AS & A Level Chemistry · Area 2 · A Level Content

Polymerisation

Condensation polymerisation joins monomers that each carry two functional groups, forming polyesters and polyamides and losing water or hydrogen chloride at every link. This topic covers how those polymers are made, how to deduce repeat units and monomers, how to predict which type of polymerisation a monomer undergoes, and why polyesters and polyamides degrade while poly(alkenes) do not.

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Syllabus coverage

  • Describe the formation of polyesters by the reaction between a diol and a dicarboxylic acid, and by the reaction between a diol and a dioyl chloride
  • Describe the formation of polyesters by the reaction of a hydroxycarboxylic acid
  • Describe the formation of polyamides by the reaction between a diamine and a dicarboxylic acid or a dioyl chloride
  • Describe the formation of polyamides by the reaction of an aminocarboxylic acid
  • Describe the formation of polyamides by the reaction between amino acids
  • Deduce the repeat unit of a condensation polymer obtained from a given monomer or pair of monomers
  • Identify the monomer or monomers present in a given section of a condensation polymer molecule
  • Predict the type of polymerisation reaction for a given monomer or pair of monomers
  • Deduce the type of polymerisation reaction which produces a given section of a polymer molecule
  • Recognise that poly(alkenes) are chemically inert and can therefore be difficult to biodegrade, that some polymers can be degraded by the action of light, and that polyesters and polyamides are biodegradable by acidic and alkaline hydrolysis

Part of the AS & A Level Chemistry syllabus 9701.

Condensation polymerisation: polyesters and polyamidesTwo different monomers, each with two reactive groups, join up with the loss of a small molecule - water. One monomer gives the esterlink -COO- and the other gives the amide link -CO-NH-, and the chain grows at both ends.A polyester: a dicarboxylic acid + a diolbenzene-1,4-dicarboxylic acid with ethane-1,2-diol gives PETHOOCCOOHbenzene-1,4-dicarboxylic acid+HOCH2CH2OHethane-1,2-diolcondensationone water molecule is lost at every link[OCOCOOCH2CH2]nthe diacid part: -C(=O)-C6H4-C(=O)-the diol part: -O-CH2-CH2-O-the ester link, -COO-The 3D structure and the forcesThe links inside a chain are covalent, butthe attractions between the chains are weak,so a polyester softens on heating and doesnot dissolve in water.The C=O groups of the ester links attractthe neighbouring chains by permanentdipole-dipole forces, so the chains packclosely and the fibre is strong.A polyamide: a dicarboxylic acid + a diaminehexane-1,6-diamine with hexanedioic acid gives nylon-6,6H2NNH2(CH2)6hexane-1,6-diamine+HOCOCOOH(CH2)4hexanedioic acidThe repeat unit of nylon-6,6[NHNHCOCO]nthe diamine part: -NH-(CH2)6-NH-the diacid part: -CO-(CH2)4-CO-the amide link, -CO-NH-Interactions between the chainsThe N-H of one chain hydrogen bonds to theC=O of the next, and hydrogen bonding isstronger than the dipole-dipole forces in apolyester, so nylon has a higher melting point.The chains are linear, so they line up andpack closely: the polymer is strong and canbe drawn into fibres.
Condensation polymerisation shown for a diol with a dicarboxylic acid and for a diamine with a dicarboxylic acid: the -OH of one monomer and the -H of the other are eliminated as a molecule of water, leaving an ester link, -COO-, in a polyester or an amide link, -CONH-, in a polyamide, and the chain can grow at both ends.

Condensation polymerisation: two functional groups and a small molecule lost

Condensation polymerisation is the joining together of many monomer molecules to form one very large molecule, with the loss of a small molecule at every link that is made. That small molecule is usually water, when a carboxylic acid reacts with an alcohol or an amine, or hydrogen chloride, when an acid chloride reacts with an alcohol or an amine. Every monomer must carry two functional groups, because the chain has to be able to grow at both ends: a molecule with only one reactive group would cap the chain and stop it dead.

The two groups react to give a linkage. An alcohol (-OH) with a carboxylic acid (-COOH) gives an ester link, -COO-, and an amine (-NH2) with a carboxylic acid (-COOH) gives an amide link, -CONH-. The chain still carries a functional group at each end after each link is made, so it can react again and the chain keeps growing. This is the opposite of addition polymerisation, where the monomers must contain a C=C double bond and nothing at all is lost, so the polymer has exactly the same empirical formula as the monomer.

Condensation polymers are named after the linkage they contain. Chains joined by ester links are polyesters; chains joined by amide links are polyamides. Both are made on a very large industrial scale, and both can be hydrolysed back into smaller molecules, which is exactly why they behave so differently from poly(alkenes) when they are thrown away.

