IGCSE Physics · Area 3 · Waves

Light

Light is reflected, refracted, focused and dispersed as it travels through different materials. This topic covers the law of reflection and the image formed by a plane mirror, refraction and refractive index, critical angle and total internal reflection including optical fibres, thin converging and diverging lenses with ray diagrams, and the dispersion of white light by a prism.

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Syllabus coverage

  • Define and use the terms normal, angle of incidence and angle of reflection; state that for reflection the angle of incidence is equal to the angle of reflection, and recall and use this relationship
  • Describe the formation of an optical image by a plane mirror and give its characteristics, that is the same size, the same distance from the mirror and virtual; use simple constructions, measurements and calculations for reflection by plane mirrors
  • Define and use the terms normal, angle of incidence and angle of refraction, and describe an experiment to show refraction of light by transparent blocks of different shapes
  • Describe the passage of light through a transparent material, limited to the boundaries between two mediums only; state the meaning of critical angle, and describe internal reflection and total internal reflection using both experimental and everyday examples
  • Define refractive index, n, as the ratio of the speeds of a wave in two different regions, and recall and use the equations n = sin i / sin r and n = 1 / sin c
  • Describe the use of optical fibres, particularly in telecommunications
  • Describe the action of thin converging and thin diverging lenses on a parallel beam of light; define and use the terms focal length, principal axis and principal focus (focal point); draw and use ray diagrams for the formation of a real image and a virtual image by a converging lens; describe the characteristics of an image using the terms enlarged/same size/diminished, upright/inverted and real/virtual; know that a virtual image is formed when diverging rays are extrapolated backwards and does not form a visible projection on a screen
  • Describe the use of a single lens as a magnifying glass, and the use of converging and diverging lenses to correct long-sightedness and short-sightedness
  • Describe the dispersion of light as illustrated by the refraction of white light by a glass prism; know the traditional seven colours of the visible spectrum in order of frequency and in order of wavelength; recall that visible light of a single frequency is described as monochromatic

Part of the IGCSE Physics syllabus 0625.

Dispersion of white light by a prismEach colour is refracted by a different amount because each colour has a different wavelength. Violet has the shortestwavelength and is deviated most.white surfaceglass prismwhite lightredorangeyellowgreenblueindigovioletThe prism refracts each colourby a different amount.Red bends least,violet bends most.White light is a mixture of all the colours. The prism separates them because each colour travels at a slightlydifferent speed in glass.Red light slows down least and is deviated least; violet light slows down most and is deviated most.
A narrow beam of white light entering a triangular glass prism: it is refracted at both surfaces and spread out into a spectrum, with red refracted least and violet refracted most.

Reflection and the law of reflection

When light hits a surface, some of it bounces back. This is reflection. To describe reflection properly you always measure angles from the normal, which is the line drawn perpendicular to the surface at the point where the ray hits it. The angle of incidence, i, is the angle between the incident ray and the normal, and the angle of reflection, r, is the angle between the reflected ray and the normal.

The law of reflection states that the angle of incidence is equal to the angle of reflection: i = r. The incident ray, the reflected ray and the normal all lie in the same plane. A smooth surface such as a mirror gives regular reflection, so a clear image is seen, while a rough surface scatters the light in all directions, which is why you cannot see your face in a painted wall.

You can show the law with a ray box and a plane mirror. A narrow ray is aimed at the mirror and the two angles are measured from the normal with a protractor. Move the ray to a new angle of incidence and the angle of reflection changes by exactly the same amount, so the two angles are always equal.

There is one useful calculation. If the mirror is turned through an angle, the reflected ray turns through twice that angle, because the normal turns with the mirror. Rotating a mirror by 10 degrees therefore swings the reflected ray by 20 degrees.

