated diffusion.
A student wroteA student wrote: 'A plant cell placed in pure water will swell up and burst, just like an animal cell, because water enters by osmosis.'
Why it loses marksThe plant cell has a cellulose cell wall outside the membrane. Water does enter and the cell does swell, but the wall is strong and pushes back, so the cell becomes turgid instead of bursting. Only an animal cell, which has no wall, will swell until the membrane fails.
The answer that scoresPure water has a water potential of zero, which is higher than the water potential inside the cell, so water enters the plant cell by osmosis and the vacuole expands. As it expands it pushes the cytoplasm and membrane outwards against the cell wall, and the wall resists, producing an opposing pressure. The cell becomes turgid and stays intact, which is what gives non-woody plant tissue and algal fronds their firmness. An animal cell has no cell wall, so when water enters it swells and eventually the surface membrane ruptures and the cell bursts. In the opposite situation, a plant cell in a solution of lower water potential loses water, the vacuole shrinks and the membrane pulls away from the wall - plasmolysis - while an animal cell simply shrinks and becomes crenated.
A student wroteA student wrote: 'A tuna is an osmoconformer because it lives in sea water, so its body fluids are the same as the sea, and this is why it does not need to drink.'
Why it loses marksLiving in sea water does not make an animal a conformer. The tuna is an osmoregulator: its body fluids are far more dilute than sea water, roughly a third of the concentration, so it is constantly losing water and must drink sea water to replace it and excrete the surplus ions actively.
The answer that scoresAn osmoconformer is an organism whose body fluid concentration follows that of the surrounding water - the marine mussel is the example, because its body fluids are isosmotic with sea water and it does not regulate them. A tuna is an osmoregulator: its body fluids are much more dilute than sea water, so its blood has a higher water potential than the sea and water is lost by osmosis across the gills. To replace it, the tuna drinks sea water and absorbs the water in its gut, and it gets rid of the salts that come in with it by actively excreting ions across its gills, while producing only a small volume of urine. Because it must hold its internal concentration at roughly a third of sea water, the tuna is also stenohaline - it tolerates only a narrow range of salinity and cannot move into estuaries.
A student wroteA student wrote: 'A large fish has a bigger surface area, so it has a larger surface area to volume ratio than a small fish, which is why it can rely on diffusion through its skin.'
Why it loses marksThe surface area is bigger, but the volume grows faster than the surface. Surface area increases with the square of length and volume with the cube, so the ratio falls as size increases. A large fish has a small surface for its volume, not a large one, which is precisely why it needs gills and a circulation.
The answer that scoresSurface area to volume ratio falls as an organism gets bigger. A cube 1 cm on a side has a surface area of 6 cm² and a volume of 1 cm³, a ratio of 6:1, but a cube 4 cm on a side has a surface area of 96 cm² and a volume of 64 cm³, a ratio of only 1.5:1. The surface is where gases are exchanged and the volume is the tissue that needs supplying, so a small organism has plenty of surface for each unit of tissue and a short diffusion distance to its centre, and simple diffusion is enough. A large fish has a small surface for a large volume and a long diffusion distance, so diffusion through the skin cannot supply its oxygen. It needs a specialised exchange surface with a large area and a thin barrier - the gills - and a transport system to carry the gases between the gills and the tissues.