FeatureAddition polymerisationCondensation polymerisation
What the monomer must containA C=C double bondTwo functional groups
Small molecule lostNone, so every atom of the monomer ends up in the polymerOne small molecule, usually H2O or HCl, at every link
Linkage formedNone: the C=C opens to give C-C single bondsAn ester link, -COO-, or an amide link, -CONH-
Empirical formula of the polymerThe same as the monomerDifferent from the monomers
ExamplesPoly(ethene), PVC, PTFEPET (terylene), nylon-6,6, Kevlar
A condensation monomer needs two functional groups. One group would stop the chain growing instead of extending it.

Polyesters: a diol with a dicarboxylic acid or a dioyl chloride

A polyester is made by reacting a diol with a dicarboxylic acid. The best known example is the reaction of ethane-1,2-diol, HOCH2CH2OH, with benzene-1,4-dicarboxylic acid (terephthalic acid), HOOC-C6H4-COOH. Each -OH group of the diol esterifies one -COOH group of the acid, so two ester links are formed per repeat unit and two molecules of water are lost. The product is poly(ethylene terephthalate), PET, which is also sold under the name terylene.

An acid and an alcohol reach an equilibrium and the esterification is slow on its own, so the industrial process is driven forward by removing the water as it forms. Replace the dicarboxylic acid with a dioyl chloride and the reaction changes completely: an acid chloride reacts with an alcohol rapidly at room temperature and without a catalyst, because a chloride ion is a far better leaving group than a hydroxide ion. The link formed is still an ester link, but the small molecule lost is hydrogen chloride rather than water. This is why dioyl chlorides are used when a polymer has to be made quickly and in high yield.

The mechanism is nucleophilic addition-elimination, and you can describe it in words. A lone pair on the oxygen of the alcohol attacks the delta-positive carbon of the C=O group of the acid chloride; the pi bond of the C=O breaks and its electrons move onto the oxygen, giving a tetrahedral intermediate. The chloride ion then leaves, taking the pair of electrons of the C-Cl bond with it, and the intermediate loses a proton to give the ester.

PET is a tough, strong, semi-crystalline thermoplastic whose melting point is high for its chain length, because the ester links are polar and the chains pack closely together. Its main uses are drinks bottles and polyester fibre for clothing, and because it contains ester links it can be broken back down to its monomers by hydrolysis, a route known as chemical recycling.

A dioyl chloride gives the same ester link as a dicarboxylic acid but loses HCl instead of water, and reacts much faster because chloride is the better leaving group.

Polyesters from a single monomer: the hydroxycarboxylic acids

You do not need two different monomers to make a condensation polymer. A hydroxycarboxylic acid carries both an -OH and a -COOH in the same molecule, so each molecule can react with its neighbours: the -COOH of one molecule esterifies the -OH of the next, and the chain grows at both ends. 2-hydroxypropanoic acid (lactic acid, CH3CH(OH)COOH) polymerises this way to give polylactic acid, PLA, and 2-hydroxyethanoic acid (glycolic acid) gives poly(glycolic acid), PGA.

When a single monomer condenses with itself, the repeat unit is exactly one molecule of the monomer minus one molecule of water. For PLA the repeat unit is -O-CH(CH3)-CO-, so the polymer has the empirical formula C3H4O2 while the monomer has C3H6O3. Notice that the repeat unit still contains one ester link and one free bond at each end, which is what lets the next unit join on.

PLA and PGA are both polyesters, so both are broken down by hydrolysis, and that is precisely why they are used where a plastic has to disappear. PLA goes into compostable food packaging, disposable cups and 3D printing filament; PGA and its copolymers are used for dissolvable surgical stitches and for implants that slowly break down inside the body, because the ester links are hydrolysed by water in the tissue and the harmless products are absorbed.

How fast such a polymer disappears can be designed. More ester links per unit length, or a lower degree of crystallinity, lets water reach the links more easily, so the polymer hydrolyses faster. That is a real design decision in medical materials, not a fixed property of the plastic.

A hydroxycarboxylic acid needs no partner: it condenses with itself, and its repeat unit is one monomer unit minus one molecule of water.

Polyamides: diamines, dicarboxylic acids, amino acids and proteins

A polyamide is made by reacting a diamine with a dicarboxylic acid. Hexane-1,6-diamine, H2N(CH2)6NH2, reacts with hexanedioic acid (adipic acid), HOOC(CH2)4COOH, to give nylon-6,6: each -NH2 condenses with a -COOH to form an amide link, -CONH-, and a molecule of water is lost, so two molecules of water are lost per repeat unit. The name records the carbon count of each monomer, six and six. Replace the dicarboxylic acid with hexanedioyl chloride and the reaction is fast at room temperature, losing hydrogen chloride instead of water; this is the reaction used in the nylon rope demonstration, where a solution of the diamine is poured onto a solution of the dioyl chloride and the polymer is drawn out as a continuous thread.