  • Angle of incidence = angle of reflection (i = r).
  • Angles are always measured from the normal, not from the surface.
  • The incident ray, reflected ray and normal all lie in the same plane.
  • Turning the mirror through an angle turns the reflected ray through twice that angle.
Every angle in optics is measured from the normal, never from the surface itself.
Reflection and the image in a plane mirrorThe law of reflection: angle of incidence = angle of reflection, both measured from the normal at the point ofincidence.The law of reflectionplane mirrornormalincident rayreflected rayirThe image in a plane mirrormirrorobjectimageddvirtualuprightsame sizelaterally invertedas far behind the mirroras the object is in frontThe law of reflection: the angle of incidence equals the angle of reflection.The image is virtual: the rays do not really meet there, they only appear to come from behind the mirror.
A ray of light striking a plane mirror: the normal is drawn perpendicular to the surface, the angle of incidence is marked between the incident ray and the normal, and the angle of reflection is marked between the normal and the reflected ray, with the two angles equal.

Images formed by a plane mirror

A plane mirror forms an image with four characteristics you should be able to state: the image is the same size as the object, it is as far behind the mirror as the object is in front, it is upright, and it is virtual. It is also laterally inverted, which is why the word AMBULANCE is written back to front on the front of the vehicle.

The image is virtual because the reflected rays diverge. They only appear to come from a point behind the mirror, and no light actually passes through that point, so a screen placed behind the mirror shows nothing at all. This is the opposite of a real image, where the rays really do meet and the image can be projected onto a screen.

You can construct the image by drawing two rays from a point on the object. Reflect each ray at the mirror using i = r, then extend the reflected rays backwards until they cross. That crossing point is the position of the image of that point. Repeating this for the top and the bottom of the object gives the whole image, and it always comes out the same size and the same distance behind the mirror as the object is in front.

Because the image is as far behind the mirror as the object is in front, you can calculate distances directly. If you stand 1.5 m from a plane mirror, your image is 1.5 m behind it, so the distance between you and your image is 3.0 m. If you walk towards the mirror at 0.5 m/s, your image also moves towards you at 0.5 m/s, so the gap between you closes at 1.0 m/s.

Plane mirror image: same size, same distance behind, upright, virtual and laterally inverted.

Refraction at a boundary

Refraction is the change in direction of light when it crosses the boundary between two transparent materials. It happens because the speed of light is different in different materials: light travels fastest in a vacuum and in air, and more slowly in water and glass. When light enters a denser medium, one in which it travels more slowly, it slows down and bends towards the normal. When it leaves the denser medium it speeds up again and bends away from the normal.

The angle of refraction, r, is the angle between the refracted ray and the normal. If light enters along the normal the angle of incidence is zero, and although the light slows down it does not change direction, so the angle of refraction is also zero.

You can show refraction with a ray box and a glass block. A ray is directed at the block at a known angle of incidence, and as it enters the glass it bends towards the normal. As it leaves the far side it bends away from the normal, so the emergent ray is parallel to the incident ray but displaced sideways. Repeat the experiment with blocks of different shapes, such as a rectangular block, a semicircular block and a triangular prism, and the same rules hold at every boundary.

Light passing through a prism is refracted twice, once at each surface, and this time the two refractions do not cancel because the faces of a prism are not parallel. The ray is turned through an angle, and this is the basis of the dispersion effect in the last block.

Into a denser medium: slow down, bend towards the normal. Out of it: speed up, bend away from the normal.
Refraction through a rectangular glass blockEntering a denser medium the ray bends towards the normal; leaving it the ray bends away from the normal. Theemergent ray is parallel to the incident ray, but displaced sideways.glass blockdenser medium than airnormalnormalincident rayemergent rayirSnell's lawn = sin i / sin ri in air, r in glassn is about 1.5 for glassThe ray bends towards the normal on entering the glass, because glass is optically denser than air and lighttravels more slowly in it.Inside the block the ray travels in a straight line. On leaving, it speeds up again and bends away from thenormal.The emergent ray is parallel to the incident ray but displaced sideways. The greater the angle of incidence, thegreater the displacement.
A ray of light entering a rectangular glass block: it bends towards the normal as it enters the glass, travels straight through, bends away from the normal as it leaves, and emerges parallel to the incident ray but displaced sideways.

Refractive index, critical angle and total internal reflection

The refractive index, n, of a material compares the speed of light in a vacuum with its speed in the material: n = speed of light in a vacuum / speed of light in the material. Because it is a ratio of two speeds, n has no unit. Air has a refractive index of about 1.00, water 1.33 and glass about 1.50.

Refractive index can also be found from the angles. For light going from air into a material, n = sin i / sin r, where i is the angle of incidence in air and r is the angle of refraction in the material. The larger the refractive index, the more strongly the light is bent.

Here is the equation working on real numbers. Light passes from air into water at an angle of incidence of 50 degrees, and the refractive index of water is 1.33. Rearranging n = sin i / sin r gives sin r = sin 50 / 1.33 = 0.766 / 1.33 = 0.576, so r = 35 degrees. The ray has bent towards the normal, exactly as expected when it enters a denser medium.

When light tries to leave a denser medium such as glass, it bends away from the normal. As the angle of incidence is increased, the angle of refraction reaches 90 degrees and the refracted ray runs along the surface. The angle of incidence at which this first happens is the critical angle, c. For any angle of incidence greater than c the light cannot escape at all, and it is all reflected back inside the material. This is total internal reflection.

The critical angle and the refractive index are linked by n = 1 / sin c, or sin c = 1 / n. For glass of refractive index 1.50, sin c = 1 / 1.50 = 0.667, so c = 41.8 degrees. For water, sin c = 1 / 1.33 = 0.752, so c = 48.8 degrees. A larger refractive index always gives a smaller critical angle.

Total internal reflection has two conditions that must both be true: the light must be travelling from a denser to a less dense medium, and the angle of incidence must be greater than the critical angle. Everyday examples include the sparkle of a cut diamond, the reflection seen at the surface of a glass of water viewed from the side, and optical fibres.

An optical fibre is a thin strand of glass with a core of higher refractive index surrounded by cladding of lower refractive index. Light entering the core at a shallow angle strikes the core-cladding boundary at an angle greater than the critical angle, so it is totally internally reflected and stays inside the core. This happens many thousands of times along the fibre, so light can carry a signal for many kilometres with very little loss. Optical fibres are used in telecommunications because they carry far more information than copper cables and are not affected by electrical interference.

MaterialRefractive indexCritical angle in degrees
Air1.00No total internal reflection, because air is the less dense medium
Water1.3348.8
Glass1.5041.8
Diamond2.4224.4
Total internal reflection needs both conditions: denser to less dense, and angle of incidence greater than the critical angle.

Thin lenses: converging and diverging

A lens is a piece of transparent material shaped so that it refracts light. A converging (convex) lens is thicker in the middle. It takes a beam of light parallel to the principal axis and brings it together at a single point called the principal focus, or focal point. The principal axis is the line passing through the centre of the lens at right angles to it, and the focal length, f, is the distance from the centre of the lens to the principal focus.

A diverging (concave) lens is thinner in the middle. It spreads a parallel beam out, so the rays appear to come from a point on the principal axis behind the lens. That point is its principal focus, and the distance to it is again the focal length. A shorter focal length means a more strongly curved lens that bends the light more, and so a more powerful lens.

You can find the focal length of a converging lens by focusing the image of a distant object, such as a window or a tree, onto a screen. When the image is sharpest, the distance from the lens to the screen is the focal length, because light from a very distant object arrives almost parallel and is brought to a focus at the principal focus.