As with polyesters, a single monomer carrying both groups is enough. 6-aminohexanoic acid, H2N(CH2)5COOH, condenses with itself to give nylon-6, whose repeat unit is -NH-(CH2)5-CO-. That repeat unit makes the point plainly: the amide link forms between the amine end of one molecule and the acid end of the next.

Amino acids behave in exactly the same way. A 2-amino acid such as glycine, H2NCH2COOH, carries an -NH2 and a -COOH, so it condenses with another amino acid to give a peptide link, which is simply an amide link. Condensing many amino acids gives a polypeptide, and a protein is a polyamide whose repeat unit is decided by the sequence of amino acids in the chain. The chemistry of nylon and the chemistry of a protein are the same reaction.

Kevlar is a polyamide made from benzene-1,4-diamine and benzene-1,4-dicarbonyl chloride. Both monomers are rigid and flat, so the chains are straight rods rather than tangles, and the amide links of neighbouring chains hydrogen bond to each other over long distances. It is that combination of rigid chains and extensive hydrogen bonding, not any covalent cross-linking, that makes Kevlar strong enough for bullet-resistant vests and for the cords of tyres.

Nylon and proteins are made by the same reaction: an amine condenses with a carboxylic acid to give an amide link, and in a protein that link is called a peptide link.

Deducing the repeat unit, and identifying the monomers

To deduce the repeat unit from a monomer or a pair of monomers, work out which atoms are lost. The -OH of the alcohol (or the -H of the amine) and the -OH of the carboxylic acid leave together as water; the -H of the alcohol or amine and the Cl of an acid chloride leave together as hydrogen chloride. What remains is the repeat unit, and it must be drawn with a bond at each end, because that is where the next unit joins on.

To go the other way, from a section of a polymer to its monomers, find the linkage first. If the linkage is an ester, the polymer is a polyester and its monomers are an alcohol and an acid, so add the elements of water across each ester link: the -CO- side takes back an -OH to become a -COOH and the -O- side takes back an H to become an -OH. If the linkage is an amide, the polymer is a polyamide, and adding water across -CO-NH- gives a -COOH on one side and an -NH2 on the other.

How many different monomers a section contains is decided by the pattern of the linkages. If every ester link in the chain is identical and the whole chain can be built from one molecule carrying both an -OH and a -COOH, the polymer came from a single hydroxycarboxylic acid or amino acid. If the chain alternates between two different fragments, for example an aromatic ring carrying two -CO- groups alternating with a two-carbon unit carrying two -O- groups, the polymer came from a dicarboxylic acid and a diol.

Remember that a repeat unit is the smallest fragment that repeats. Copying out the whole visible section, or leaving out the two bonds that join the repeat units together, both lose the mark.

Monomer or pair of monomersLinkagePolymerRepeat unit
Ethane-1,2-diol + benzene-1,4-dicarboxylic acidEsterPET (terylene)-O-CH2CH2-O-CO-C6H4-CO-
Ethane-1,2-diol + benzene-1,4-dicarbonyl chlorideEsterPET (terylene), the same repeat unit-O-CH2CH2-O-CO-C6H4-CO-
2-hydroxypropanoic acidEsterPolylactic acid (PLA)-O-CH(CH3)-CO-
Hexane-1,6-diamine + hexanedioic acidAmideNylon-6,6-NH-(CH2)6-NH-CO-(CH2)4-CO-
6-aminohexanoic acidAmideNylon-6-NH-(CH2)5-CO-
Glycine + glycineAmide (peptide)A polypeptide-NH-CH2-CO-NH-CH2-CO-
Find the linkage, then add water back. An ester link gives an acid and an alcohol; an amide link gives an acid and an amine.

Predicting the type of polymerisation

To predict which polymerisation a monomer will undergo, look at the functional groups, not at the size of the molecule. If the only reactive feature is a C=C double bond, the monomer undergoes addition polymerisation, because the double bond opens and joins the monomers together with nothing lost. If the monomer carries two functional groups that can condense, such as an -OH with a -COOH, an -NH2 with a -COOH, or an acid chloride with an -OH or an -NH2, it undergoes condensation polymerisation.

A single monomer can undergo condensation polymerisation provided it carries both of the reacting groups in the same molecule, which is why 2-hydroxypropanoic acid and 6-aminohexanoic acid are condensation monomers rather than addition monomers. A pair of monomers undergoes condensation when between them they provide the two reacting groups, as in a diol with a dicarboxylic acid, or a diamine with a dioyl chloride.