LensShapeAction on a parallel beamPrincipal focus
Converging (convex)Thicker in the middleBrings the rays togetherA real focus, in front of the lens, where the rays actually meet
Diverging (concave)Thinner in the middleSpreads the rays apartA virtual focus, behind the lens, from which the rays only appear to come
Converging lens: parallel rays meet at a real principal focus. Diverging lens: parallel rays appear to come from a virtual principal focus.
Ray diagrams for a convex and a concave lensF is the principal focus and the focal length f is the distance from the lens to F. The lens is thin, so all raysare taken to bend at the centre line of the lens.Convex (converging) lensFF2Fconvex lensobjectbeyond 2FimageReal, inverted, diminished, between F and 2FConcave (diverging) lensFFconcave lensobjectimagevirtualVirtual, upright, diminishedConvex lens: rays parallel to the axis converge at F. An object beyond 2F gives a real, inverted, diminishedimage between F and 2F.Concave lens: rays parallel to the axis diverge as if from F on the same side, so the image is always virtual,upright and diminished.
Two lenses compared: a converging lens brings a parallel beam to a real principal focus on the far side, while a diverging lens spreads the beam so that it appears to come from a virtual principal focus on the near side. The principal axis and the focal length are marked in each case.

Ray diagrams: real and virtual images

To draw a ray diagram for a converging lens, use two or three rays from the top of the object. The three standard rays are: a ray parallel to the principal axis, which passes through the principal focus after the lens; a ray through the centre of the lens, which carries straight on without bending; and a ray through the principal focus, which emerges parallel to the principal axis. Where two of these rays cross after the lens is where the image of the top of the object is formed.

If the object is further from the lens than the focal length, the rays really do cross after the lens and a real image is formed. A real image is inverted and it can be projected onto a screen. Its size depends on the object distance: an object beyond twice the focal length gives a diminished image, as in a camera, while an object between one and two focal lengths from the lens gives an enlarged image, as in a projector.

If the object is closer to the lens than the focal length, the rays diverge after passing through the lens. They never actually meet, but when they are extended backwards they appear to come from a point on the same side of the lens as the object. This is a virtual image. It is upright and enlarged, and it cannot be projected onto a screen because no light actually passes through it. This is exactly how a magnifying glass works.

Lenses are also used to correct vision. In short-sightedness the eye focuses the light in front of the retina, so a diverging lens is used to spread the rays slightly before they enter the eye. In long-sightedness the eye cannot focus the light enough and the image would form behind the retina, so a converging lens is used to bring the rays together sooner.

FeatureReal imageVirtual image
How it is formedRays of light actually meet after passing through the lensThe rays only appear to come from a point, because diverging rays are extrapolated backwards
Projection onto a screenYes, the image can be projected onto a screenNo, a screen shows nothing
OrientationInvertedUpright
Example with a converging lensA camera, with the object beyond the focal lengthA magnifying glass, with the object nearer than the focal length
A real image can be projected onto a screen; a virtual image cannot, because the rays only appear to come from it.

Dispersion: splitting white light into a spectrum

White light is a mixture of all the colours of the visible spectrum. When a narrow beam of white light passes through a triangular glass prism, it is refracted at both surfaces and spread out into a band of colours called a spectrum. This spreading is called dispersion.

The reason is that the refractive index of glass is slightly different for each colour. Violet light has the highest frequency and is slowed down the most by the glass, so it has the largest refractive index and is refracted through the largest angle. Red light has the lowest frequency, is slowed down the least, and is refracted the least. The colours therefore leave the prism at slightly different angles and separate out.

The traditional seven colours, in order of decreasing frequency and therefore of increasing wavelength, are red, orange, yellow, green, blue, indigo, violet. Red has the longest wavelength and the lowest frequency, and violet has the shortest wavelength and the highest frequency. The order is remembered by the mnemonic Richard Of York Gave Battle In Vain.

Light of a single frequency is described as monochromatic. A monochromatic beam is not split by a prism, it is only refracted. A rainbow is a natural spectrum, produced when sunlight is refracted and reflected inside millions of raindrops.

ColourApproximate wavelength in nmFrequency compared with the others
Red700Lowest frequency, refracted least
Orange620Higher than red
Yellow580Higher than orange
Green530About the middle of the spectrum
Blue470Higher than green
Indigo445Higher than blue
Violet400Highest frequency, refracted most
Violet is refracted the most because it has the highest frequency and the highest refractive index in glass; red is refracted the least.