The trap is a molecule carrying both a C=C bond and a second functional group. Propenoic acid, CH2=CHCOOH, has a double bond and a carboxylic acid group, but a single -COOH has nothing to condense with, so propenoic acid polymerises by addition through the C=C bond, leaving the -COOH groups hanging from the chain as pendants. That polymer, poly(propenoic acid), is a real material: as its sodium salt it is the superabsorbent that swells inside a disposable nappy.

To work the other way, from a section of a polymer to the type of polymerisation, look for the tell-tale groups. A backbone of carbon atoms only, with substituent groups hanging from it and no polar link inside the chain, must have come from addition polymerisation of an alkene. A chain interrupted at regular intervals by -COO- or -CONH- links, with a heteroatom and a C=O inside the backbone, must have come from condensation polymerisation.

Monomer or pair of monomersReactive featureType of polymerisation
Propene, CH2=CHCH3One C=C and no second functional groupAddition
Propenoic acid, CH2=CHCOOHA C=C; the single -COOH cannot condense with itselfAddition, through the C=C
Ethane-1,2-diol + benzene-1,4-dicarboxylic acidTwo -OH and two -COOHCondensation, giving a polyester
Hexane-1,6-diamine + hexanedioic acidTwo -NH2 and two -COOHCondensation, giving a polyamide
2-hydroxypropanoic acidOne -OH and one -COOH in the same moleculeCondensation, giving a polyester
6-aminohexanoic acidOne -NH2 and one -COOH in the same moleculeCondensation, giving a polyamide
Benzene-1,4-diamine + benzene-1,4-dicarbonyl chlorideTwo -NH2 and two acid chloride groupsCondensation, giving the polyamide Kevlar
A C=C means addition; two condensing groups mean condensation. A monomer with both a C=C and a single -COOH still polymerises by addition.

Degradable polymers: why poly(alkenes) persist and polyesters do not

A polymer is biodegradable if microorganisms, or the water, acids and alkalis in the environment, can break its chains down into small molecules that living things can use. Poly(alkenes) such as poly(ethene), poly(propene) and PVC are built on a backbone of C-C and C-H single bonds, which are strong, non-polar and chemically unreactive. There is no polar group for water to attack and no link that an enzyme can hydrolyse, and the long, tangled, hydrophobic chains offer a microorganism nothing to work on. A poly(alkene) can therefore sit in landfill or in the sea for decades, which is the whole reason for the recycling and waste-reduction effort.

Polyesters and polyamides are different. Both contain a polar carbonyl group in the backbone, and both the ester link and the amide link can be attacked by water. Acid hydrolysis is catalysed by H+ ions and alkaline hydrolysis by OH- ions, and the alkaline reaction is faster because the hydroxide ion is a much better nucleophile than a water molecule. Microorganisms supply the same chemistry with enzymes: esterases attack polyester links and proteases attack polyamide links, which is why a polyester or a polyamide buried in soil or in compost will break down while a poly(alkene) will not.

The hydrolysis cuts the chain into shorter and shorter fragments until the products are the original monomers or their ions. From a polyester you get the diol and the dicarboxylic acid, or the salt of the acid in alkali. From a polyamide you get the diamine and the dicarboxylic acid, or their salts in alkali. Those small, water-soluble molecules can then be metabolised, which is what makes the polymer genuinely biodegradable rather than merely brittle.

Some polymers are designed to be broken down by light. If ethene is copolymerised with a small amount of carbon monoxide, ketone carbonyl groups are built into the chain at intervals. A C=O group absorbs ultraviolet light, and the energy it absorbs breaks the chain at that point. Sunlight therefore chops the chain into short fragments, the plastic becomes brittle and falls apart, and those fragments are then small enough for microorganisms to finish off. This is how photodegradable mulch film and photodegradable carrier bags work, and the limitation is worth remembering: light alone only fragments the plastic, so unless the fragments are themselves biodegradable the plastic has been broken up rather than removed.

No polar link, no breakdown. Poly(alkenes) have nothing for water or an enzyme to attack; polyesters and polyamides have a C=O link that hydrolysis can open.
A collection of manufactured plastic items of the kind that end up as mixed plastic waste: poly(alkenes) such as poly(ethene) and poly(propene) contain no polar link that water or an enzyme can attack, so they resist biodegradation and persist, whereas polyesters and polyamides are broken down by acidic and alkaline hydrolysis.