Key terms you must be able to define

Normal
The line drawn perpendicular to a surface at the point where a ray of light meets it. All angles of incidence, reflection and refraction are measured from the normal.
Refractive index, n
The ratio of the speed of light in a vacuum to the speed of light in the material, n = speed in a vacuum / speed in the material. It has no unit. It can also be found from n = sin i / sin r.
Critical angle, c
The angle of incidence in the denser medium at which the angle of refraction is exactly 90 degrees, so the refracted ray runs along the boundary. It is given by sin c = 1 / n.
Total internal reflection
The complete reflection of light back into a denser medium when it meets a boundary with a less dense medium at an angle of incidence greater than the critical angle. It is the principle behind optical fibres.
Principal focus (focal point)
The point on the principal axis at which a beam of light parallel to the axis is brought to a focus by a converging lens, or from which it appears to diverge after a diverging lens.
Focal length
The distance from the centre of a lens to its principal focus. A shorter focal length means a more powerful lens that bends light more strongly.
Real image
An image formed where rays of light actually meet after passing through a lens. It is inverted and can be projected onto a screen.
Virtual image
An image formed where rays of light only appear to come from, because the diverging rays are extrapolated backwards. It cannot be projected onto a screen.

Applied to the real world

Cambridge sets physics in unfamiliar contexts - a car braking, a power station, a hospital scanner, a satellite. Use these as models for how to apply the physics, then write your own.

In a bathroom

A plane mirror gives a virtual image that is the same size as your face and the same distance behind the mirror as you are in front of it. If you stand 0.6 m from the mirror, your image is 0.6 m behind it, so you and your image are 1.2 m apart. This is why you have to move twice as far as you expect to change the apparent distance in the mirror.

In telecommunications

A telephone call or an internet message is carried as pulses of light along an optical fibre. Light in the glass core strikes the core-cladding boundary at an angle greater than the critical angle, so it is totally internally reflected and stays in the core, bouncing along for many kilometres with very little loss. One fibre can carry far more information than a copper cable of the same thickness.

In a camera

A camera uses a converging lens to form a real, inverted image on a sensor or film. The object is further from the lens than the focal length, so the rays actually cross and the image can be captured. Moving the lens further from the sensor focuses on closer objects, because a nearer object forms its image further from the lens.

At the optician

Spectacles correct the two common focusing faults of the eye. Short-sightedness is corrected with a diverging lens, which spreads the rays so that the eye focuses them on the retina instead of in front of it. Long-sightedness is corrected with a converging lens, which brings the rays together sooner so the image falls on the retina instead of behind it.

On the road

A rear-view mirror is often a diverging mirror rather than a flat one. A diverging surface spreads the reflected rays, so the driver sees a wider field of view, and the image is upright but diminished, which is why objects look further away than they really are.

In a rainbow

A rainbow is a natural spectrum. Sunlight enters a raindrop and is refracted, reflects off the inside of the back of the drop, and is refracted again as it leaves. Because violet is refracted more than red, the colours spread out into the arc you see, with red on the outside and violet on the inside.

Flashcards

Click a card to flip it. Mark honestly — the tracker uses this.

Q1State the law of reflection.
The angle of incidence is equal to the angle of reflection.
Q2What is the normal?
The line drawn perpendicular to the surface at the point where the ray meets it. All angles in optics are measured from it.
Q3Give the characteristics of an image formed by a plane mirror.
It is the same size as the object, as far behind the mirror as the object is in front, upright, virtual and laterally inverted.
Q4What is refraction?
The change in direction of light as it crosses the boundary between two transparent materials, caused by a change in its speed.
Q5In which direction does light bend when it enters a denser medium?
It slows down and bends towards the normal. On leaving the denser medium it speeds up and bends away from the normal.
Q6Define the refractive index of a material.
n = speed of light in a vacuum / speed of light in the material. It has no unit, because it is a ratio of two speeds.
Q7Write the equation linking refractive index to the angles of incidence and refraction.
n = sin i / sin r, where i is in air or a vacuum and r is in the material.
Q8What is the critical angle?
The angle of incidence in the denser medium for which the angle of refraction is exactly 90 degrees.
Q9State the two conditions needed for total internal reflection.
Light must travel from a denser to a less dense medium, and the angle of incidence must be greater than the critical angle.
Q10Write the equation linking the critical angle to the refractive index.
sin c = 1 / n, which can also be written as n = 1 / sin c.
Q11What does a converging lens do to a beam of light parallel to its principal axis?
It brings the rays together at the principal focus, a real focus on the far side of the lens.
Q12What is the focal length of a lens?
The distance from the centre of the lens to its principal focus.
Q13How do you tell a real image from a virtual image?
A real image is formed where rays actually meet and can be projected onto a screen. A virtual image is where rays only appear to come from, and it cannot be projected.
Q14Why is white light split into a spectrum by a prism?
Each colour has a slightly different refractive index in glass, so each colour is refracted by a different amount. Violet is refracted most and red least.
0 of 14 marked as known

Exam-style questions

9 questions, 28 marks. Write your answer, then reveal the mark scheme and tick each point you actually made. Answering honestly here is what makes the rest of the site useful.

StateAO11 mark
State the relationship between the angle of incidence and the angle of reflection for a ray of light reflected from a plane mirror.

Mark scheme — tick each point you actually made

Examiner tip: Both angles are measured from the normal, not from the surface of the mirror.
StateAO12 marks
A student looks at her face in a plane mirror. State two characteristics of the image that she sees.

Mark scheme — tick each point you actually made

Any 2 of these score full marks. The examiner only needs 2 distinct points - pick the ones you actually made.
Examiner tip: Any two of the listed characteristics score. Do not write that the image is real or smaller, because both are wrong for a plane mirror.
DescribeAO23 marks
Describe how you would use a ray box and a semicircular glass block to find the critical angle of the glass.

Mark scheme — tick each point you actually made

Examiner tip: Say that the angle is measured from the normal and that the critical angle is the value at which the refracted ray runs along the surface.
ExplainAO23 marks
A swimming pool full of clear water looks shallower than it really is when you look down into it from the side. Explain why.

Mark scheme — tick each point you actually made

Examiner tip: Name the two media and say which way the light bends. The mark is for linking the refraction to the apparent position of the bottom.
CompareAO24 marks
Compare a real image with a virtual image formed by a converging lens. In your answer, state how each image is formed, whether each can be projected onto a screen, and how each is oriented.

Mark scheme — tick each point you actually made

Examiner tip: Use the words inverted and upright as well as real and virtual. The comparison needs both images described, not just one.
ExplainAO24 marks
Explain how light travels along an optical fibre. Use the terms core, critical angle and total internal reflection in your answer.

Mark scheme — tick each point you actually made

Examiner tip: State both conditions for total internal reflection. The cladding has a lower refractive index than the core, which is what makes the reflection possible.
ExplainAO26 marks
A narrow beam of white light is passed through a triangular glass prism and a spectrum is seen on a screen. Explain why the white light is split into a spectrum, and state the colours of the spectrum in order of increasing wavelength.

Mark scheme — tick each point you actually made

Examiner tip: Link the amount of refraction to the frequency of each colour, and give the seven colours in the correct order. Reversing red and violet is a very common error.
CalculateAO23 marks
A ray of light passes from air into a glass block. The angle of incidence is 40.0 degrees and the angle of refraction is 25.4 degrees. Calculate the refractive index of the glass. Give your answer to 2 significant figures.

Mark scheme — tick each point you actually made

Examiner tip: Write the equation, then substitute the two sine values, then give the answer. Do not attach a unit to a refractive index.
CalculateAO22 marks
Light travels through a glass of refractive index 1.50. Calculate the critical angle for the boundary between this glass and air.

Mark scheme — tick each point you actually made

Examiner tip: The critical angle is the angle of incidence in the glass, so the answer is in degrees. Rearrange n = 1 / sin c before you substitute.