Key terms you must be able to define

Condensation polymerisation
The joining together of many monomer molecules, each carrying two functional groups, into one large molecule with the loss of a small molecule such as water or hydrogen chloride at every link formed.
Polyester
A condensation polymer whose chains are joined by ester links, -COO-, made either from a diol with a dicarboxylic acid or dioyl chloride, or from a hydroxycarboxylic acid; examples are PET (terylene) and polylactic acid.
Polyamide
A condensation polymer whose chains are joined by amide links, -CONH-, made from a diamine with a dicarboxylic acid or dioyl chloride, or from an aminocarboxylic acid or an amino acid; examples are nylon-6,6, nylon-6, Kevlar and every protein.
Ester link
The -COO- group formed when a carboxylic acid (or an acid chloride) condenses with an alcohol, eliminating water (or hydrogen chloride); it holds a polyester together and it is the link that acid and alkaline hydrolysis open.
Amide link
The -CONH- group formed when a carboxylic acid (or an acid chloride) condenses with an amine, eliminating water (or hydrogen chloride); the same link in a protein is called a peptide link.
Dioyl chloride
A molecule carrying two -COCl groups, for example benzene-1,4-dicarbonyl chloride; it reacts with a diol or a diamine rapidly and without a catalyst, forming the same ester or amide links as the dicarboxylic acid but eliminating hydrogen chloride instead of water.
Repeat unit
The smallest fragment of a polymer chain that repeats along it; it is drawn with one free bond at each end, and for a condensation polymer it is one unit of each monomer minus the small molecules that were lost.
Hydroxycarboxylic acid
A molecule carrying both an -OH group and a -COOH group, for example 2-hydroxypropanoic acid (lactic acid); because it has both reacting groups it condenses with itself to give a polyester.
Biodegradable polymer
A polymer whose chains can be broken down by microorganisms or by hydrolysis in the environment, giving small water-soluble products that can be metabolised; polyesters and polyamides are biodegradable by acidic and alkaline hydrolysis, whereas poly(alkenes) are not.

Applied to the real world

Cambridge sets 9701 in named contexts - an industrial plant, a laboratory, a hospital, a car battery, a water treatment works. Use these as models for how to apply the chemistry, then write your own.

In an industrial plant

Poly(ethylene terephthalate), PET, is made on a huge scale by heating ethane-1,2-diol with benzene-1,4-dicarboxylic acid and removing the water as it forms, which drives the equilibrium towards the polymer. The same repeat unit is obtained far more quickly if benzene-1,4-dicarbonyl chloride is used instead, because then hydrogen chloride is lost and no catalyst is needed. Much of the PET becomes drinks bottles and polyester fibre, and because the chains contain ester links the polymer can be hydrolysed back to its monomers, which is why PET is one of the most successfully recycled plastics.

In a laboratory

Nylon-6,6 is made in a demonstration by pouring a solution of hexane-1,6-diamine onto a solution of hexanedioyl chloride. The two liquids meet at the interface, amide links form immediately and hydrogen chloride is lost, and the polymer can be drawn out as a continuous thread while it is still being made. If the hydrolysable links are then boiled with aqueous sodium hydroxide, the polymer falls apart and the products are hexane-1,6-diamine and the sodium salt of hexanedioic acid.

In a hospital

Polylactic acid and poly(glycolic acid) are polyesters used for dissolvable surgical stitches and for implants that disappear once the tissue has healed. Water in the tissue hydrolyses the ester links, so the chain is cut into lactic acid and glycolic acid units that the body handles in the normal way, and the patient does not need a second operation to have the stitches removed. The same ester chemistry that makes a PET bottle hydrolysable is what makes these materials disappear on a controlled timescale.

In the environment

A poly(ethene) carrier bag has a backbone of C-C and C-H single bonds and no polar link at all, so it is chemically inert and can survive in landfill for decades. A bag made from ethene copolymerised with a small amount of carbon monoxide behaves differently: the ketone carbonyl groups built into the chain absorb ultraviolet light in sunlight, the chains are cut and the bag becomes brittle and fragments, and the fragments can then be broken down further by microorganisms, provided they are themselves biodegradable.

Flashcards

Click a card to flip it. Mark honestly — the tracker uses this.