Exam technique for this topic

  • Always measure angles of incidence, reflection and refraction from the normal, never from the surface. Measuring from the surface is the single most common mistake in this topic.
  • In a refractive index calculation, check which way the light is travelling. Use n = sin i / sin r only with i in air or a vacuum and r in the material, and remember that n has no unit.
  • For total internal reflection, both conditions must be stated: the light must go from a denser to a less dense medium, and the angle of incidence must be greater than the critical angle.
  • When you describe an image, use the three pairs of words the syllabus asks for: enlarged, same size or diminished; upright or inverted; real or virtual. Say also whether it can be projected onto a screen.
  • In a ray diagram, draw an arrow on every ray to show the direction of travel, and mark the principal axis and the principal focus. A diagram without arrows loses marks even when the geometry is correct.
  • For dispersion, quote the colours in the correct order and link the amount of refraction to frequency: violet has the highest frequency and is refracted most, and red has the lowest frequency and is refracted least.

Why students lose marks here

A student wroteA student wrote: 'The angle of incidence is measured from the surface of the mirror.'
Why it loses marksAngles in optics are always measured from the normal, the line perpendicular to the surface. Measuring from the surface gives an angle that is 90 degrees out, so every later calculation is wrong.
The answer that scoresThe angle of incidence is the angle between the incident ray and the normal. The normal is drawn perpendicular to the surface at the point where the ray strikes it. The angle of reflection is measured in the same way, from the normal, and the two angles are equal.
Ray boxBeam of lightBends towards the normalGlass blockScreenThe dashed line is the normal, drawn at right angles to the glass surface where the beam meetsit. The beam bends towards the normal as it enters the glass, because light travels more slowlyin glass than in air.
A ray box directing a narrow beam at a mirror, with the normal drawn perpendicular to the mirror surface and both angles measured from it.
A student wroteA student wrote: 'The image in a plane mirror is on the surface of the mirror and it is real.'
Why it loses marksThe image is not on the surface and it is not real. It is formed behind the mirror, at the same distance behind as the object is in front, and because no light actually reaches that point it is virtual.
The answer that scoresA plane mirror forms a virtual image. The reflected rays diverge, so they only appear to come from a point behind the mirror, and a screen placed there would show nothing. The image is the same size as the object, upright, laterally inverted, and as far behind the mirror as the object is in front of it.
A student wroteA student wrote: 'When light passes from air into glass it speeds up and bends away from the normal.'
Why it loses marksThis is the wrong way round. Light travels more slowly in glass than in air, and a ray that slows down on entering a denser medium bends towards the normal, not away from it.
The answer that scoresGlass is denser than air, so light travels more slowly in it. When the ray enters the glass it slows down and bends towards the normal. When it leaves the glass on the other side it speeds up again and bends away from the normal, so the emergent ray is parallel to the incident ray but displaced sideways.
A student wroteA student wrote: 'Total internal reflection happens whenever light hits a boundary between glass and air.'
Why it loses marksTwo conditions are needed, and neither is automatic. The light must be travelling from the denser medium to the less dense medium, and the angle of incidence must be greater than the critical angle. If either condition fails, the light refracts out instead.
The answer that scoresTotal internal reflection happens only when light travels from a denser to a less dense medium and the angle of incidence is greater than the critical angle. At angles below the critical angle most of the light is refracted out of the glass. This is why light is trapped in the core of an optical fibre and can carry a signal for many kilometres.
An optical fibre carrying pulses of light: the light strikes the core-cladding boundary at an angle greater than the critical angle and is totally internally reflected back into the core, so it stays trapped inside the fibre.

Where this fits in IGCSE Physics

This page is one topic of Cambridge IGCSE Physics 0625. IGCSE Physics is the course home: every area and every topic in Cambridge's own order, the papers you sit and what each one tests, and the exam-practice tools. The full topic list, with each topic linked to its revision page, is on the IGCSE Physics syllabus page.