Q1What is condensation polymerisation?
The joining together of many monomer molecules, each carrying two functional groups, into one large molecule, with the loss of a small molecule such as water or hydrogen chloride at every link formed.
Q2What must every monomer in a condensation polymerisation contain, and why?
Two functional groups, because the chain has to be able to grow at both ends. A monomer with only one functional group would stop the chain instead of extending it.
Q3Which small molecule is lost when a diol reacts with a dicarboxylic acid, and which is lost when it reacts with a dioyl chloride?
Water is lost with the dicarboxylic acid, and hydrogen chloride is lost with the dioyl chloride. The link formed is the same ester link in both cases.
Q4Name the polymer formed from ethane-1,2-diol and benzene-1,4-dicarboxylic acid, and the link it contains.
Poly(ethylene terephthalate), PET, also called terylene. It is a polyester, so its chains are joined by ester links, -COO-, and two molecules of water are lost per repeat unit.
Q5Write the repeat unit of polylactic acid.
-O-CH(CH3)-CO-. It is one molecule of 2-hydroxypropanoic acid minus one molecule of water, because that monomer carries both an -OH and a -COOH and so condenses with itself.
Q6Name the two monomers of nylon-6,6 and the link that is formed between them.
Hexane-1,6-diamine and hexanedioic acid. Each -NH2 condenses with a -COOH to give an amide link, -CONH-, with the loss of one molecule of water for each link, so two are lost per repeat unit.
Q7Which single monomer gives nylon-6?
6-aminohexanoic acid, H2N(CH2)5COOH. It carries both an amine and a carboxylic acid group and condenses with itself, and its repeat unit is -NH-(CH2)5-CO-.
Q8Why can an amino acid polymerise by condensation on its own?
Because it carries both an -NH2 group and a -COOH group, so the amine end of one molecule condenses with the acid end of the next, forming a peptide link, which is an amide link.
Q9What are the monomers of Kevlar, and why is the fibre so strong?
Benzene-1,4-diamine and benzene-1,4-dicarbonyl chloride. Both are rigid, straight molecules, so the polyamide chains are rod-like and hydrogen bond to each other over long distances, which makes the fibre exceptionally strong.
Q10How do you decide whether a monomer will undergo addition or condensation polymerisation?
From the functional groups. A C=C double bond with no second condensing group means addition; two functional groups that can condense, such as an -OH with a -COOH or an -NH2 with a -COOH, mean condensation.
Q11Why is propenoic acid, CH2=CHCOOH, polymerised by addition rather than by condensation?
A single -COOH group has nothing to condense with and there is no second functional group, so the C=C double bond is the only route open to it, and it opens to join the monomers together with the -COOH groups left as pendants.
Q12Why are poly(alkenes) so difficult to biodegrade?
Their backbones are made of strong, non-polar C-C and C-H single bonds, with no polar link for water to hydrolyse and no group that an enzyme can attack, so microorganisms cannot break the chains and the polymer persists.
Q13How can a polymer be degraded by the action of light?
Carbonyl ketone groups built into the chain, for example by copolymerising ethene with a small amount of carbon monoxide, absorb ultraviolet light, and the absorbed energy breaks the chain at that point. The plastic becomes brittle and fragments, but the fragments must still be biodegradable for the material to be removed.
Q14Which polymers are biodegradable by acidic and alkaline hydrolysis, and what are the products?
Polyesters and polyamides. Hydrolysis opens the ester link, -COO-, or the amide link, -CONH-, giving back the diol or the diamine together with the dicarboxylic acid; in alkali the acid is obtained as its salt.
0 of 14 marked as known

Exam-style questions

9 questions, 30 marks. Write your answer, then reveal the mark scheme and tick each point you actually made. Answering honestly here is what makes the rest of the site useful.

DefineAO12 marks
Define the term condensation polymerisation, and state the small molecule that is eliminated when a diol reacts with a dicarboxylic acid to form a polyester.

Mark scheme — tick each point you actually made

Examiner tip: Two marks, two ideas: the loss of a small molecule and the two functional groups on each monomer. Simply saying that the monomers join together is true of addition polymerisation as well and will not score.
DescribeAO13 marks
Describe the formation of a polyester from ethane-1,2-diol and benzene-1,4-dicarbonyl chloride. Your answer should name the linkage formed and the small molecule eliminated.

Mark scheme — tick each point you actually made

Examiner tip: The linkage is the same whether you start from the dicarboxylic acid or from the dioyl chloride; only the small molecule changes. Saying that water is lost here loses the third mark.
IdentifyAO22 marks
A section of a polymer molecule is -NH-(CH2)6-NH-CO-(CH2)4-CO-NH-(CH2)6-NH-CO-(CH2)4-CO-. Identify the two monomers from which it was formed and name the type of linkage present.

Mark scheme — tick each point you actually made

Examiner tip: Add the elements of water back across one amide link: the -CO- side becomes -COOH and the -NH- side becomes -NH2. That gives the two monomers straight away.
CalculateAO24 marks
Nylon-6,6 is made by the condensation polymerisation of hexane-1,6-diamine (Mr = 116.0) with hexanedioic acid (Mr = 146.0), and its repeat unit has Mr = 226.0. A sample of 1.16 g of hexane-1,6-diamine is reacted with an excess of hexanedioic acid. Calculate the amount, in mol, of hexane-1,6-diamine used, the mass of water eliminated, and the maximum mass of nylon-6,6 that could be formed.

Mark scheme — tick each point you actually made

Examiner tip: Every repeat unit takes one molecule of each monomer, so the amount of repeat units equals the amount of the limiting monomer. Two molecules of water are lost per repeat unit, not one, because each monomer is difunctional.
ExplainAO24 marks
For each of the following, predict whether the polymerisation is addition or condensation and explain your answer: (a) propene, CH2=CHCH3; (b) a mixture of ethane-1,2-diol and benzene-1,4-dicarboxylic acid; (c) propenoic acid, CH2=CHCOOH; (d) 6-aminohexanoic acid, H2N(CH2)5COOH.

Mark scheme — tick each point you actually made

Examiner tip: Part (c) is the trap. A molecule can contain a C=C and still not be a condensation monomer, because a single acid group has nothing to condense with.
ExplainAO24 marks
Poly(ethene) is chemically inert and persists in the environment for many years, whereas a polyester such as PET is biodegradable. Explain this difference with reference to the bonds and the functional groups in the two polymers.

Mark scheme — tick each point you actually made

Examiner tip: Name the link that is attacked. Writing that poly(ethene) is unreactive 'because it is a plastic' scores nothing; the marks are for the non-polar C-C backbone of the poly(alkene) and the polar ester link of the polyester.
DeduceAO25 marks
A polyester is made from ethane-1,2-diol and benzene-1,4-dicarboxylic acid. Deduce the products formed when a sample of this polyester is heated with (a) dilute aqueous hydrochloric acid and (b) aqueous sodium hydroxide, and explain why the polymer breaks down in each case.

Mark scheme — tick each point you actually made

Examiner tip: Say what is different about the two sets of conditions. The ester link is broken in both, but in alkali the carboxylic acid produced is neutralised straight away, so the product is its salt rather than the free acid.
OutlineAO33 marks
A student is given a white polymer of unknown type and is told that it is either a poly(alkene) or a polyester. Outline an experimental method that would show which of the two it is, and state the result you would expect in each case.

Mark scheme — tick each point you actually made

Examiner tip: For a method mark, name the reagent and the conditions: aqueous sodium hydroxide, heated under reflux. Testing solubility in cold water proves nothing, because neither polymer dissolves in cold water.
DeduceAO23 marks
Ethane-1,2-diol reacts with hexanedioic acid to give a polyester, and 2-hydroxypropanoic acid reacts with itself to give a polyester. Deduce the repeat unit of each polymer and show how each repeat unit is related to the monomer or monomers used.

Mark scheme — tick each point you actually made

Examiner tip: Count the water molecules lost against the number of links formed: one per ester link. Two difunctional monomers give two links and lose two molecules of water, whereas a single hydroxycarboxylic acid gives one link and loses one.

Exam technique for this topic

  • Read the monomer before you write anything: a C=C means addition polymerisation, and two condensing functional groups mean condensation polymerisation. Decide from the functional groups, never from the name of the polymer.
  • A condensation monomer must have two functional groups. If you build a polyamide from a molecule with a single -NH2 you have drawn a chain that cannot grow, and you lose the mark for the linkage.
  • Show every repeat unit with a bond at each end through which it joins the next unit. A fragment drawn with an -H at one end and an -OH at the other is the monomer, not the repeat unit that the monomer forms.
  • When you deduce the monomers from a section of a polymer, add the elements of water across every ester or amide link in the section, and say what each side becomes: a -COOH for the acid, an -OH for the alcohol and an -NH2 for the amine.
  • In a hydrolysis question, give the conditions and the products separately for acid and for alkali: acid hydrolysis gives the diol or diamine together with the dicarboxylic acid, whereas alkaline hydrolysis gives the diol or diamine together with the salt of the dicarboxylic acid.
  • For a question about degradability, name the link that is attacked and the species that attacks it. 'It is biodegradable' scores nothing on its own; 'the ester link is polar and is hydrolysed by OH- ions, so the chain is cut into small water-soluble fragments' scores.

Why students lose marks here

A student wroteA student wrote: 'Poly(ethene) and nylon-6,6 are made by the same type of polymerisation, because in both cases the monomers join together into a long chain.'
Why it loses marksJoining up into a long chain is common to both types of polymerisation and tells you nothing. The test is what the monomers contain and whether a small molecule is lost: addition polymerisation needs a C=C double bond and loses nothing at all, while condensation polymerisation needs two functional groups on each monomer and loses a small molecule such as water or hydrogen chloride at every link.
The answer that scoresEthene has a C=C double bond and no second functional group, so poly(ethene) is made by addition polymerisation and every atom of the monomer ends up in the polymer. Hexane-1,6-diamine and hexanedioic acid each carry two functional groups, an amine and a carboxylic acid, so nylon-6,6 is made by condensation polymerisation, and one molecule of water is lost at each of the two links formed per repeat unit.
Addition and condensation polymerisation comparedIn addition polymerisation the monomers join without losing anything; in condensation polymerisation two different monomers join and lose asmall molecule.Addition polymerisationOne monomer type, containing a C=C double bond.HHHHCCthe monomer: ethene, CH2=CH2high pressure (about 200 atm)with a catalyst, and no other productthe repeat unit:nCCHHHHthe brackets show that theunit repeats n timesThe linkage formed: a C-C single bond (drawn in teal).No atoms are lost: n molecules of ethene give one molecule ofpoly(ethene), so the monomer and the repeat unit have the sameempirical formula, C2H4.The same happens with chloroethene (PVC), propene(poly(propene)) and tetrafluoroethene (PTFE).Condensation polymerisationTwo different monomers, each with two functional groups.hexane-1,6-diamine, H2N-(CH2)6-NH2hexanedioic acid, HOOC-(CH2)4-COOHeach monomer has two reactive ends, so the chain grows both waysheatH2Oa molecule of water is losteach time two monomers jointhe repeat unit (drawn in condensed form):n-NH-(CH2)6-NH-CO-(CH2)4-CO-CH2CONCH2HThe linkage formed: the amide linkage, -CO-NH-.COOCH2the ester linkage, -CO-O-A polyester is made the same way from a diol and a dicarboxylicacid: the linkage is an ester linkage, as in Terylene (PET) fromethane-1,2-diol and benzene-1,4-dicarboxylic acid.Water is lost every time two monomers join, so the monomer andthe repeat unit do not have the same formula.
The two routes compared: on the left an alkene monomer with a C=C double bond opens and adds to its neighbours by addition polymerisation with nothing lost, and on the right a diol and a dicarboxylic acid (or a diamine and a dicarboxylic acid) condense to give ester or amide links with the loss of a small molecule at every link.
A student wroteA student wrote: 'The repeat unit of nylon-6,6 is -H2N-(CH2)6-NH2-HOOC-(CH2)4-COOH-, because those are the monomers that were used.'
Why it loses marksThat is the two monomers written out one after the other, not the repeat unit. A repeat unit is the fragment that is actually left after the small molecules have been eliminated, and it must be drawn with one free bond at each end so that the next unit can join on to it.
The answer that scoresHexane-1,6-diamine and hexanedioic acid condense with the loss of two molecules of water per repeat unit, so the repeat unit is -NH-(CH2)6-NH-CO-(CH2)4-CO-. Each -NH2 group has become an -NH- in an amide link and each -COOH group has become a -CO- in an amide link, and the two free bonds at the ends are where the neighbouring repeat units are joined.
A student wroteA student wrote: 'Poly(ethene) is biodegradable because it is made from ethene, which comes from a natural source, and all polymers can be broken down by bacteria.'
Why it loses marksPoly(ethene) is made from ethene obtained by cracking crude oil, and coming from a natural feedstock says nothing about whether a polymer can be attacked chemically. A poly(alkene) has a backbone of strong, non-polar C-C and C-H single bonds, with no polar link for water to hydrolyse and no group that an enzyme can attack, so it is chemically inert and persists for decades in the environment.
The answer that scoresPoly(ethene) is not biodegradable: its backbone has no polar link that hydrolysis can open and no group that an esterase or a protease can attack, so microorganisms cannot break the chains. A polyester such as PET is biodegradable because it contains ester links, which are hydrolysed by acid, by alkali and by esterase enzymes, and a polyamide such as nylon-6,6 is biodegradable because its amide links are hydrolysed in the same way.
A student wroteA student wrote: 'A photodegradable carrier bag disappears completely in sunlight, so it solves the problem of plastic waste.'
Why it loses marksLight breaks the polymer chains into shorter fragments, but it does not remove the material. Unless the fragments are themselves biodegradable, the plastic has simply been turned into small pieces, which are harder to collect and are easily eaten by animals.
The answer that scoresUltraviolet light is absorbed by the carbonyl groups built into the chain and the chain is broken at that point, so the plastic becomes brittle and fragments. That is only the first step: the fragments must then be hydrolysed and metabolised by microorganisms before the material is actually removed. A polymer is only fully degradable if the bonds in it can also be attacked by water or by enzymes.

Where this fits in AS & A Level Chemistry

This page is one topic of Cambridge AS & A Level Chemistry 9701. AS & A Level Chemistry is the course home: every area and every topic in Cambridge's own order, the papers you sit and what each one tests, and the exam-practice tools. The full topic list, with each topic linked to its revision page, is on the AS & A Level Chemistry syllabus page.